Ytukyg

my aim is to create mortgage calculator in python. I want it to calculate number of days between now, and fixed time in future. To get number od days, or months between two dates I use datetime , that you can see in my code. My problem is that i can't perform division operation on number of days returned by datetime function, because it is in wrong data type. Is there any option to change date type into integer?

import datetime

from datetime import date

import time





today=datetime.date.today()

d0=date(2021,11,29)

delta=d0-today

print(delta.days)



def diff_month(d1,d2,c1):

    if c1=="monthly":

         a=(d1.year - d2.year) * 12 + d1.month - d2.month

         instalment = 1000000 / a



         return (instalment)

    if c1=="daily":

         a=(d1-d2)

         instalment=1000000/a.days



         return (instalment)









# counter=diff_month(d0,today,"daily")

    #instalment=1000000/counter

    #print(type(counter))

    #print(instalment)

    print(diff_month(d0,today,"daily")) 

Thanks in advance
edit:
Thanks for your advices, finally i do that in this way. The only problem is that monnthly payment is equal everytime, in reality it would not be equal, because number of days in each month is not constant, so i would rather use daily payment than monthly.

Some suggestions:

On the line:

instalment=1000000/counter

You expect counter to contain the number of days. However, diff_month returns the number of months if c1 is "monthly". Fix this. make the function return the number of days in all cases.

The return value from diff_month is of type timedelta. Objects of this type have an attribute called days which is an integer, so you can write:

instalment=1000000/counter.days