How to create a table and choose any column in database?
Write a function named "create_table" that doesn't take any parameters and doesn't return a value. This function will create a table named "spokesman" with any columns you choose in a database with the file name "region.db". If the table already exists your program should not crash (ie. your function will be called twice and should work properly on both calls).
import sqlite3
def create_table():
conn=sqlite3.connect('region.db')
cur=conn.cursor()
cur.execute("CREATE TABLE spokesman (first text)")
conn.commit()
conn.close()
What am I doing wrong, getting table spokesman already exists?
python database sqlite
add a comment |
Write a function named "create_table" that doesn't take any parameters and doesn't return a value. This function will create a table named "spokesman" with any columns you choose in a database with the file name "region.db". If the table already exists your program should not crash (ie. your function will be called twice and should work properly on both calls).
import sqlite3
def create_table():
conn=sqlite3.connect('region.db')
cur=conn.cursor()
cur.execute("CREATE TABLE spokesman (first text)")
conn.commit()
conn.close()
What am I doing wrong, getting table spokesman already exists?
python database sqlite
add a comment |
Write a function named "create_table" that doesn't take any parameters and doesn't return a value. This function will create a table named "spokesman" with any columns you choose in a database with the file name "region.db". If the table already exists your program should not crash (ie. your function will be called twice and should work properly on both calls).
import sqlite3
def create_table():
conn=sqlite3.connect('region.db')
cur=conn.cursor()
cur.execute("CREATE TABLE spokesman (first text)")
conn.commit()
conn.close()
What am I doing wrong, getting table spokesman already exists?
python database sqlite
Write a function named "create_table" that doesn't take any parameters and doesn't return a value. This function will create a table named "spokesman" with any columns you choose in a database with the file name "region.db". If the table already exists your program should not crash (ie. your function will be called twice and should work properly on both calls).
import sqlite3
def create_table():
conn=sqlite3.connect('region.db')
cur=conn.cursor()
cur.execute("CREATE TABLE spokesman (first text)")
conn.commit()
conn.close()
What am I doing wrong, getting table spokesman already exists?
python database sqlite
python database sqlite
asked Nov 24 '18 at 1:52
user10649535
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1 Answer
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That means you have already executed the program before and therefore the table has already been created. You can not create a new table with the same name as an existing table. So if you have executed the program twice, you will get that error.
Therefore, change the SQL command to CREATE TABLE IF NOT EXISTS spokesman (first text).
So the whole program shall be as follows:
import sqlite3
def create_table():
conn = sqlite3.connect('region.db')
cur = conn.cursor()
cur.execute("CREATE TABLE IF NOT EXISTS spokesman (first text)")
conn.commit()
conn.close()
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
add a comment |
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1 Answer
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1 Answer
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That means you have already executed the program before and therefore the table has already been created. You can not create a new table with the same name as an existing table. So if you have executed the program twice, you will get that error.
Therefore, change the SQL command to CREATE TABLE IF NOT EXISTS spokesman (first text).
So the whole program shall be as follows:
import sqlite3
def create_table():
conn = sqlite3.connect('region.db')
cur = conn.cursor()
cur.execute("CREATE TABLE IF NOT EXISTS spokesman (first text)")
conn.commit()
conn.close()
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
add a comment |
That means you have already executed the program before and therefore the table has already been created. You can not create a new table with the same name as an existing table. So if you have executed the program twice, you will get that error.
Therefore, change the SQL command to CREATE TABLE IF NOT EXISTS spokesman (first text).
So the whole program shall be as follows:
import sqlite3
def create_table():
conn = sqlite3.connect('region.db')
cur = conn.cursor()
cur.execute("CREATE TABLE IF NOT EXISTS spokesman (first text)")
conn.commit()
conn.close()
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
add a comment |
That means you have already executed the program before and therefore the table has already been created. You can not create a new table with the same name as an existing table. So if you have executed the program twice, you will get that error.
Therefore, change the SQL command to CREATE TABLE IF NOT EXISTS spokesman (first text).
So the whole program shall be as follows:
import sqlite3
def create_table():
conn = sqlite3.connect('region.db')
cur = conn.cursor()
cur.execute("CREATE TABLE IF NOT EXISTS spokesman (first text)")
conn.commit()
conn.close()
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
That means you have already executed the program before and therefore the table has already been created. You can not create a new table with the same name as an existing table. So if you have executed the program twice, you will get that error.
Therefore, change the SQL command to CREATE TABLE IF NOT EXISTS spokesman (first text).
So the whole program shall be as follows:
import sqlite3
def create_table():
conn = sqlite3.connect('region.db')
cur = conn.cursor()
cur.execute("CREATE TABLE IF NOT EXISTS spokesman (first text)")
conn.commit()
conn.close()
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
answered Nov 24 '18 at 1:57
RealPawPawRealPawPaw
40814
40814
add a comment |
add a comment |
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