Find the tangency point where $y = -x$ is tangent to the curve given by $y = x^3 + 6x^2 + 8x$ [closed]
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Find the tangency point where $y = -x$ is tangent to the curve given by $y = x^3 + 6x^2 + 8x$.
I don't know if I expressed myself correctly on the question; English is not
my first language.
derivatives
edited Nov 21 at 3:33
hardmath
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
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closed as off-topic by Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R Nov 21 at 9:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
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Find the tangency point where $y = -x$ is tangent to the curve given by $y = x^3 + 6x^2 + 8x$.
I don't know if I expressed myself correctly on the question; English is not
my first language.
derivatives
edited Nov 21 at 3:33
hardmath
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
closed as off-topic by Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R Nov 21 at 9:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Find the tangency point where $y = -x$ is tangent to the curve given by $y = x^3 + 6x^2 + 8x$.
I don't know if I expressed myself correctly on the question; English is not
my first language.
derivatives
edited Nov 21 at 3:33
hardmath
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Find the tangency point where $y = -x$ is tangent to the curve given by $y = x^3 + 6x^2 + 8x$.
I don't know if I expressed myself correctly on the question; English is not
my first language.
derivatives
derivatives
edited Nov 21 at 3:33
hardmath
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 21 at 3:33
hardmath
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 21 at 3:33
hardmath
28.5k94994
edited Nov 21 at 3:33
hardmath
28.5k94994
edited Nov 21 at 3:33
hardmath
28.5k94994
28.5k94994
asked Nov 21 at 2:38
hawkg2
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 21 at 2:38
hawkg2
1
asked Nov 21 at 2:38
hawkg2
1
1
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
hawkg2 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
closed as off-topic by Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R Nov 21 at 9:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R Nov 21 at 9:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Leucippus, Jean-Claude Arbaut, Rebellos, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32
add a comment |
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32
add a comment |
1 Answer
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First you need to calculate the intersections
$$-x=x^3+6x^2+8x$$
or $$x(x^2+6x+9)=x(x+3)^2=0$$
Now calculate the tangents of the two curves at $x=0$ and $x=-3$. If the derivatives are the same, the two curves are tangent.
answered Nov 21 at 2:51
Andrei
10.1k21025
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
First you need to calculate the intersections
$$-x=x^3+6x^2+8x$$
or $$x(x^2+6x+9)=x(x+3)^2=0$$
Now calculate the tangents of the two curves at $x=0$ and $x=-3$. If the derivatives are the same, the two curves are tangent.
answered Nov 21 at 2:51
Andrei
10.1k21025
add a comment |
up vote
0
down vote
First you need to calculate the intersections
$$-x=x^3+6x^2+8x$$
or $$x(x^2+6x+9)=x(x+3)^2=0$$
Now calculate the tangents of the two curves at $x=0$ and $x=-3$. If the derivatives are the same, the two curves are tangent.
answered Nov 21 at 2:51
Andrei
10.1k21025
add a comment |
up vote
0
down vote
up vote
0
down vote
First you need to calculate the intersections
$$-x=x^3+6x^2+8x$$
or $$x(x^2+6x+9)=x(x+3)^2=0$$
Now calculate the tangents of the two curves at $x=0$ and $x=-3$. If the derivatives are the same, the two curves are tangent.
answered Nov 21 at 2:51
Andrei
10.1k21025
First you need to calculate the intersections
$$-x=x^3+6x^2+8x$$
or $$x(x^2+6x+9)=x(x+3)^2=0$$
Now calculate the tangents of the two curves at $x=0$ and $x=-3$. If the derivatives are the same, the two curves are tangent.
answered Nov 21 at 2:51
Andrei
10.1k21025
answered Nov 21 at 2:51
Andrei
10.1k21025
answered Nov 21 at 2:51
Andrei
10.1k21025
answered Nov 21 at 2:51
Andrei
10.1k21025
10.1k21025
add a comment |
add a comment |
I'm going to include the problem statement from the title into the body of the Question. You should elaborate on your approach to the problem (what you already tried) to avoid having Readers spend unnecessary effort telling you things you already know. For example, if a line and a curve are tangent at a point, what do you know about the derivatives at that point?
– hardmath
Nov 21 at 3:32