Rationalizing complex numbers when the denominator has a (+ 1) added to it











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If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??



(I'm sorry idk how to format the conjugate can someone help edit)










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    If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??



    (I'm sorry idk how to format the conjugate can someone help edit)










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      If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??



      (I'm sorry idk how to format the conjugate can someone help edit)










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      If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??



      (I'm sorry idk how to format the conjugate can someone help edit)







      complex-numbers






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      edited Nov 21 at 10:50









      José Carlos Santos

      141k19111207




      141k19111207










      asked Nov 21 at 10:45









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          If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$






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            If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$






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              If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$






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                If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$






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                If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$







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                answered Nov 21 at 10:50









                José Carlos Santos

                141k19111207




                141k19111207






























                     

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