Ytukyg

According to that guide: enter link description here

i wrote:

#define DEBUG

#ifdef DEBUG

 #define DEBUG_PRINT(x)  Serial.print (x)

 #define DEBUG_PRINTLN(x)  Serial.println (x)

 #define DEBUG_PRINT_HEX(x)  Serial.print (x, HEX)

 #define DEBUG_PRINT_DEC(x)  Serial.print (x, DEC)

#else

 #define DEBUG_PRINT(x)

 #define DEBUG_PRINTLN(x)

 #define DEBUG_PRINT_HEX(x)

 #define DEBUG_PRINT_DEC(x)

#endif

if i call a function:

uint32_t versiondata;

DEBUG_PRINT_HEX((versiondata>>24) & 0xFF, HEX);

DEBUG_PRINT_DEC((versiondata>>16) & 0xFF, DEC);

uint8_t uidLength;

DEBUG_PRINT_DEC(uidLength, DEC);

the compiler give me:

error: macro "DEBUG_PRINT_DEC" passed 2 arguments, but takes just 1
error: macro "DEBUG_PRINT_HEX" passed 2 arguments, but takes just 1

Someone can explain me why does not works?

Look at the error message. You had defined this macro:

#define DEBUG_PRINT_HEX(x)

This macro want one argument: the x

And you call the macro with two arguments:

DEBUG_PRINT_HEX((versiondata>>24) & 0xFF, HEX);  

1 argument: (versiondata>>24) & 0xFF

2 argument: HEX

Just call the macro like this:

DEBUG_PRINT_HEX((versiondata>>24) & 0xFF);