A simple Variation on the Imaginary Unit i
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I think a more appropriate tag would have been 'quasicomplex numbers' rather than 'hypercomplex numbers'.
I'm normally perfectly comfortable with the correspondence between hyperbolic functions & circular functions - the way one is just the other with imaginary argument, or an imaginary component in the argument ... & all that.
But I ran into a bit of a problem recently with this correspondence seeming to break down. I was looking at a post recently in which the matter of $$sum_{k=1}^noperatorname{atn}(x_k)$$$$=$$$$operatorname{atn}left(frac{sum _{kinℕ_0,k<{nover2}}(-1)^koperatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}(-1)^koperatorname{het}_{n,2k}(underline{x})}right)$$with $operatorname{het}_{n,k}$ denoting the symmetric polynomial in $n$ variables of degree $k$ consisting of the sum of strictly heterogeneous products of the variables (I presume this is not standard notation; but I think it will do here). Another contibutor exposited that this is a consequence of the fact that $operatorname{atn}x$ is the argument of $1+ix$ together with the fact that the argument of the product of a set of complex numbers is the sum of the arguments: and indeed if you expand$$prod_{k=1}^n(1+ix_k)$$you get those symmetric polynomials, and the tangent of the argument is indeed the function of the $x_j$ constituting the content (it's getting awkward through 'argument' having two different meanings here!) of $operatorname{atn}$ on the RHS of the relation shown above.
But you also have$$sum_{k=1}^noperatorname{atnh}(x_k)$$$$=$$$$operatorname{atnh}left(frac{sum _{kinℕ_0,k<{nover2}}operatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}operatorname{het}_{n,2k}(underline{x})}right) ,$$ and yet there is no corresponding logic for this ... unless ... perhaps you introduce an operator (let's call it $h$ for now) that has the properties $h≠1$, $|h|=1$, & $h^2=1$. The entity $h$ is not 1 ... and yet $h^2$ does (coz it does right!!?) = 1 ... $h$ is just eheieh asher eheieh - it just is what it is. (I've found that this point can be such a stumblingblock for people who are learning these things - the idea of an entity just being what it is ... & also how my own mind kept reverting to wanting some explicit statement in terms of $pi$, or decimals, or whatever, of what $i$ is ... & how one day it just 'clicked' that it's not occasioned - and indeed there is none!)
And then you could have precisely analogous logic for the formula for the sum of plural $operatorname{atanh}$, with the 'argument' of$$prod_{k=1}^n(1+hx_k)$$ analogous to the argument of the circular complex product above.
The question is, is there any occurence of such ... hyperbolically complex numbers in mathematics atall; and has the idea ever been developed atall? I think if you were to put any kind of interpretation on the 'meaning' of this $h$, it would be that whereas $i$ is a rotation, $h$ is a reflection. And we are of course free to define any entity we wish ... the chief question then is "is the entity we have defined just a total cul-de-sac, or is there some mileage in it?" Maybe there is no mileage in this $h$ beyond it's being an expedient for buttressing the analogy between circular & hyperbolic functions.
Another entity we could define, for instance, and which in effect kind of is defined in the differential calculus would be (let's call it) $epsilon$, which has the rather mutually-strange properties $epsilon≠0$, $|epsilon|=0$, & $epsilon^2=0$.
hyperbolic-functions hypercomplex-numbers
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|
show 2 more comments
$begingroup$
I think a more appropriate tag would have been 'quasicomplex numbers' rather than 'hypercomplex numbers'.
I'm normally perfectly comfortable with the correspondence between hyperbolic functions & circular functions - the way one is just the other with imaginary argument, or an imaginary component in the argument ... & all that.
But I ran into a bit of a problem recently with this correspondence seeming to break down. I was looking at a post recently in which the matter of $$sum_{k=1}^noperatorname{atn}(x_k)$$$$=$$$$operatorname{atn}left(frac{sum _{kinℕ_0,k<{nover2}}(-1)^koperatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}(-1)^koperatorname{het}_{n,2k}(underline{x})}right)$$with $operatorname{het}_{n,k}$ denoting the symmetric polynomial in $n$ variables of degree $k$ consisting of the sum of strictly heterogeneous products of the variables (I presume this is not standard notation; but I think it will do here). Another contibutor exposited that this is a consequence of the fact that $operatorname{atn}x$ is the argument of $1+ix$ together with the fact that the argument of the product of a set of complex numbers is the sum of the arguments: and indeed if you expand$$prod_{k=1}^n(1+ix_k)$$you get those symmetric polynomials, and the tangent of the argument is indeed the function of the $x_j$ constituting the content (it's getting awkward through 'argument' having two different meanings here!) of $operatorname{atn}$ on the RHS of the relation shown above.
But you also have$$sum_{k=1}^noperatorname{atnh}(x_k)$$$$=$$$$operatorname{atnh}left(frac{sum _{kinℕ_0,k<{nover2}}operatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}operatorname{het}_{n,2k}(underline{x})}right) ,$$ and yet there is no corresponding logic for this ... unless ... perhaps you introduce an operator (let's call it $h$ for now) that has the properties $h≠1$, $|h|=1$, & $h^2=1$. The entity $h$ is not 1 ... and yet $h^2$ does (coz it does right!!?) = 1 ... $h$ is just eheieh asher eheieh - it just is what it is. (I've found that this point can be such a stumblingblock for people who are learning these things - the idea of an entity just being what it is ... & also how my own mind kept reverting to wanting some explicit statement in terms of $pi$, or decimals, or whatever, of what $i$ is ... & how one day it just 'clicked' that it's not occasioned - and indeed there is none!)
And then you could have precisely analogous logic for the formula for the sum of plural $operatorname{atanh}$, with the 'argument' of$$prod_{k=1}^n(1+hx_k)$$ analogous to the argument of the circular complex product above.
The question is, is there any occurence of such ... hyperbolically complex numbers in mathematics atall; and has the idea ever been developed atall? I think if you were to put any kind of interpretation on the 'meaning' of this $h$, it would be that whereas $i$ is a rotation, $h$ is a reflection. And we are of course free to define any entity we wish ... the chief question then is "is the entity we have defined just a total cul-de-sac, or is there some mileage in it?" Maybe there is no mileage in this $h$ beyond it's being an expedient for buttressing the analogy between circular & hyperbolic functions.
Another entity we could define, for instance, and which in effect kind of is defined in the differential calculus would be (let's call it) $epsilon$, which has the rather mutually-strange properties $epsilon≠0$, $|epsilon|=0$, & $epsilon^2=0$.
hyperbolic-functions hypercomplex-numbers
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2
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You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
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– K B Dave
Dec 7 '18 at 20:56
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@K B Dave -- Right! Lets have a look at this then.
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– AmbretteOrrisey
Dec 7 '18 at 21:03
1
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
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– J.G.
Dec 7 '18 at 21:09
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
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– AmbretteOrrisey
Dec 7 '18 at 21:12
1
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@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03
|
show 2 more comments
$begingroup$
I think a more appropriate tag would have been 'quasicomplex numbers' rather than 'hypercomplex numbers'.
I'm normally perfectly comfortable with the correspondence between hyperbolic functions & circular functions - the way one is just the other with imaginary argument, or an imaginary component in the argument ... & all that.
But I ran into a bit of a problem recently with this correspondence seeming to break down. I was looking at a post recently in which the matter of $$sum_{k=1}^noperatorname{atn}(x_k)$$$$=$$$$operatorname{atn}left(frac{sum _{kinℕ_0,k<{nover2}}(-1)^koperatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}(-1)^koperatorname{het}_{n,2k}(underline{x})}right)$$with $operatorname{het}_{n,k}$ denoting the symmetric polynomial in $n$ variables of degree $k$ consisting of the sum of strictly heterogeneous products of the variables (I presume this is not standard notation; but I think it will do here). Another contibutor exposited that this is a consequence of the fact that $operatorname{atn}x$ is the argument of $1+ix$ together with the fact that the argument of the product of a set of complex numbers is the sum of the arguments: and indeed if you expand$$prod_{k=1}^n(1+ix_k)$$you get those symmetric polynomials, and the tangent of the argument is indeed the function of the $x_j$ constituting the content (it's getting awkward through 'argument' having two different meanings here!) of $operatorname{atn}$ on the RHS of the relation shown above.
But you also have$$sum_{k=1}^noperatorname{atnh}(x_k)$$$$=$$$$operatorname{atnh}left(frac{sum _{kinℕ_0,k<{nover2}}operatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}operatorname{het}_{n,2k}(underline{x})}right) ,$$ and yet there is no corresponding logic for this ... unless ... perhaps you introduce an operator (let's call it $h$ for now) that has the properties $h≠1$, $|h|=1$, & $h^2=1$. The entity $h$ is not 1 ... and yet $h^2$ does (coz it does right!!?) = 1 ... $h$ is just eheieh asher eheieh - it just is what it is. (I've found that this point can be such a stumblingblock for people who are learning these things - the idea of an entity just being what it is ... & also how my own mind kept reverting to wanting some explicit statement in terms of $pi$, or decimals, or whatever, of what $i$ is ... & how one day it just 'clicked' that it's not occasioned - and indeed there is none!)
And then you could have precisely analogous logic for the formula for the sum of plural $operatorname{atanh}$, with the 'argument' of$$prod_{k=1}^n(1+hx_k)$$ analogous to the argument of the circular complex product above.
The question is, is there any occurence of such ... hyperbolically complex numbers in mathematics atall; and has the idea ever been developed atall? I think if you were to put any kind of interpretation on the 'meaning' of this $h$, it would be that whereas $i$ is a rotation, $h$ is a reflection. And we are of course free to define any entity we wish ... the chief question then is "is the entity we have defined just a total cul-de-sac, or is there some mileage in it?" Maybe there is no mileage in this $h$ beyond it's being an expedient for buttressing the analogy between circular & hyperbolic functions.
Another entity we could define, for instance, and which in effect kind of is defined in the differential calculus would be (let's call it) $epsilon$, which has the rather mutually-strange properties $epsilon≠0$, $|epsilon|=0$, & $epsilon^2=0$.
hyperbolic-functions hypercomplex-numbers
$endgroup$
I think a more appropriate tag would have been 'quasicomplex numbers' rather than 'hypercomplex numbers'.
I'm normally perfectly comfortable with the correspondence between hyperbolic functions & circular functions - the way one is just the other with imaginary argument, or an imaginary component in the argument ... & all that.
But I ran into a bit of a problem recently with this correspondence seeming to break down. I was looking at a post recently in which the matter of $$sum_{k=1}^noperatorname{atn}(x_k)$$$$=$$$$operatorname{atn}left(frac{sum _{kinℕ_0,k<{nover2}}(-1)^koperatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}(-1)^koperatorname{het}_{n,2k}(underline{x})}right)$$with $operatorname{het}_{n,k}$ denoting the symmetric polynomial in $n$ variables of degree $k$ consisting of the sum of strictly heterogeneous products of the variables (I presume this is not standard notation; but I think it will do here). Another contibutor exposited that this is a consequence of the fact that $operatorname{atn}x$ is the argument of $1+ix$ together with the fact that the argument of the product of a set of complex numbers is the sum of the arguments: and indeed if you expand$$prod_{k=1}^n(1+ix_k)$$you get those symmetric polynomials, and the tangent of the argument is indeed the function of the $x_j$ constituting the content (it's getting awkward through 'argument' having two different meanings here!) of $operatorname{atn}$ on the RHS of the relation shown above.
But you also have$$sum_{k=1}^noperatorname{atnh}(x_k)$$$$=$$$$operatorname{atnh}left(frac{sum _{kinℕ_0,k<{nover2}}operatorname{het}_{n,2k+1}(underline{x})}{sum_{kinℕ_0,kleq{nover2}}operatorname{het}_{n,2k}(underline{x})}right) ,$$ and yet there is no corresponding logic for this ... unless ... perhaps you introduce an operator (let's call it $h$ for now) that has the properties $h≠1$, $|h|=1$, & $h^2=1$. The entity $h$ is not 1 ... and yet $h^2$ does (coz it does right!!?) = 1 ... $h$ is just eheieh asher eheieh - it just is what it is. (I've found that this point can be such a stumblingblock for people who are learning these things - the idea of an entity just being what it is ... & also how my own mind kept reverting to wanting some explicit statement in terms of $pi$, or decimals, or whatever, of what $i$ is ... & how one day it just 'clicked' that it's not occasioned - and indeed there is none!)
And then you could have precisely analogous logic for the formula for the sum of plural $operatorname{atanh}$, with the 'argument' of$$prod_{k=1}^n(1+hx_k)$$ analogous to the argument of the circular complex product above.
The question is, is there any occurence of such ... hyperbolically complex numbers in mathematics atall; and has the idea ever been developed atall? I think if you were to put any kind of interpretation on the 'meaning' of this $h$, it would be that whereas $i$ is a rotation, $h$ is a reflection. And we are of course free to define any entity we wish ... the chief question then is "is the entity we have defined just a total cul-de-sac, or is there some mileage in it?" Maybe there is no mileage in this $h$ beyond it's being an expedient for buttressing the analogy between circular & hyperbolic functions.
Another entity we could define, for instance, and which in effect kind of is defined in the differential calculus would be (let's call it) $epsilon$, which has the rather mutually-strange properties $epsilon≠0$, $|epsilon|=0$, & $epsilon^2=0$.
hyperbolic-functions hypercomplex-numbers
hyperbolic-functions hypercomplex-numbers
edited Dec 7 '18 at 21:01
AmbretteOrrisey
asked Dec 7 '18 at 17:56
AmbretteOrriseyAmbretteOrrisey
54210
54210
2
$begingroup$
You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
$endgroup$
– K B Dave
Dec 7 '18 at 20:56
$begingroup$
@K B Dave -- Right! Lets have a look at this then.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:03
1
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
$endgroup$
– J.G.
Dec 7 '18 at 21:09
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:12
1
$begingroup$
@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03
|
show 2 more comments
2
$begingroup$
You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
$endgroup$
– K B Dave
Dec 7 '18 at 20:56
$begingroup$
@K B Dave -- Right! Lets have a look at this then.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:03
1
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
$endgroup$
– J.G.
Dec 7 '18 at 21:09
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:12
1
$begingroup$
@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03
2
2
$begingroup$
You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
$endgroup$
– K B Dave
Dec 7 '18 at 20:56
$begingroup$
You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
$endgroup$
– K B Dave
Dec 7 '18 at 20:56
$begingroup$
@K B Dave -- Right! Lets have a look at this then.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:03
$begingroup$
@K B Dave -- Right! Lets have a look at this then.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:03
1
1
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
$endgroup$
– J.G.
Dec 7 '18 at 21:09
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
$endgroup$
– J.G.
Dec 7 '18 at 21:09
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:12
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:12
1
1
$begingroup$
@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03
$begingroup$
@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03
|
show 2 more comments
1 Answer
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As in the comments, these things exist and are called the split-complex numbers $mathbb{R}[j]/(j^2 - 1)$. They are just another example of a ring, albeit a funny example because they aren't an integral domain and so some familiar properties of rings like the integers $mathbb{Z}$, the rationals $mathbb{Q}$, the real numbers $mathbb{R}$, and the complex numbers $mathbb{C}$ don't apply: for example, as you've observed, in the split complex numbers the equation $x^2 = 1$ has four solutions $1, -1, j, -j$, more than its degree.
In the same way as the complex numbers can be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bi leftrightarrow left[ begin{array}{cc} a & - b \ b & a end{array} right]$$
the split-complex numbers can also be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bj leftrightarrow left[ begin{array}{cc} a & b \ b & a end{array} right].$$
What this reveals is that, just as you wrote, in the same way that $i$ represents a rotation, $j$ represents a reflection.
Abstractly the split-complex numbers are isomorphic as a ring to the product $mathbb{R} times mathbb{R}$ of two copies of the real numbers, via the correspondence
$$a + bj leftrightarrow (a + b, a - b)$$
and so they aren't genuinely "new" in the same way that the complex numbers are. But again, as you say, they are a cute way of expressing the analogy between hyperbolic and trigonometric functions. For example there is a hyperbolic Euler's formula
$$exp(j t) = cosh t + j sinh t.$$
The dual numbers $mathbb{R}[epsilon]/(epsilon^2)$ as you mention, and as mentioned in the comments, are another example of a ring, and find some use. There are lots more rings than this, though. If you really want to have some fun you can learn about the quaternions next.
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$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
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– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
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– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
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$begingroup$
As in the comments, these things exist and are called the split-complex numbers $mathbb{R}[j]/(j^2 - 1)$. They are just another example of a ring, albeit a funny example because they aren't an integral domain and so some familiar properties of rings like the integers $mathbb{Z}$, the rationals $mathbb{Q}$, the real numbers $mathbb{R}$, and the complex numbers $mathbb{C}$ don't apply: for example, as you've observed, in the split complex numbers the equation $x^2 = 1$ has four solutions $1, -1, j, -j$, more than its degree.
In the same way as the complex numbers can be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bi leftrightarrow left[ begin{array}{cc} a & - b \ b & a end{array} right]$$
the split-complex numbers can also be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bj leftrightarrow left[ begin{array}{cc} a & b \ b & a end{array} right].$$
What this reveals is that, just as you wrote, in the same way that $i$ represents a rotation, $j$ represents a reflection.
Abstractly the split-complex numbers are isomorphic as a ring to the product $mathbb{R} times mathbb{R}$ of two copies of the real numbers, via the correspondence
$$a + bj leftrightarrow (a + b, a - b)$$
and so they aren't genuinely "new" in the same way that the complex numbers are. But again, as you say, they are a cute way of expressing the analogy between hyperbolic and trigonometric functions. For example there is a hyperbolic Euler's formula
$$exp(j t) = cosh t + j sinh t.$$
The dual numbers $mathbb{R}[epsilon]/(epsilon^2)$ as you mention, and as mentioned in the comments, are another example of a ring, and find some use. There are lots more rings than this, though. If you really want to have some fun you can learn about the quaternions next.
$endgroup$
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
add a comment |
$begingroup$
As in the comments, these things exist and are called the split-complex numbers $mathbb{R}[j]/(j^2 - 1)$. They are just another example of a ring, albeit a funny example because they aren't an integral domain and so some familiar properties of rings like the integers $mathbb{Z}$, the rationals $mathbb{Q}$, the real numbers $mathbb{R}$, and the complex numbers $mathbb{C}$ don't apply: for example, as you've observed, in the split complex numbers the equation $x^2 = 1$ has four solutions $1, -1, j, -j$, more than its degree.
In the same way as the complex numbers can be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bi leftrightarrow left[ begin{array}{cc} a & - b \ b & a end{array} right]$$
the split-complex numbers can also be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bj leftrightarrow left[ begin{array}{cc} a & b \ b & a end{array} right].$$
What this reveals is that, just as you wrote, in the same way that $i$ represents a rotation, $j$ represents a reflection.
Abstractly the split-complex numbers are isomorphic as a ring to the product $mathbb{R} times mathbb{R}$ of two copies of the real numbers, via the correspondence
$$a + bj leftrightarrow (a + b, a - b)$$
and so they aren't genuinely "new" in the same way that the complex numbers are. But again, as you say, they are a cute way of expressing the analogy between hyperbolic and trigonometric functions. For example there is a hyperbolic Euler's formula
$$exp(j t) = cosh t + j sinh t.$$
The dual numbers $mathbb{R}[epsilon]/(epsilon^2)$ as you mention, and as mentioned in the comments, are another example of a ring, and find some use. There are lots more rings than this, though. If you really want to have some fun you can learn about the quaternions next.
$endgroup$
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
add a comment |
$begingroup$
As in the comments, these things exist and are called the split-complex numbers $mathbb{R}[j]/(j^2 - 1)$. They are just another example of a ring, albeit a funny example because they aren't an integral domain and so some familiar properties of rings like the integers $mathbb{Z}$, the rationals $mathbb{Q}$, the real numbers $mathbb{R}$, and the complex numbers $mathbb{C}$ don't apply: for example, as you've observed, in the split complex numbers the equation $x^2 = 1$ has four solutions $1, -1, j, -j$, more than its degree.
In the same way as the complex numbers can be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bi leftrightarrow left[ begin{array}{cc} a & - b \ b & a end{array} right]$$
the split-complex numbers can also be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bj leftrightarrow left[ begin{array}{cc} a & b \ b & a end{array} right].$$
What this reveals is that, just as you wrote, in the same way that $i$ represents a rotation, $j$ represents a reflection.
Abstractly the split-complex numbers are isomorphic as a ring to the product $mathbb{R} times mathbb{R}$ of two copies of the real numbers, via the correspondence
$$a + bj leftrightarrow (a + b, a - b)$$
and so they aren't genuinely "new" in the same way that the complex numbers are. But again, as you say, they are a cute way of expressing the analogy between hyperbolic and trigonometric functions. For example there is a hyperbolic Euler's formula
$$exp(j t) = cosh t + j sinh t.$$
The dual numbers $mathbb{R}[epsilon]/(epsilon^2)$ as you mention, and as mentioned in the comments, are another example of a ring, and find some use. There are lots more rings than this, though. If you really want to have some fun you can learn about the quaternions next.
$endgroup$
As in the comments, these things exist and are called the split-complex numbers $mathbb{R}[j]/(j^2 - 1)$. They are just another example of a ring, albeit a funny example because they aren't an integral domain and so some familiar properties of rings like the integers $mathbb{Z}$, the rationals $mathbb{Q}$, the real numbers $mathbb{R}$, and the complex numbers $mathbb{C}$ don't apply: for example, as you've observed, in the split complex numbers the equation $x^2 = 1$ has four solutions $1, -1, j, -j$, more than its degree.
In the same way as the complex numbers can be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bi leftrightarrow left[ begin{array}{cc} a & - b \ b & a end{array} right]$$
the split-complex numbers can also be thought of in terms of $2 times 2$ matrices via the correspondence
$$a + bj leftrightarrow left[ begin{array}{cc} a & b \ b & a end{array} right].$$
What this reveals is that, just as you wrote, in the same way that $i$ represents a rotation, $j$ represents a reflection.
Abstractly the split-complex numbers are isomorphic as a ring to the product $mathbb{R} times mathbb{R}$ of two copies of the real numbers, via the correspondence
$$a + bj leftrightarrow (a + b, a - b)$$
and so they aren't genuinely "new" in the same way that the complex numbers are. But again, as you say, they are a cute way of expressing the analogy between hyperbolic and trigonometric functions. For example there is a hyperbolic Euler's formula
$$exp(j t) = cosh t + j sinh t.$$
The dual numbers $mathbb{R}[epsilon]/(epsilon^2)$ as you mention, and as mentioned in the comments, are another example of a ring, and find some use. There are lots more rings than this, though. If you really want to have some fun you can learn about the quaternions next.
edited Dec 7 '18 at 21:54
answered Dec 7 '18 at 21:47
Qiaochu YuanQiaochu Yuan
278k32584920
278k32584920
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
add a comment |
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
A ring that isn't an integral domain! Well that's something in its own right - and equations having a number of solutions greater than the degree - that is weird! Abd it makes me wonder just how far this matter has been developed. ¶ And speeaking more generally, there does seem to be a certain duality between 'circular' space or hypobolic space, & hyperbolic space, (space of functions, thatis) we could say: there is also the perfect of a matrix - like determinant, but with no 'checkerboard of signs - much less well -known ... but I have seen aoplications of it here & there.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:58
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
@Ambrette: ring theory is extremely well-developed in many different directions. There are lots of different branches to it with emphasis on different kinds of rings depending on what you want to do with them. My first exposure to it was through number theory and rings like the Gaussian integers $mathbb{Z}[i]$, which can be used to prove lots of fun facts like that every prime congruent to $1 bmod 4$ is a sum of two squares (of integers).
$endgroup$
– Qiaochu Yuan
Dec 7 '18 at 22:03
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
It is, like surpassingly amazing, group theory, ring theory, field theory, & all that. In a sense it is the theory of relation per se - not the relations of any particular things ... but just ... relation, in-&-of itself. And it never ceases to baffle me that sheer relation gives-rise to so many particular patterns: the particular groups that can exist of a given order; and the particular anatomies of those groups in terms of their subgroups & conjugacy classes, & the various other kinds of internal organ that they have.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:11
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
$begingroup$
Not the perfect of a matrix - that that's like the determinant but without the 'checkerboard' of signs, but rather - the permanent!
$endgroup$
– AmbretteOrrisey
Dec 8 '18 at 1:53
add a comment |
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$begingroup$
You mean, has someone developed the the theory of functions of a split-complex number? People have done so since the mid-19th century: en.wikipedia.org/wiki/Split-complex_number#History
$endgroup$
– K B Dave
Dec 7 '18 at 20:56
$begingroup$
@K B Dave -- Right! Lets have a look at this then.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:03
1
$begingroup$
Your $h$ is often denoted $j$, but it can be $h$ too, and $epsilon$ is standard for what it is: en.wikipedia.org/wiki/Dual_number
$endgroup$
– J.G.
Dec 7 '18 at 21:09
$begingroup$
@K B Dave -- just had a scan of it ... it looks like what I'm after. And moreover, I've noticed that there's mention of it in connection with the rapidity of special relativity, which has particularly piqued my attention, as I remember many years ago trying to get to grips with that subject, & it occuring to me that these split numbers could be applied ... but abandoning it, telling myself I'd gotten snared by some flaky fantasy & that I was overtired. So I'm very much looking forward to searching this out properly. Thanks for that direction. It's pity that so much oldstuff neglected!
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 21:12
1
$begingroup$
@Qiaochu Yuan -- Hmmm ... but 'fallen away' still, I think, in that that's where it stays for the most part! It just doesn't seem to have any threads spun-out from it involved in other departnents!.
$endgroup$
– AmbretteOrrisey
Dec 7 '18 at 22:03