Converting key, value pairs in a JSON column into their own separate columns












0















I have a table that has just two columns, a uuid column and a json_data column which contains JSON. So the table looks like this...



uuid    json
uuid1 {'0.25': '1.0', '0.5': '2.0'}
uuid2 {'0.25': '4.0', '0.5': '8.0'}


My desired output is to have each of these json keys as it's own column, in other words, a wide format. I can get the table into a long format by using the json_each function



SELECT uuid, json_each(json) AS key_values
FROM mytable;


which returns



uuid    key_values
uuid1 ('0.25', '1.0')
uuid1 ('0.5', '2.0')
uuid2 ('0.25', '4.0')
uuid2 ('0.5', '8.0')


But what I would ideally like is...



uuid    0.25    0.5
uuid1 1.0 2.0
uuid2 4.0 8.0









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  • 1





    what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

    – Kaushik Nayak
    Nov 26 '18 at 11:59
















0















I have a table that has just two columns, a uuid column and a json_data column which contains JSON. So the table looks like this...



uuid    json
uuid1 {'0.25': '1.0', '0.5': '2.0'}
uuid2 {'0.25': '4.0', '0.5': '8.0'}


My desired output is to have each of these json keys as it's own column, in other words, a wide format. I can get the table into a long format by using the json_each function



SELECT uuid, json_each(json) AS key_values
FROM mytable;


which returns



uuid    key_values
uuid1 ('0.25', '1.0')
uuid1 ('0.5', '2.0')
uuid2 ('0.25', '4.0')
uuid2 ('0.5', '8.0')


But what I would ideally like is...



uuid    0.25    0.5
uuid1 1.0 2.0
uuid2 4.0 8.0









share|improve this question


















  • 1





    what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

    – Kaushik Nayak
    Nov 26 '18 at 11:59














0












0








0








I have a table that has just two columns, a uuid column and a json_data column which contains JSON. So the table looks like this...



uuid    json
uuid1 {'0.25': '1.0', '0.5': '2.0'}
uuid2 {'0.25': '4.0', '0.5': '8.0'}


My desired output is to have each of these json keys as it's own column, in other words, a wide format. I can get the table into a long format by using the json_each function



SELECT uuid, json_each(json) AS key_values
FROM mytable;


which returns



uuid    key_values
uuid1 ('0.25', '1.0')
uuid1 ('0.5', '2.0')
uuid2 ('0.25', '4.0')
uuid2 ('0.5', '8.0')


But what I would ideally like is...



uuid    0.25    0.5
uuid1 1.0 2.0
uuid2 4.0 8.0









share|improve this question














I have a table that has just two columns, a uuid column and a json_data column which contains JSON. So the table looks like this...



uuid    json
uuid1 {'0.25': '1.0', '0.5': '2.0'}
uuid2 {'0.25': '4.0', '0.5': '8.0'}


My desired output is to have each of these json keys as it's own column, in other words, a wide format. I can get the table into a long format by using the json_each function



SELECT uuid, json_each(json) AS key_values
FROM mytable;


which returns



uuid    key_values
uuid1 ('0.25', '1.0')
uuid1 ('0.5', '2.0')
uuid2 ('0.25', '4.0')
uuid2 ('0.5', '8.0')


But what I would ideally like is...



uuid    0.25    0.5
uuid1 1.0 2.0
uuid2 4.0 8.0






json postgresql






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asked Nov 26 '18 at 9:22









bgranthambgrantham

5316




5316








  • 1





    what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

    – Kaushik Nayak
    Nov 26 '18 at 11:59














  • 1





    what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

    – Kaushik Nayak
    Nov 26 '18 at 11:59








1




1





what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

– Kaushik Nayak
Nov 26 '18 at 11:59





what you need is a dynamic pivot using the output of key value pairs from json_each . It isn't straightforward, see stackoverflow.com/a/36831103/7998591

– Kaushik Nayak
Nov 26 '18 at 11:59












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