compute the location of a point in the original image
I have a rotated and scaled image and a point in it but I want to map the location of this point in the original image with respect to the rotated and scaled image. How can I do it in OpenCV?
opencv affinetransform
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
add a comment |
I have a rotated and scaled image and a point in it but I want to map the location of this point in the original image with respect to the rotated and scaled image. How can I do it in OpenCV?
opencv affinetransform
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
1
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49
add a comment |
I have a rotated and scaled image and a point in it but I want to map the location of this point in the original image with respect to the rotated and scaled image. How can I do it in OpenCV?
opencv affinetransform
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
I have a rotated and scaled image and a point in it but I want to map the location of this point in the original image with respect to the rotated and scaled image. How can I do it in OpenCV?
opencv affinetransform
opencv affinetransform
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
asked Nov 24 '18 at 17:10
BarracudaBarracuda
1,62611535
1,62611535
1
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49
add a comment |
1
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49
1
1
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53460523%2fcompute-the-location-of-a-point-in-the-original-image%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53460523%2fcompute-the-location-of-a-point-in-the-original-image%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
if the rotation and scaling is described as a homography transformstion you can easily invert it by matrix inversion
– Micka
Nov 24 '18 at 21:49