C++20 bit_cast vs reinterpret_cast












7














According to the last meeting of the ISO C++ Commitee, bit-cast will be introduced in C++20 standard.



I know that reinterpret_cast is not suitable for this job due to type allasing rules but my question is why did they choose not to extend the reinterpret_cast to treat the object like it bit sequence representation and prefered to give this functionallity as a new language construct?










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  • In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
    – Nicol Bolas
    Nov 20 at 21:23












  • @NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
    – geza
    Nov 20 at 21:29










  • I was thinking exactly like @geza suggested
    – bogdan tudose
    Nov 20 at 21:34
















7














According to the last meeting of the ISO C++ Commitee, bit-cast will be introduced in C++20 standard.



I know that reinterpret_cast is not suitable for this job due to type allasing rules but my question is why did they choose not to extend the reinterpret_cast to treat the object like it bit sequence representation and prefered to give this functionallity as a new language construct?










share|improve this question
























  • In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
    – Nicol Bolas
    Nov 20 at 21:23












  • @NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
    – geza
    Nov 20 at 21:29










  • I was thinking exactly like @geza suggested
    – bogdan tudose
    Nov 20 at 21:34














7












7








7


1





According to the last meeting of the ISO C++ Commitee, bit-cast will be introduced in C++20 standard.



I know that reinterpret_cast is not suitable for this job due to type allasing rules but my question is why did they choose not to extend the reinterpret_cast to treat the object like it bit sequence representation and prefered to give this functionallity as a new language construct?










share|improve this question















According to the last meeting of the ISO C++ Commitee, bit-cast will be introduced in C++20 standard.



I know that reinterpret_cast is not suitable for this job due to type allasing rules but my question is why did they choose not to extend the reinterpret_cast to treat the object like it bit sequence representation and prefered to give this functionallity as a new language construct?







c++ language-lawyer type-alias c++20






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share|improve this question













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share|improve this question








edited Nov 21 at 10:43

























asked Nov 20 at 21:16









bogdan tudose

867




867












  • In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
    – Nicol Bolas
    Nov 20 at 21:23












  • @NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
    – geza
    Nov 20 at 21:29










  • I was thinking exactly like @geza suggested
    – bogdan tudose
    Nov 20 at 21:34


















  • In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
    – Nicol Bolas
    Nov 20 at 21:23












  • @NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
    – geza
    Nov 20 at 21:29










  • I was thinking exactly like @geza suggested
    – bogdan tudose
    Nov 20 at 21:34
















In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
– Nicol Bolas
Nov 20 at 21:23






In what way are you suggesting that reinterpret_cast be extended? That is, what would code that uses this hypothetically look like?
– Nicol Bolas
Nov 20 at 21:23














@NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
– geza
Nov 20 at 21:29




@NicolBolas: How about allowing reinterpret_cast to do this: float x = 1.0f; reinterpret_cast<unsigned int>(x);.
– geza
Nov 20 at 21:29












I was thinking exactly like @geza suggested
– bogdan tudose
Nov 20 at 21:34




I was thinking exactly like @geza suggested
– bogdan tudose
Nov 20 at 21:34












1 Answer
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Well, there is one obvious reason: because it wouldn't do everything that bit_cast does. Even in the C++20 world where we can allocate memory at compile time, reinterpret_cast is forbidden in constexpr functions. One of the explicit goals of bit_cast is to be able to do these sorts of things at compile-time:




Furthermore, it is currently impossible to implement a constexpr bit-cast function, as memcpy itself isn’t constexpr. Marking the proposed function as constexpr doesn’t require or prevent memcpy from becoming constexpr, but requires compiler support. This leaves implementations free to use their own internal solution (e.g. LLVM has a bitcast opcode).




Now, you could say that you could just extend this specific usage of reinterpret_cast to constexpr contexts. But that makes the rules complicated. Instead of simply knowing that reinterpret_cast can't be used in constexpr code period, you have to remember the specific forms of reinterpret_cast that can't be used.



Also, there are practical concerns. Even if you wanted to go the reinterpret_cast route, std::bit_cast is a library function. And it's always easier to get a library feature through the committee than a language feature, even if it would receive some compiler support.



Then there's the more subjective stuff. reinterpret_cast is generally considered an inherently dangerous operation, indicative of "cheating" the type system in some way. By contrast, bit_cast is not. It is generating a new object as if by copying its value representation from an existing one. It's a low-level tool, but it's not a tool that messes with the type system. So it would be strange to spell a "safe" operation the same way you spell a "dangerous" one.



Indeed, if you did spell them the same way, it starts raising questions as to why this is reasonably well-defined:



float f = 20.4f;
int i = reinterpret_cast<int>(f);


But this is somehow bad:



float f = 20.4f;
int &i = reinterpret_cast<int &>(f);


And sure, a language lawyer or someone familiar with the strict aliasing rule would understand why the latter is bad. But for the lay person, if it is fine to use reinterpret_cast to do a bit-conversion, it is unclear why it is wrong to use reinterpret_cast to convert pointers/references and interpret an existing object as a converted type.



Different tools should be spelled differently.






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    Well, there is one obvious reason: because it wouldn't do everything that bit_cast does. Even in the C++20 world where we can allocate memory at compile time, reinterpret_cast is forbidden in constexpr functions. One of the explicit goals of bit_cast is to be able to do these sorts of things at compile-time:




    Furthermore, it is currently impossible to implement a constexpr bit-cast function, as memcpy itself isn’t constexpr. Marking the proposed function as constexpr doesn’t require or prevent memcpy from becoming constexpr, but requires compiler support. This leaves implementations free to use their own internal solution (e.g. LLVM has a bitcast opcode).




    Now, you could say that you could just extend this specific usage of reinterpret_cast to constexpr contexts. But that makes the rules complicated. Instead of simply knowing that reinterpret_cast can't be used in constexpr code period, you have to remember the specific forms of reinterpret_cast that can't be used.



    Also, there are practical concerns. Even if you wanted to go the reinterpret_cast route, std::bit_cast is a library function. And it's always easier to get a library feature through the committee than a language feature, even if it would receive some compiler support.



    Then there's the more subjective stuff. reinterpret_cast is generally considered an inherently dangerous operation, indicative of "cheating" the type system in some way. By contrast, bit_cast is not. It is generating a new object as if by copying its value representation from an existing one. It's a low-level tool, but it's not a tool that messes with the type system. So it would be strange to spell a "safe" operation the same way you spell a "dangerous" one.



    Indeed, if you did spell them the same way, it starts raising questions as to why this is reasonably well-defined:



    float f = 20.4f;
    int i = reinterpret_cast<int>(f);


    But this is somehow bad:



    float f = 20.4f;
    int &i = reinterpret_cast<int &>(f);


    And sure, a language lawyer or someone familiar with the strict aliasing rule would understand why the latter is bad. But for the lay person, if it is fine to use reinterpret_cast to do a bit-conversion, it is unclear why it is wrong to use reinterpret_cast to convert pointers/references and interpret an existing object as a converted type.



    Different tools should be spelled differently.






    share|improve this answer




























      8














      Well, there is one obvious reason: because it wouldn't do everything that bit_cast does. Even in the C++20 world where we can allocate memory at compile time, reinterpret_cast is forbidden in constexpr functions. One of the explicit goals of bit_cast is to be able to do these sorts of things at compile-time:




      Furthermore, it is currently impossible to implement a constexpr bit-cast function, as memcpy itself isn’t constexpr. Marking the proposed function as constexpr doesn’t require or prevent memcpy from becoming constexpr, but requires compiler support. This leaves implementations free to use their own internal solution (e.g. LLVM has a bitcast opcode).




      Now, you could say that you could just extend this specific usage of reinterpret_cast to constexpr contexts. But that makes the rules complicated. Instead of simply knowing that reinterpret_cast can't be used in constexpr code period, you have to remember the specific forms of reinterpret_cast that can't be used.



      Also, there are practical concerns. Even if you wanted to go the reinterpret_cast route, std::bit_cast is a library function. And it's always easier to get a library feature through the committee than a language feature, even if it would receive some compiler support.



      Then there's the more subjective stuff. reinterpret_cast is generally considered an inherently dangerous operation, indicative of "cheating" the type system in some way. By contrast, bit_cast is not. It is generating a new object as if by copying its value representation from an existing one. It's a low-level tool, but it's not a tool that messes with the type system. So it would be strange to spell a "safe" operation the same way you spell a "dangerous" one.



      Indeed, if you did spell them the same way, it starts raising questions as to why this is reasonably well-defined:



      float f = 20.4f;
      int i = reinterpret_cast<int>(f);


      But this is somehow bad:



      float f = 20.4f;
      int &i = reinterpret_cast<int &>(f);


      And sure, a language lawyer or someone familiar with the strict aliasing rule would understand why the latter is bad. But for the lay person, if it is fine to use reinterpret_cast to do a bit-conversion, it is unclear why it is wrong to use reinterpret_cast to convert pointers/references and interpret an existing object as a converted type.



      Different tools should be spelled differently.






      share|improve this answer


























        8












        8








        8






        Well, there is one obvious reason: because it wouldn't do everything that bit_cast does. Even in the C++20 world where we can allocate memory at compile time, reinterpret_cast is forbidden in constexpr functions. One of the explicit goals of bit_cast is to be able to do these sorts of things at compile-time:




        Furthermore, it is currently impossible to implement a constexpr bit-cast function, as memcpy itself isn’t constexpr. Marking the proposed function as constexpr doesn’t require or prevent memcpy from becoming constexpr, but requires compiler support. This leaves implementations free to use their own internal solution (e.g. LLVM has a bitcast opcode).




        Now, you could say that you could just extend this specific usage of reinterpret_cast to constexpr contexts. But that makes the rules complicated. Instead of simply knowing that reinterpret_cast can't be used in constexpr code period, you have to remember the specific forms of reinterpret_cast that can't be used.



        Also, there are practical concerns. Even if you wanted to go the reinterpret_cast route, std::bit_cast is a library function. And it's always easier to get a library feature through the committee than a language feature, even if it would receive some compiler support.



        Then there's the more subjective stuff. reinterpret_cast is generally considered an inherently dangerous operation, indicative of "cheating" the type system in some way. By contrast, bit_cast is not. It is generating a new object as if by copying its value representation from an existing one. It's a low-level tool, but it's not a tool that messes with the type system. So it would be strange to spell a "safe" operation the same way you spell a "dangerous" one.



        Indeed, if you did spell them the same way, it starts raising questions as to why this is reasonably well-defined:



        float f = 20.4f;
        int i = reinterpret_cast<int>(f);


        But this is somehow bad:



        float f = 20.4f;
        int &i = reinterpret_cast<int &>(f);


        And sure, a language lawyer or someone familiar with the strict aliasing rule would understand why the latter is bad. But for the lay person, if it is fine to use reinterpret_cast to do a bit-conversion, it is unclear why it is wrong to use reinterpret_cast to convert pointers/references and interpret an existing object as a converted type.



        Different tools should be spelled differently.






        share|improve this answer














        Well, there is one obvious reason: because it wouldn't do everything that bit_cast does. Even in the C++20 world where we can allocate memory at compile time, reinterpret_cast is forbidden in constexpr functions. One of the explicit goals of bit_cast is to be able to do these sorts of things at compile-time:




        Furthermore, it is currently impossible to implement a constexpr bit-cast function, as memcpy itself isn’t constexpr. Marking the proposed function as constexpr doesn’t require or prevent memcpy from becoming constexpr, but requires compiler support. This leaves implementations free to use their own internal solution (e.g. LLVM has a bitcast opcode).




        Now, you could say that you could just extend this specific usage of reinterpret_cast to constexpr contexts. But that makes the rules complicated. Instead of simply knowing that reinterpret_cast can't be used in constexpr code period, you have to remember the specific forms of reinterpret_cast that can't be used.



        Also, there are practical concerns. Even if you wanted to go the reinterpret_cast route, std::bit_cast is a library function. And it's always easier to get a library feature through the committee than a language feature, even if it would receive some compiler support.



        Then there's the more subjective stuff. reinterpret_cast is generally considered an inherently dangerous operation, indicative of "cheating" the type system in some way. By contrast, bit_cast is not. It is generating a new object as if by copying its value representation from an existing one. It's a low-level tool, but it's not a tool that messes with the type system. So it would be strange to spell a "safe" operation the same way you spell a "dangerous" one.



        Indeed, if you did spell them the same way, it starts raising questions as to why this is reasonably well-defined:



        float f = 20.4f;
        int i = reinterpret_cast<int>(f);


        But this is somehow bad:



        float f = 20.4f;
        int &i = reinterpret_cast<int &>(f);


        And sure, a language lawyer or someone familiar with the strict aliasing rule would understand why the latter is bad. But for the lay person, if it is fine to use reinterpret_cast to do a bit-conversion, it is unclear why it is wrong to use reinterpret_cast to convert pointers/references and interpret an existing object as a converted type.



        Different tools should be spelled differently.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 21 at 14:34

























        answered Nov 20 at 21:57









        Nicol Bolas

        281k33464640




        281k33464640






























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