Ytukyg

I am using the com.sun.jersey.api.uri.UriBuilderImpl implementation of UriBuilder to encode a URL (version 1.19). The issue arises when the query parameter of my URL includes both curly brackets and a space.

Example:

UriBuilder uriBuilder = fromUri("www.something.com")

        .queryParam("q", "{some thing}");



return uriBuilder.build().toString();

This fails with:

javax.ws.rs.core.UriBuilderException: java.net.URISyntaxException: Illegal character in query at index 27: www.something.com?q=%7Bsome thing%7D

Which is interesting, as if I take the curly brackets away, I get the expected encoding: www.something.com?q=some+thing...

org.apache.http.client.utils.URIBuilder encodes that as I would expect, which is: www.something.com?q=%7Bsome+thing%7D

I've tried doing this:

...

.queryParam("q", UriComponent.encode(searchQuery, UriComponent.Type.QUERY_PARAM)).

.build();

But then the space character also gets encoded to www.something.com?q=%7Bsome%2Bthing%7D.

What do I have to do to get www.something.com?q=%7Bsome+thing%7D?

I'm using jersey-client v1.9.1 and your code run with no error.

Here is my maven dependency:

<!-- https://mvnrepository.com/artifact/com.sun.jersey/jersey-client -->

        <dependency>

            <groupId>com.sun.jersey</groupId>

            <artifactId>jersey-client</artifactId>

            <version>1.9.1</version>

        </dependency>

And the java code:

import java.net.URI;



import javax.ws.rs.core.UriBuilder;



public class Main {

    public static void main(String args) throws Exception {

        try {

            URI url = UriBuilder.fromUri("www.something.com")

                    .queryParam("q", "{some thing}")

                    .build();

            System.out.println(url);

        } catch (Exception e) {

            // TODO Auto-generated catch block

            e.printStackTrace();

        }

    }



}

The output: www.something.com?q=%7Bsome+thing%7D

UPDATE

The curly braces are the reason for failing with v1.19 (see the documentation)

Here is a working version for v1.19:

        URI url = UriBuilder.fromPath("www.something.com")

                .queryParam("q", "{value}")

                .build("{some thing}", "value");

        System.out.println(url);

You can try this:
You need two library
jersey-core-1.19.2 and javax.ws.rs and jersey-client-1.19.2

public class ClassTest {

    public static void main(String args) throws UnsupportedEncodingException {

        String queryString =  URLEncoder.encode("{some thing}", "UTF-8");

        System.out.println(queryString);

        URI uri = UriBuilder.fromUri("www.something.com")

                .queryParam("q", queryString)

                .build();

        String url = uri.toString().replace("%2B", "+");

        System.out.println(url);

    }

}