Write a function to return diagonal elements of an array(NxN) as an array in python
0
import numpy as np
#getting number of rows and columns for the arrat
nr=input("enter rows")
nc=input("enter columns")
print("Please enter same rows and columns")
n=nr*nc
ar1=
#checking for square matrix
if(nr==nc):
#loop to append elements into the empty-list ar1
for i in range(n):
ele=input("enter elements")
ar1.append(ele)
#getting the number of rows of array1
array1=np.array(ar1).shape
#function to get the diagonal elements of array
def diagonal(a):
global n
n=str(n)
for i in n:
for j in n:
if i==j:
newarr=np.array(a[i][j])
#print(newarr)
diagonal(array1)
newarr=np.array(a[i][j]) is resulting in an error showing:
#TypeError: tuple indices must be integers, not str for below code
python numpy
asked Nov 26 '18 at 9:10
SethuSethu
269
add a comment |
0
import numpy as np
#getting number of rows and columns for the arrat
nr=input("enter rows")
nc=input("enter columns")
print("Please enter same rows and columns")
n=nr*nc
ar1=
#checking for square matrix
if(nr==nc):
#loop to append elements into the empty-list ar1
for i in range(n):
ele=input("enter elements")
ar1.append(ele)
#getting the number of rows of array1
array1=np.array(ar1).shape
#function to get the diagonal elements of array
def diagonal(a):
global n
n=str(n)
for i in n:
for j in n:
if i==j:
newarr=np.array(a[i][j])
#print(newarr)
diagonal(array1)
newarr=np.array(a[i][j]) is resulting in an error showing:
#TypeError: tuple indices must be integers, not str for below code
python numpy
asked Nov 26 '18 at 9:10
SethuSethu
269
Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23
add a comment |
0
0
0
import numpy as np
#getting number of rows and columns for the arrat
nr=input("enter rows")
nc=input("enter columns")
print("Please enter same rows and columns")
n=nr*nc
ar1=
#checking for square matrix
if(nr==nc):
#loop to append elements into the empty-list ar1
for i in range(n):
ele=input("enter elements")
ar1.append(ele)
#getting the number of rows of array1
array1=np.array(ar1).shape
#function to get the diagonal elements of array
def diagonal(a):
global n
n=str(n)
for i in n:
for j in n:
if i==j:
newarr=np.array(a[i][j])
#print(newarr)
diagonal(array1)
newarr=np.array(a[i][j]) is resulting in an error showing:
#TypeError: tuple indices must be integers, not str for below code
python numpy
asked Nov 26 '18 at 9:10
SethuSethu
269
import numpy as np
#getting number of rows and columns for the arrat
nr=input("enter rows")
nc=input("enter columns")
print("Please enter same rows and columns")
n=nr*nc
ar1=
#checking for square matrix
if(nr==nc):
#loop to append elements into the empty-list ar1
for i in range(n):
ele=input("enter elements")
ar1.append(ele)
#getting the number of rows of array1
array1=np.array(ar1).shape
#function to get the diagonal elements of array
def diagonal(a):
global n
n=str(n)
for i in n:
for j in n:
if i==j:
newarr=np.array(a[i][j])
#print(newarr)
diagonal(array1)
newarr=np.array(a[i][j]) is resulting in an error showing:
#TypeError: tuple indices must be integers, not str for below code
python numpy
python numpy
asked Nov 26 '18 at 9:10
SethuSethu
269
asked Nov 26 '18 at 9:10
SethuSethu
269
asked Nov 26 '18 at 9:10
SethuSethu
269
asked Nov 26 '18 at 9:10
SethuSethu
269
asked Nov 26 '18 at 9:10
SethuSethu
269
269
Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23
add a comment |
Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23
Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23
Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23
add a comment |
2 Answers
2
active
oldest
votes
0
If you know that your matrix is going to be a square one, you need not take the row and column input separately. You can just take the value n. Your diagonal function will then look like :
newa=
def diag(arr):
for i,a in enumerate(arr):
newa[i]=arr[i,i]
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
add a comment |
0
I do agree with @Gautam, by the way here's a workaround solution which uses inbuilt diagonal function:
lst =
size = int(input('Enter size of sqaure matrix'))
for i in range(1, (size**2)+1):
lst.append(int(input('Enter ' + str(i) +'th element')))
lst
Enter size of sqaure matrix2
Enter 1th element5
Enter 2th element6
Enter 3th element8
Enter 4th element7
[5, 6, 8, 7]
arr = np.array(lst).reshape(size,size)
arr.diagonal()
[5, 7]
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
If you know that your matrix is going to be a square one, you need not take the row and column input separately. You can just take the value n. Your diagonal function will then look like :
newa=
def diag(arr):
for i,a in enumerate(arr):
newa[i]=arr[i,i]
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
add a comment |
0
If you know that your matrix is going to be a square one, you need not take the row and column input separately. You can just take the value n. Your diagonal function will then look like :
newa=
def diag(arr):
for i,a in enumerate(arr):
newa[i]=arr[i,i]
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
add a comment |
0
0
0
If you know that your matrix is going to be a square one, you need not take the row and column input separately. You can just take the value n. Your diagonal function will then look like :
newa=
def diag(arr):
for i,a in enumerate(arr):
newa[i]=arr[i,i]
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
If you know that your matrix is going to be a square one, you need not take the row and column input separately. You can just take the value n. Your diagonal function will then look like :
newa=
def diag(arr):
for i,a in enumerate(arr):
newa[i]=arr[i,i]
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
answered Nov 26 '18 at 9:17
GautamGautam
1,12329
1,12329
add a comment |
add a comment |
0
I do agree with @Gautam, by the way here's a workaround solution which uses inbuilt diagonal function:
lst =
size = int(input('Enter size of sqaure matrix'))
for i in range(1, (size**2)+1):
lst.append(int(input('Enter ' + str(i) +'th element')))
lst
Enter size of sqaure matrix2
Enter 1th element5
Enter 2th element6
Enter 3th element8
Enter 4th element7
[5, 6, 8, 7]
arr = np.array(lst).reshape(size,size)
arr.diagonal()
[5, 7]
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
add a comment |
0
I do agree with @Gautam, by the way here's a workaround solution which uses inbuilt diagonal function:
lst =
size = int(input('Enter size of sqaure matrix'))
for i in range(1, (size**2)+1):
lst.append(int(input('Enter ' + str(i) +'th element')))
lst
Enter size of sqaure matrix2
Enter 1th element5
Enter 2th element6
Enter 3th element8
Enter 4th element7
[5, 6, 8, 7]
arr = np.array(lst).reshape(size,size)
arr.diagonal()
[5, 7]
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
add a comment |
0
0
0
I do agree with @Gautam, by the way here's a workaround solution which uses inbuilt diagonal function:
lst =
size = int(input('Enter size of sqaure matrix'))
for i in range(1, (size**2)+1):
lst.append(int(input('Enter ' + str(i) +'th element')))
lst
Enter size of sqaure matrix2
Enter 1th element5
Enter 2th element6
Enter 3th element8
Enter 4th element7
[5, 6, 8, 7]
arr = np.array(lst).reshape(size,size)
arr.diagonal()
[5, 7]
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
I do agree with @Gautam, by the way here's a workaround solution which uses inbuilt diagonal function:
lst =
size = int(input('Enter size of sqaure matrix'))
for i in range(1, (size**2)+1):
lst.append(int(input('Enter ' + str(i) +'th element')))
lst
Enter size of sqaure matrix2
Enter 1th element5
Enter 2th element6
Enter 3th element8
Enter 4th element7
[5, 6, 8, 7]
arr = np.array(lst).reshape(size,size)
arr.diagonal()
[5, 7]
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
answered Nov 26 '18 at 9:21
dataLeodataLeo
6431519
6431519
add a comment |
add a comment |
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Isn't the error clear? Why don't you fix this (pretty obvious) issue first? Also consider a Minimal, Complete, and Verifiable example, if you're not clear where they come from and how to fix them.
– Ulrich Eckhardt
Nov 26 '18 at 9:23