Two-variable limit of $lim_{(x,y)to(0,0)}frac{sin(x^4+y^4)}{x^2+y^2}$












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$begingroup$


$$lim_{(x,y)to(0,0)}frac{sin(x^4+y^4)}{x^2+y^2}$$



I tried to bound it with $frac{sin((x^2+y^2)^2)}{x^2+y^2}$ and using polar coordinates with $x = rcostheta$ and $y = rsintheta$, but neither of the approaches provided any results. I know that the limit exists and is equal to 0, so tricks with different paths won't work. Should I use the squeeze theorem, or is there another solution?










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$endgroup$

















    4












    $begingroup$


    $$lim_{(x,y)to(0,0)}frac{sin(x^4+y^4)}{x^2+y^2}$$



    I tried to bound it with $frac{sin((x^2+y^2)^2)}{x^2+y^2}$ and using polar coordinates with $x = rcostheta$ and $y = rsintheta$, but neither of the approaches provided any results. I know that the limit exists and is equal to 0, so tricks with different paths won't work. Should I use the squeeze theorem, or is there another solution?










    share|cite|improve this question











    $endgroup$















      4












      4








      4


      2



      $begingroup$


      $$lim_{(x,y)to(0,0)}frac{sin(x^4+y^4)}{x^2+y^2}$$



      I tried to bound it with $frac{sin((x^2+y^2)^2)}{x^2+y^2}$ and using polar coordinates with $x = rcostheta$ and $y = rsintheta$, but neither of the approaches provided any results. I know that the limit exists and is equal to 0, so tricks with different paths won't work. Should I use the squeeze theorem, or is there another solution?










      share|cite|improve this question











      $endgroup$




      $$lim_{(x,y)to(0,0)}frac{sin(x^4+y^4)}{x^2+y^2}$$



      I tried to bound it with $frac{sin((x^2+y^2)^2)}{x^2+y^2}$ and using polar coordinates with $x = rcostheta$ and $y = rsintheta$, but neither of the approaches provided any results. I know that the limit exists and is equal to 0, so tricks with different paths won't work. Should I use the squeeze theorem, or is there another solution?







      limits multivariable-calculus






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      edited Dec 24 '18 at 22:55









      Lorenzo B.

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      1,8622520










      asked Oct 8 '17 at 8:26









      JoaldJoald

      393314




      393314






















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          $begingroup$

          Use $|sin t|leq |t|$ then
          $$Big|frac{sin(x^4+y^4)}{x^2+y^2}Big|leqfrac{x^4+y^4}{x^2+y^2}leqfrac{x^4+y^4+2x^2y^2}{x^2+y^2}= x^2+y^2$$






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            1 Answer
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            1 Answer
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            12












            $begingroup$

            Use $|sin t|leq |t|$ then
            $$Big|frac{sin(x^4+y^4)}{x^2+y^2}Big|leqfrac{x^4+y^4}{x^2+y^2}leqfrac{x^4+y^4+2x^2y^2}{x^2+y^2}= x^2+y^2$$






            share|cite|improve this answer











            $endgroup$


















              12












              $begingroup$

              Use $|sin t|leq |t|$ then
              $$Big|frac{sin(x^4+y^4)}{x^2+y^2}Big|leqfrac{x^4+y^4}{x^2+y^2}leqfrac{x^4+y^4+2x^2y^2}{x^2+y^2}= x^2+y^2$$






              share|cite|improve this answer











              $endgroup$
















                12












                12








                12





                $begingroup$

                Use $|sin t|leq |t|$ then
                $$Big|frac{sin(x^4+y^4)}{x^2+y^2}Big|leqfrac{x^4+y^4}{x^2+y^2}leqfrac{x^4+y^4+2x^2y^2}{x^2+y^2}= x^2+y^2$$






                share|cite|improve this answer











                $endgroup$



                Use $|sin t|leq |t|$ then
                $$Big|frac{sin(x^4+y^4)}{x^2+y^2}Big|leqfrac{x^4+y^4}{x^2+y^2}leqfrac{x^4+y^4+2x^2y^2}{x^2+y^2}= x^2+y^2$$







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Oct 8 '17 at 8:35









                Andrei

                13.1k21230




                13.1k21230










                answered Oct 8 '17 at 8:30









                NosratiNosrati

                26.6k62354




                26.6k62354






























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