Deserialize two element string in JSON
I have the following string,
[{ "AnimalName" : "Gatto", "Year" : 5.0 }, { "AnimalName" : "Gatto", "Year" : 6.0 }]
I want to Deserialize this string using the class Animali
public class Animali
{
public string AnimalName { get; set; }
public double Year { get; set; }
}
I use the following code,
Animali json = JsonConvert.DeserializeObject<Animali>(string);
My problem is that having two separate element, I receive the error;
Newtonsoft.Json.JsonReaderException: 'Additional text encountered after finished reading JSON content: ,. Path '', line 1, position 40.'
What is the correct way to deserialize the string? Any suggestion?
P.S. Using one elemente like [{ "AnimalName" : "Gatto", "Year" : 5.0 }] the code works correctly.
c# json json.net
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
add a comment |
I have the following string,
[{ "AnimalName" : "Gatto", "Year" : 5.0 }, { "AnimalName" : "Gatto", "Year" : 6.0 }]
I want to Deserialize this string using the class Animali
public class Animali
{
public string AnimalName { get; set; }
public double Year { get; set; }
}
I use the following code,
Animali json = JsonConvert.DeserializeObject<Animali>(string);
My problem is that having two separate element, I receive the error;
Newtonsoft.Json.JsonReaderException: 'Additional text encountered after finished reading JSON content: ,. Path '', line 1, position 40.'
What is the correct way to deserialize the string? Any suggestion?
P.S. Using one elemente like [{ "AnimalName" : "Gatto", "Year" : 5.0 }] the code works correctly.
c# json json.net
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
2
You have multiple animal now, you should be expecting aAnimaliorList<Animali>.
– Xiaoy312
Nov 24 '18 at 1:45
Ohhh,ok. Now is clear. With this code the Json works correctlyList<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data));Thanks so much @Xiaoy312!!
– mems
Nov 24 '18 at 2:04
add a comment |
I have the following string,
[{ "AnimalName" : "Gatto", "Year" : 5.0 }, { "AnimalName" : "Gatto", "Year" : 6.0 }]
I want to Deserialize this string using the class Animali
public class Animali
{
public string AnimalName { get; set; }
public double Year { get; set; }
}
I use the following code,
Animali json = JsonConvert.DeserializeObject<Animali>(string);
My problem is that having two separate element, I receive the error;
Newtonsoft.Json.JsonReaderException: 'Additional text encountered after finished reading JSON content: ,. Path '', line 1, position 40.'
What is the correct way to deserialize the string? Any suggestion?
P.S. Using one elemente like [{ "AnimalName" : "Gatto", "Year" : 5.0 }] the code works correctly.
c# json json.net
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
I have the following string,
[{ "AnimalName" : "Gatto", "Year" : 5.0 }, { "AnimalName" : "Gatto", "Year" : 6.0 }]
I want to Deserialize this string using the class Animali
public class Animali
{
public string AnimalName { get; set; }
public double Year { get; set; }
}
I use the following code,
Animali json = JsonConvert.DeserializeObject<Animali>(string);
My problem is that having two separate element, I receive the error;
Newtonsoft.Json.JsonReaderException: 'Additional text encountered after finished reading JSON content: ,. Path '', line 1, position 40.'
What is the correct way to deserialize the string? Any suggestion?
P.S. Using one elemente like [{ "AnimalName" : "Gatto", "Year" : 5.0 }] the code works correctly.
c# json json.net
c# json json.net
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
edited Nov 24 '18 at 10:06
Uwe Keim
27.5k32131212
27.5k32131212
asked Nov 24 '18 at 1:41
memsmems
154
asked Nov 24 '18 at 1:41
memsmems
154
asked Nov 24 '18 at 1:41
memsmems
154
154
2
You have multiple animal now, you should be expecting aAnimaliorList<Animali>.
– Xiaoy312
Nov 24 '18 at 1:45
Ohhh,ok. Now is clear. With this code the Json works correctlyList<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data));Thanks so much @Xiaoy312!!
– mems
Nov 24 '18 at 2:04
add a comment |
2
You have multiple animal now, you should be expecting aAnimaliorList<Animali>.
– Xiaoy312
Nov 24 '18 at 1:45
Ohhh,ok. Now is clear. With this code the Json works correctlyList<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data));Thanks so much @Xiaoy312!!
– mems
Nov 24 '18 at 2:04
2
2
You have multiple animal now, you should be expecting a
Animali or List<Animali>.– Xiaoy312
Nov 24 '18 at 1:45
You have multiple animal now, you should be expecting a
Animali or List<Animali>.– Xiaoy312
Nov 24 '18 at 1:45
Ohhh,ok. Now is clear. With this code the Json works correctly
List<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data)); Thanks so much @Xiaoy312!!– mems
Nov 24 '18 at 2:04
Ohhh,ok. Now is clear. With this code the Json works correctly
List<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data)); Thanks so much @Xiaoy312!!– mems
Nov 24 '18 at 2:04
add a comment |
2 Answers
2
active
oldest
votes
As pointed out, your json is an array, and you need to deserialize it as such
var results = JsonConvert.DeserializeObject<List<Animali>>(string);
Example from the json site
Deserialize a Collection
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
add a comment |
Try to parse your json string into JToken.
Cast your JToken to List.
Here I created a console app for your demonstration purpose.
class Program
{
static void Main(string args)
{
string json = @"[{ 'AnimalName' : 'Gatto', 'Year' : 5.0 }, { 'AnimalName' : 'Gatto', 'Year' : 6.0 }]";
JToken jToken = JToken.Parse(json); //Point No. 1
List<Animali> animalis = jToken.ToObject<List<Animali>>(); //Point No. 2
foreach (Animali animali in animalis) //Print result
{
Console.WriteLine("AnimalName: " + animali.AnimalName + "t Year: " + animali.Year);
}
Console.ReadLine();
}
}
Output:
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
As pointed out, your json is an array, and you need to deserialize it as such
var results = JsonConvert.DeserializeObject<List<Animali>>(string);
Example from the json site
Deserialize a Collection
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
add a comment |
As pointed out, your json is an array, and you need to deserialize it as such
var results = JsonConvert.DeserializeObject<List<Animali>>(string);
Example from the json site
Deserialize a Collection
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
add a comment |
As pointed out, your json is an array, and you need to deserialize it as such
var results = JsonConvert.DeserializeObject<List<Animali>>(string);
Example from the json site
Deserialize a Collection
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
As pointed out, your json is an array, and you need to deserialize it as such
var results = JsonConvert.DeserializeObject<List<Animali>>(string);
Example from the json site
Deserialize a Collection
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
answered Nov 24 '18 at 2:16
Michael RandallMichael Randall
32.4k63565
32.4k63565
add a comment |
add a comment |
Try to parse your json string into JToken.
Cast your JToken to List.
Here I created a console app for your demonstration purpose.
class Program
{
static void Main(string args)
{
string json = @"[{ 'AnimalName' : 'Gatto', 'Year' : 5.0 }, { 'AnimalName' : 'Gatto', 'Year' : 6.0 }]";
JToken jToken = JToken.Parse(json); //Point No. 1
List<Animali> animalis = jToken.ToObject<List<Animali>>(); //Point No. 2
foreach (Animali animali in animalis) //Print result
{
Console.WriteLine("AnimalName: " + animali.AnimalName + "t Year: " + animali.Year);
}
Console.ReadLine();
}
}
Output:
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
add a comment |
Try to parse your json string into JToken.
Cast your JToken to List.
Here I created a console app for your demonstration purpose.
class Program
{
static void Main(string args)
{
string json = @"[{ 'AnimalName' : 'Gatto', 'Year' : 5.0 }, { 'AnimalName' : 'Gatto', 'Year' : 6.0 }]";
JToken jToken = JToken.Parse(json); //Point No. 1
List<Animali> animalis = jToken.ToObject<List<Animali>>(); //Point No. 2
foreach (Animali animali in animalis) //Print result
{
Console.WriteLine("AnimalName: " + animali.AnimalName + "t Year: " + animali.Year);
}
Console.ReadLine();
}
}
Output:
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
add a comment |
Try to parse your json string into JToken.
Cast your JToken to List.
Here I created a console app for your demonstration purpose.
class Program
{
static void Main(string args)
{
string json = @"[{ 'AnimalName' : 'Gatto', 'Year' : 5.0 }, { 'AnimalName' : 'Gatto', 'Year' : 6.0 }]";
JToken jToken = JToken.Parse(json); //Point No. 1
List<Animali> animalis = jToken.ToObject<List<Animali>>(); //Point No. 2
foreach (Animali animali in animalis) //Print result
{
Console.WriteLine("AnimalName: " + animali.AnimalName + "t Year: " + animali.Year);
}
Console.ReadLine();
}
}
Output:
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
Try to parse your json string into JToken.
Cast your JToken to List.
Here I created a console app for your demonstration purpose.
class Program
{
static void Main(string args)
{
string json = @"[{ 'AnimalName' : 'Gatto', 'Year' : 5.0 }, { 'AnimalName' : 'Gatto', 'Year' : 6.0 }]";
JToken jToken = JToken.Parse(json); //Point No. 1
List<Animali> animalis = jToken.ToObject<List<Animali>>(); //Point No. 2
foreach (Animali animali in animalis) //Print result
{
Console.WriteLine("AnimalName: " + animali.AnimalName + "t Year: " + animali.Year);
}
Console.ReadLine();
}
}
Output:
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
edited Nov 24 '18 at 10:30
Uwe Keim
27.5k32131212
27.5k32131212
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
answered Nov 24 '18 at 10:02
er-shoer-sho
6,1472617
6,1472617
add a comment |
add a comment |
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2
You have multiple animal now, you should be expecting a
AnimaliorList<Animali>.– Xiaoy312
Nov 24 '18 at 1:45
Ohhh,ok. Now is clear. With this code the Json works correctly
List<Animali> jsonReal2 = JsonConvert.DeserializeObject <List<Animali>>(Encoding.ASCII.GetString(data));Thanks so much @Xiaoy312!!– mems
Nov 24 '18 at 2:04