Complete solution vs General solution of a PDE












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I am unable to understand why the general solution is a "bigger set of solutions" than the complete solution.



What is the intuition behind this?



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enter image description here










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    0












    $begingroup$


    I am unable to understand why the general solution is a "bigger set of solutions" than the complete solution.



    What is the intuition behind this?



    Source of the quotation:



    enter image description here










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I am unable to understand why the general solution is a "bigger set of solutions" than the complete solution.



      What is the intuition behind this?



      Source of the quotation:



      enter image description here










      share|cite|improve this question









      $endgroup$




      I am unable to understand why the general solution is a "bigger set of solutions" than the complete solution.



      What is the intuition behind this?



      Source of the quotation:



      enter image description here







      pde






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      asked Mar 19 '18 at 8:20









      AJ_AJ_

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          $begingroup$

          The general solution involves arbitrary function of known function's $u$ and $v$, while the complete solution involves arbitrary constants.
          The arbitrary function is more general than arbitrary constants as it include all possible functions of variable and constants, so I think that's the reason.






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            $begingroup$

            The general solution involves arbitrary function of known function's $u$ and $v$, while the complete solution involves arbitrary constants.
            The arbitrary function is more general than arbitrary constants as it include all possible functions of variable and constants, so I think that's the reason.






            share|cite|improve this answer











            $endgroup$


















              -1












              $begingroup$

              The general solution involves arbitrary function of known function's $u$ and $v$, while the complete solution involves arbitrary constants.
              The arbitrary function is more general than arbitrary constants as it include all possible functions of variable and constants, so I think that's the reason.






              share|cite|improve this answer











              $endgroup$
















                -1












                -1








                -1





                $begingroup$

                The general solution involves arbitrary function of known function's $u$ and $v$, while the complete solution involves arbitrary constants.
                The arbitrary function is more general than arbitrary constants as it include all possible functions of variable and constants, so I think that's the reason.






                share|cite|improve this answer











                $endgroup$



                The general solution involves arbitrary function of known function's $u$ and $v$, while the complete solution involves arbitrary constants.
                The arbitrary function is more general than arbitrary constants as it include all possible functions of variable and constants, so I think that's the reason.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Dec 18 '18 at 17:56









                dantopa

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                6,51942244










                answered Dec 18 '18 at 17:28









                Mansoor KhanMansoor Khan

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