save multi thread output to txt file












-3















i write this simple code ... i need to save the code output to text file in my pc how i can do that ?



import threading
import time


def qan(hey):
while True:

d = hey + 1
print d
time.sleep(1)


def printd(printme):
while True:
print printme + "n"
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()


and this is my code output




hey



2 2 hey



2hey



2











share|improve this question























  • Possible duplicate of many threads to write log file at same time python

    – user10455554
    Nov 26 '18 at 9:12
















-3















i write this simple code ... i need to save the code output to text file in my pc how i can do that ?



import threading
import time


def qan(hey):
while True:

d = hey + 1
print d
time.sleep(1)


def printd(printme):
while True:
print printme + "n"
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()


and this is my code output




hey



2 2 hey



2hey



2











share|improve this question























  • Possible duplicate of many threads to write log file at same time python

    – user10455554
    Nov 26 '18 at 9:12














-3












-3








-3








i write this simple code ... i need to save the code output to text file in my pc how i can do that ?



import threading
import time


def qan(hey):
while True:

d = hey + 1
print d
time.sleep(1)


def printd(printme):
while True:
print printme + "n"
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()


and this is my code output




hey



2 2 hey



2hey



2











share|improve this question














i write this simple code ... i need to save the code output to text file in my pc how i can do that ?



import threading
import time


def qan(hey):
while True:

d = hey + 1
print d
time.sleep(1)


def printd(printme):
while True:
print printme + "n"
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()


and this is my code output




hey



2 2 hey



2hey



2








python windows multithreading save python-multithreading






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 26 '18 at 9:09









evilcode1evilcode1

328




328













  • Possible duplicate of many threads to write log file at same time python

    – user10455554
    Nov 26 '18 at 9:12



















  • Possible duplicate of many threads to write log file at same time python

    – user10455554
    Nov 26 '18 at 9:12

















Possible duplicate of many threads to write log file at same time python

– user10455554
Nov 26 '18 at 9:12





Possible duplicate of many threads to write log file at same time python

– user10455554
Nov 26 '18 at 9:12












1 Answer
1






active

oldest

votes


















0














Use some buffer with data:



import threading
import time


buffer =

def qan(hey):
while True:

d = hey + 1
buffer.append(d)
time.sleep(1)


def printd(printme):
while True:
buffer.append(printme + "n")
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()

with open('output.txt') as f:
f.write(''.join(buffer))





share|improve this answer
























  • its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

    – evilcode1
    Nov 26 '18 at 10:38













  • output : ['heyn', 2] just oneline !!

    – evilcode1
    Nov 26 '18 at 10:38











  • rewrite first buffer.append as buffer.append(str(d) + 'n')

    – Nick
    Nov 26 '18 at 10:40













  • First of all, print in python prints string with 'n' , and join method works only with list strings

    – Nick
    Nov 26 '18 at 10:42













  • so how i can solve this issue ?

    – evilcode1
    Dec 4 '18 at 16:29












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Use some buffer with data:



import threading
import time


buffer =

def qan(hey):
while True:

d = hey + 1
buffer.append(d)
time.sleep(1)


def printd(printme):
while True:
buffer.append(printme + "n")
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()

with open('output.txt') as f:
f.write(''.join(buffer))





share|improve this answer
























  • its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

    – evilcode1
    Nov 26 '18 at 10:38













  • output : ['heyn', 2] just oneline !!

    – evilcode1
    Nov 26 '18 at 10:38











  • rewrite first buffer.append as buffer.append(str(d) + 'n')

    – Nick
    Nov 26 '18 at 10:40













  • First of all, print in python prints string with 'n' , and join method works only with list strings

    – Nick
    Nov 26 '18 at 10:42













  • so how i can solve this issue ?

    – evilcode1
    Dec 4 '18 at 16:29
















0














Use some buffer with data:



import threading
import time


buffer =

def qan(hey):
while True:

d = hey + 1
buffer.append(d)
time.sleep(1)


def printd(printme):
while True:
buffer.append(printme + "n")
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()

with open('output.txt') as f:
f.write(''.join(buffer))





share|improve this answer
























  • its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

    – evilcode1
    Nov 26 '18 at 10:38













  • output : ['heyn', 2] just oneline !!

    – evilcode1
    Nov 26 '18 at 10:38











  • rewrite first buffer.append as buffer.append(str(d) + 'n')

    – Nick
    Nov 26 '18 at 10:40













  • First of all, print in python prints string with 'n' , and join method works only with list strings

    – Nick
    Nov 26 '18 at 10:42













  • so how i can solve this issue ?

    – evilcode1
    Dec 4 '18 at 16:29














0












0








0







Use some buffer with data:



import threading
import time


buffer =

def qan(hey):
while True:

d = hey + 1
buffer.append(d)
time.sleep(1)


def printd(printme):
while True:
buffer.append(printme + "n")
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()

with open('output.txt') as f:
f.write(''.join(buffer))





share|improve this answer













Use some buffer with data:



import threading
import time


buffer =

def qan(hey):
while True:

d = hey + 1
buffer.append(d)
time.sleep(1)


def printd(printme):
while True:
buffer.append(printme + "n")
time.sleep(1)


t1 = threading.Thread(target=qan, args=(1,))
t2 = threading.Thread(target=printd, args=("hey",))
t2.start()
t1.start()

with open('output.txt') as f:
f.write(''.join(buffer))






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 26 '18 at 9:14









NickNick

2998




2998













  • its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

    – evilcode1
    Nov 26 '18 at 10:38













  • output : ['heyn', 2] just oneline !!

    – evilcode1
    Nov 26 '18 at 10:38











  • rewrite first buffer.append as buffer.append(str(d) + 'n')

    – Nick
    Nov 26 '18 at 10:40













  • First of all, print in python prints string with 'n' , and join method works only with list strings

    – Nick
    Nov 26 '18 at 10:42













  • so how i can solve this issue ?

    – evilcode1
    Dec 4 '18 at 16:29



















  • its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

    – evilcode1
    Nov 26 '18 at 10:38













  • output : ['heyn', 2] just oneline !!

    – evilcode1
    Nov 26 '18 at 10:38











  • rewrite first buffer.append as buffer.append(str(d) + 'n')

    – Nick
    Nov 26 '18 at 10:40













  • First of all, print in python prints string with 'n' , and join method works only with list strings

    – Nick
    Nov 26 '18 at 10:42













  • so how i can solve this issue ?

    – evilcode1
    Dec 4 '18 at 16:29

















its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

– evilcode1
Nov 26 '18 at 10:38







its now working u got an error after i modify the code : with open('output.txt' , "a") as f: f.write('n'.join(str(buffer)) )

– evilcode1
Nov 26 '18 at 10:38















output : ['heyn', 2] just oneline !!

– evilcode1
Nov 26 '18 at 10:38





output : ['heyn', 2] just oneline !!

– evilcode1
Nov 26 '18 at 10:38













rewrite first buffer.append as buffer.append(str(d) + 'n')

– Nick
Nov 26 '18 at 10:40







rewrite first buffer.append as buffer.append(str(d) + 'n')

– Nick
Nov 26 '18 at 10:40















First of all, print in python prints string with 'n' , and join method works only with list strings

– Nick
Nov 26 '18 at 10:42







First of all, print in python prints string with 'n' , and join method works only with list strings

– Nick
Nov 26 '18 at 10:42















so how i can solve this issue ?

– evilcode1
Dec 4 '18 at 16:29





so how i can solve this issue ?

– evilcode1
Dec 4 '18 at 16:29




















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