Rationalizing complex numbers when the denominator has a (+ 1) added to it
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If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??
(I'm sorry idk how to format the conjugate can someone help edit)
complex-numbers
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If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??
(I'm sorry idk how to format the conjugate can someone help edit)
complex-numbers
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??
(I'm sorry idk how to format the conjugate can someone help edit)
complex-numbers
If I were to try and rationalize a complex number like $Z + 2W + 3 over Z + 1$, when I multiply by the conjugate of Z to make the denominator a real number, do I have to write z(conjugate)/z(conjugate) or z(conjugate) + 1/z(conjugate) + 1 or z(conjugate) - 1/z(conjugate) - 1??
(I'm sorry idk how to format the conjugate can someone help edit)
complex-numbers
complex-numbers
edited Nov 21 at 10:50
José Carlos Santos
141k19111207
141k19111207
asked Nov 21 at 10:45
ming
282
282
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If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$
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1 Answer
1
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$
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up vote
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If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$
add a comment |
up vote
1
down vote
up vote
1
down vote
If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$
If $Z,Winmathbb{C}$ (and $Zneq-1$) and if you wish to express $dfrac{Z+2W+3}{Z+1}$ has a quotient whose denominator is a real number, the natural option consists in multiplying both numerator and denominator with $overline{Z+1}$, thereby getting$$frac{Z+2W+3}{Z+1}=frac{(Z+2W+3)left(overline{Z+1}right)}{(Z+1)left(overline{Z+1}right)}=frac{(Z+2W+3)left(overline Z+1right)}{lvert Z+1rvert^2}.$$
answered Nov 21 at 10:50
José Carlos Santos
141k19111207
141k19111207
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