Frobenius norm of Fourier matrix
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0
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Fourier matrix is given as
where $omega = e^{-2pi i/N}$
Is there any clever way to calculate Frobenius norm of Fourier matrix? I tried solving it with brute force and got some ugly calculations
linear-algebra matrices matrix-calculus
add a comment |
up vote
0
down vote
favorite
Fourier matrix is given as
where $omega = e^{-2pi i/N}$
Is there any clever way to calculate Frobenius norm of Fourier matrix? I tried solving it with brute force and got some ugly calculations
linear-algebra matrices matrix-calculus
Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Fourier matrix is given as
where $omega = e^{-2pi i/N}$
Is there any clever way to calculate Frobenius norm of Fourier matrix? I tried solving it with brute force and got some ugly calculations
linear-algebra matrices matrix-calculus
Fourier matrix is given as
where $omega = e^{-2pi i/N}$
Is there any clever way to calculate Frobenius norm of Fourier matrix? I tried solving it with brute force and got some ugly calculations
linear-algebra matrices matrix-calculus
linear-algebra matrices matrix-calculus
asked 2 days ago
Studying Optimization
596
596
Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago
add a comment |
Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago
Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago
add a comment |
1 Answer
1
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oldest
votes
up vote
0
down vote
accepted
This is a straightforward computation using any reasonable definition of the Frobenius norm. For instance, we have
$$
|W| = sqrt{operatorname{tr}(W^*W)} = sqrt{operatorname{tr}(I)} = sqrt{N}
$$
where $W^*W = I$ since $W$ is a unitary matrix.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
This is a straightforward computation using any reasonable definition of the Frobenius norm. For instance, we have
$$
|W| = sqrt{operatorname{tr}(W^*W)} = sqrt{operatorname{tr}(I)} = sqrt{N}
$$
where $W^*W = I$ since $W$ is a unitary matrix.
add a comment |
up vote
0
down vote
accepted
This is a straightforward computation using any reasonable definition of the Frobenius norm. For instance, we have
$$
|W| = sqrt{operatorname{tr}(W^*W)} = sqrt{operatorname{tr}(I)} = sqrt{N}
$$
where $W^*W = I$ since $W$ is a unitary matrix.
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
This is a straightforward computation using any reasonable definition of the Frobenius norm. For instance, we have
$$
|W| = sqrt{operatorname{tr}(W^*W)} = sqrt{operatorname{tr}(I)} = sqrt{N}
$$
where $W^*W = I$ since $W$ is a unitary matrix.
This is a straightforward computation using any reasonable definition of the Frobenius norm. For instance, we have
$$
|W| = sqrt{operatorname{tr}(W^*W)} = sqrt{operatorname{tr}(I)} = sqrt{N}
$$
where $W^*W = I$ since $W$ is a unitary matrix.
answered 2 days ago
Omnomnomnom
124k788176
124k788176
add a comment |
add a comment |
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Do you know what’s the formula to compute the Frobenius norm?
– lcv
2 days ago
@lcv, yes I do. You can google it if you want to know
– Studying Optimization
2 days ago
Thank you 😊. So you only need to compute the sum of the absolute values squared of all the entries. Note that each entry has modulus one. Can you take it from here?
– lcv
2 days ago
@lcv, thanks, what I didnt see is that each entry squared has modulus one
– Studying Optimization
2 days ago