How to prove associativity of lattice?
up vote
1
down vote
favorite
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
add a comment |
up vote
1
down vote
favorite
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
discrete-mathematics
asked Nov 26 at 18:32
Amit
1398
1398
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3014727%2fhow-to-prove-associativity-of-lattice%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
add a comment |
up vote
1
down vote
accepted
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
edited Nov 26 at 19:53
answered Nov 26 at 19:21
Kelly Shepphard
2298
2298
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3014727%2fhow-to-prove-associativity-of-lattice%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown