Printing Nested Values from Firebase Query with Swift
1
I currently have a firebase database structured like so:
Playlist
Playlist1
0: "song1"
1: "song2"
Playlist2
0: "song1"
1: "song2"
What I would like to do print the name of each playlist name onto a TableViewController. I understand how the TableView works, but what I'm hung up on is how to make the call to the database. I have hardcoded for now as
let ref = Database.database().reference().child("Playlists/Playlist1")
ref.observe(.value, with: {
snapshot in
print(snapshot.key)
This obviously isn't scalable, is there anyway I can iterate over all the data and just get the playlist names?
swift firebase firebase-realtime-database
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
add a comment |
1
I currently have a firebase database structured like so:
Playlist
Playlist1
0: "song1"
1: "song2"
Playlist2
0: "song1"
1: "song2"
What I would like to do print the name of each playlist name onto a TableViewController. I understand how the TableView works, but what I'm hung up on is how to make the call to the database. I have hardcoded for now as
let ref = Database.database().reference().child("Playlists/Playlist1")
ref.observe(.value, with: {
snapshot in
print(snapshot.key)
This obviously isn't scalable, is there anyway I can iterate over all the data and just get the playlist names?
swift firebase firebase-realtime-database
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
add a comment |
1
1
1
I currently have a firebase database structured like so:
Playlist
Playlist1
0: "song1"
1: "song2"
Playlist2
0: "song1"
1: "song2"
What I would like to do print the name of each playlist name onto a TableViewController. I understand how the TableView works, but what I'm hung up on is how to make the call to the database. I have hardcoded for now as
let ref = Database.database().reference().child("Playlists/Playlist1")
ref.observe(.value, with: {
snapshot in
print(snapshot.key)
This obviously isn't scalable, is there anyway I can iterate over all the data and just get the playlist names?
swift firebase firebase-realtime-database
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
I currently have a firebase database structured like so:
Playlist
Playlist1
0: "song1"
1: "song2"
Playlist2
0: "song1"
1: "song2"
What I would like to do print the name of each playlist name onto a TableViewController. I understand how the TableView works, but what I'm hung up on is how to make the call to the database. I have hardcoded for now as
let ref = Database.database().reference().child("Playlists/Playlist1")
ref.observe(.value, with: {
snapshot in
print(snapshot.key)
This obviously isn't scalable, is there anyway I can iterate over all the data and just get the playlist names?
swift firebase firebase-realtime-database
swift firebase firebase-realtime-database
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
edited Nov 26 '18 at 2:53
Frank van Puffelen
242k29387414
242k29387414
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
asked Nov 26 '18 at 0:13
javarookiejavarookie
185
185
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
If this is your structure:
Database.database().reference().child("Playlists").observe(.value, with: { (_snapshot) in
if let playLists = _snapshot.value as? [String : Any] {
var names = [String]()
for playlist in playLists {
names.append(playlist.key)
}
// return names in a completion
}
}, withCancel: nil)
outputs:
I would also recommend to NOT use the name of the playlist as a key, you should use an ID like childByAutoID, it's a built in firebase method. Then, have the name as attribute.
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
|
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
If this is your structure:
Database.database().reference().child("Playlists").observe(.value, with: { (_snapshot) in
if let playLists = _snapshot.value as? [String : Any] {
var names = [String]()
for playlist in playLists {
names.append(playlist.key)
}
// return names in a completion
}
}, withCancel: nil)
outputs:
I would also recommend to NOT use the name of the playlist as a key, you should use an ID like childByAutoID, it's a built in firebase method. Then, have the name as attribute.
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
|
show 1 more comment
1
If this is your structure:
Database.database().reference().child("Playlists").observe(.value, with: { (_snapshot) in
if let playLists = _snapshot.value as? [String : Any] {
var names = [String]()
for playlist in playLists {
names.append(playlist.key)
}
// return names in a completion
}
}, withCancel: nil)
outputs:
I would also recommend to NOT use the name of the playlist as a key, you should use an ID like childByAutoID, it's a built in firebase method. Then, have the name as attribute.
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
|
show 1 more comment
1
1
1
If this is your structure:
Database.database().reference().child("Playlists").observe(.value, with: { (_snapshot) in
if let playLists = _snapshot.value as? [String : Any] {
var names = [String]()
for playlist in playLists {
names.append(playlist.key)
}
// return names in a completion
}
}, withCancel: nil)
outputs:
I would also recommend to NOT use the name of the playlist as a key, you should use an ID like childByAutoID, it's a built in firebase method. Then, have the name as attribute.
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
If this is your structure:
Database.database().reference().child("Playlists").observe(.value, with: { (_snapshot) in
if let playLists = _snapshot.value as? [String : Any] {
var names = [String]()
for playlist in playLists {
names.append(playlist.key)
}
// return names in a completion
}
}, withCancel: nil)
outputs:
I would also recommend to NOT use the name of the playlist as a key, you should use an ID like childByAutoID, it's a built in firebase method. Then, have the name as attribute.
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
edited Nov 26 '18 at 0:49
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
answered Nov 26 '18 at 0:19
Gustavo VollbrechtGustavo Vollbrecht
1,6581922
1,6581922
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
|
show 1 more comment
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
I added a print statement inside the for loop and there was no data outputted. To your point, do you think it would be best to structure the data like Playlists: 0: 0: "song1" 1: "song2" name: "Playlist1"
– javarookie
Nov 26 '18 at 0:37
1
1
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
check new edit, I think your parent node is called 'Playlist' instead of 'Playlists'
– Gustavo Vollbrecht
Nov 26 '18 at 0:38
1
1
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
not sequential, use childByAutoID when inserting new values.
– Gustavo Vollbrecht
Nov 26 '18 at 0:41
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
okay, changed the parent node to 'Playlists' (kept the original structure), still no data being outputted
– javarookie
Nov 26 '18 at 0:46
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
Thanks for the help, works great now! I think I made it hard on myself with how I structured the database initially, so I'll follow your advice
– javarookie
Nov 26 '18 at 1:01
|
show 1 more comment
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