Robot Framework - TypeError: string indices must be integers When Parsing Json
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0
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I am trying to parse an array of json, But I am getting the following error
TypeError: string indices must be integers
Json:
{
'locationId': 'location1',
'name': 'Name',
'type': 'Ward',
'patientId': None,
'children': [{
'locationId': 'location2',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': [{
'locationId': 'location3',
'name': 'Name',
'type': 'HospitalGroup',
'patientId': None,
'children': None
}]
}, {
'locationId': 'location4',
'name': 'Name',
'type': 'Hospital',
'patientId': None,
'children': None
}, {
'locationId': 'location5',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location6',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location27',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}]
}
I am trying to the get all the locationId values and store the values one by one inside a list.
Here is what I am doing
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
I have also tried this
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['children'][0]['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
But I am getting the same error.
The test is failing on this line ${locationId}= set variable ${item['locationId']}
Any help would be apprectiated.
json testing robotframework
add a comment |
up vote
0
down vote
favorite
I am trying to parse an array of json, But I am getting the following error
TypeError: string indices must be integers
Json:
{
'locationId': 'location1',
'name': 'Name',
'type': 'Ward',
'patientId': None,
'children': [{
'locationId': 'location2',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': [{
'locationId': 'location3',
'name': 'Name',
'type': 'HospitalGroup',
'patientId': None,
'children': None
}]
}, {
'locationId': 'location4',
'name': 'Name',
'type': 'Hospital',
'patientId': None,
'children': None
}, {
'locationId': 'location5',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location6',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location27',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}]
}
I am trying to the get all the locationId values and store the values one by one inside a list.
Here is what I am doing
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
I have also tried this
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['children'][0]['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
But I am getting the same error.
The test is failing on this line ${locationId}= set variable ${item['locationId']}
Any help would be apprectiated.
json testing robotframework
Can you check with aLog Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.
– A. Kootstra
Nov 20 at 13:31
@A.Kootstra I have changed the${item['locationId']}
to${item["locationId"]}
and now i am able to find only the first location value
– Wojtek T
Nov 20 at 13:39
The format isLog Many ${Location_Json_List}
Note the$
– A. Kootstra
Nov 20 at 13:40
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
Apply theLog Many
to the children and just loop through them.
– A. Kootstra
Nov 20 at 14:01
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am trying to parse an array of json, But I am getting the following error
TypeError: string indices must be integers
Json:
{
'locationId': 'location1',
'name': 'Name',
'type': 'Ward',
'patientId': None,
'children': [{
'locationId': 'location2',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': [{
'locationId': 'location3',
'name': 'Name',
'type': 'HospitalGroup',
'patientId': None,
'children': None
}]
}, {
'locationId': 'location4',
'name': 'Name',
'type': 'Hospital',
'patientId': None,
'children': None
}, {
'locationId': 'location5',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location6',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location27',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}]
}
I am trying to the get all the locationId values and store the values one by one inside a list.
Here is what I am doing
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
I have also tried this
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['children'][0]['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
But I am getting the same error.
The test is failing on this line ${locationId}= set variable ${item['locationId']}
Any help would be apprectiated.
json testing robotframework
I am trying to parse an array of json, But I am getting the following error
TypeError: string indices must be integers
Json:
{
'locationId': 'location1',
'name': 'Name',
'type': 'Ward',
'patientId': None,
'children': [{
'locationId': 'location2',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': [{
'locationId': 'location3',
'name': 'Name',
'type': 'HospitalGroup',
'patientId': None,
'children': None
}]
}, {
'locationId': 'location4',
'name': 'Name',
'type': 'Hospital',
'patientId': None,
'children': None
}, {
'locationId': 'location5',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location6',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}, {
'locationId': 'location27',
'name': 'Name',
'type': 'Bed',
'patientId': None,
'children': None
}]
}
I am trying to the get all the locationId values and store the values one by one inside a list.
Here is what I am doing
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
I have also tried this
@{locationIds}= create list
:FOR ${item} IN @{Location_Json}
${locationId}= set variable ${item['children'][0]['locationId']}
log ${locationId}
append to list ${locationIds} '${locationId}'
But I am getting the same error.
The test is failing on this line ${locationId}= set variable ${item['locationId']}
Any help would be apprectiated.
json testing robotframework
json testing robotframework
edited Nov 20 at 13:55
asked Nov 20 at 11:41
Wojtek T
1,128422
1,128422
Can you check with aLog Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.
– A. Kootstra
Nov 20 at 13:31
@A.Kootstra I have changed the${item['locationId']}
to${item["locationId"]}
and now i am able to find only the first location value
– Wojtek T
Nov 20 at 13:39
The format isLog Many ${Location_Json_List}
Note the$
– A. Kootstra
Nov 20 at 13:40
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
Apply theLog Many
to the children and just loop through them.
– A. Kootstra
Nov 20 at 14:01
add a comment |
Can you check with aLog Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.
– A. Kootstra
Nov 20 at 13:31
@A.Kootstra I have changed the${item['locationId']}
to${item["locationId"]}
and now i am able to find only the first location value
– Wojtek T
Nov 20 at 13:39
The format isLog Many ${Location_Json_List}
Note the$
– A. Kootstra
Nov 20 at 13:40
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
Apply theLog Many
to the children and just loop through them.
– A. Kootstra
Nov 20 at 14:01
Can you check with a
Log Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.– A. Kootstra
Nov 20 at 13:31
Can you check with a
Log Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.– A. Kootstra
Nov 20 at 13:31
@A.Kootstra I have changed the
${item['locationId']}
to ${item["locationId"]}
and now i am able to find only the first location value– Wojtek T
Nov 20 at 13:39
@A.Kootstra I have changed the
${item['locationId']}
to ${item["locationId"]}
and now i am able to find only the first location value– Wojtek T
Nov 20 at 13:39
The format is
Log Many ${Location_Json_List}
Note the $
– A. Kootstra
Nov 20 at 13:40
The format is
Log Many ${Location_Json_List}
Note the $
– A. Kootstra
Nov 20 at 13:40
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
Apply the
Log Many
to the children and just loop through them.– A. Kootstra
Nov 20 at 14:01
Apply the
Log Many
to the children and just loop through them.– A. Kootstra
Nov 20 at 14:01
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
If the content of the var ${Location_Json}
is indeed the json sample you've put above, that would explain the exception "string indices must be integers".
The json you are working with is a dictionary (not a list); thus, in this loop:
:FOR ${item} IN @{Location_Json}
, the value of ${item}
is going to be the keys in the in the dictionary - e.g. locationId
, name
, etc of the top-level dictionary.
If you are interested in the "locationId" of the "children" subdict, that will do it - iteration over the "children" items:
:FOR ${item} IN @{Location_Json['children']}
On each iteration the ${item}
is going to be one of the sub-dicts in "children", and you can get its "locationId"
${locationId}= set variable ${item['locationId']}
Not related to your issue, put please do not do that:
append to list ${locationIds} '${locationId}'
Do not put the value of ${locationId}
inside the single quotes - what will happen is those quotes will now be a part of the list member.
Say, the value of ${locationId}
is
location5
with those quotes surrounding it, it will end up as
'location5'
I don't think that's your goal; with these extra quotes, this will fail:
Should Be Equal As Strings location5 ${locationIds[3]} # because locationIds[3] will have the extra quotes
Thanks for the answer, that helped me solve my problem, also nice spot with the'${locationId}'
thanks
– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get thelocation3
value
– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that hadlocation3
as value had something in thechildren
key - you would then want to get the valuelocation3.1
out from it too, I guess.That's a different problem from the one you've put in this question.
– Todor
Nov 21 at 9:57
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
If the content of the var ${Location_Json}
is indeed the json sample you've put above, that would explain the exception "string indices must be integers".
The json you are working with is a dictionary (not a list); thus, in this loop:
:FOR ${item} IN @{Location_Json}
, the value of ${item}
is going to be the keys in the in the dictionary - e.g. locationId
, name
, etc of the top-level dictionary.
If you are interested in the "locationId" of the "children" subdict, that will do it - iteration over the "children" items:
:FOR ${item} IN @{Location_Json['children']}
On each iteration the ${item}
is going to be one of the sub-dicts in "children", and you can get its "locationId"
${locationId}= set variable ${item['locationId']}
Not related to your issue, put please do not do that:
append to list ${locationIds} '${locationId}'
Do not put the value of ${locationId}
inside the single quotes - what will happen is those quotes will now be a part of the list member.
Say, the value of ${locationId}
is
location5
with those quotes surrounding it, it will end up as
'location5'
I don't think that's your goal; with these extra quotes, this will fail:
Should Be Equal As Strings location5 ${locationIds[3]} # because locationIds[3] will have the extra quotes
Thanks for the answer, that helped me solve my problem, also nice spot with the'${locationId}'
thanks
– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get thelocation3
value
– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that hadlocation3
as value had something in thechildren
key - you would then want to get the valuelocation3.1
out from it too, I guess.That's a different problem from the one you've put in this question.
– Todor
Nov 21 at 9:57
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
add a comment |
up vote
1
down vote
accepted
If the content of the var ${Location_Json}
is indeed the json sample you've put above, that would explain the exception "string indices must be integers".
The json you are working with is a dictionary (not a list); thus, in this loop:
:FOR ${item} IN @{Location_Json}
, the value of ${item}
is going to be the keys in the in the dictionary - e.g. locationId
, name
, etc of the top-level dictionary.
If you are interested in the "locationId" of the "children" subdict, that will do it - iteration over the "children" items:
:FOR ${item} IN @{Location_Json['children']}
On each iteration the ${item}
is going to be one of the sub-dicts in "children", and you can get its "locationId"
${locationId}= set variable ${item['locationId']}
Not related to your issue, put please do not do that:
append to list ${locationIds} '${locationId}'
Do not put the value of ${locationId}
inside the single quotes - what will happen is those quotes will now be a part of the list member.
Say, the value of ${locationId}
is
location5
with those quotes surrounding it, it will end up as
'location5'
I don't think that's your goal; with these extra quotes, this will fail:
Should Be Equal As Strings location5 ${locationIds[3]} # because locationIds[3] will have the extra quotes
Thanks for the answer, that helped me solve my problem, also nice spot with the'${locationId}'
thanks
– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get thelocation3
value
– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that hadlocation3
as value had something in thechildren
key - you would then want to get the valuelocation3.1
out from it too, I guess.That's a different problem from the one you've put in this question.
– Todor
Nov 21 at 9:57
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
If the content of the var ${Location_Json}
is indeed the json sample you've put above, that would explain the exception "string indices must be integers".
The json you are working with is a dictionary (not a list); thus, in this loop:
:FOR ${item} IN @{Location_Json}
, the value of ${item}
is going to be the keys in the in the dictionary - e.g. locationId
, name
, etc of the top-level dictionary.
If you are interested in the "locationId" of the "children" subdict, that will do it - iteration over the "children" items:
:FOR ${item} IN @{Location_Json['children']}
On each iteration the ${item}
is going to be one of the sub-dicts in "children", and you can get its "locationId"
${locationId}= set variable ${item['locationId']}
Not related to your issue, put please do not do that:
append to list ${locationIds} '${locationId}'
Do not put the value of ${locationId}
inside the single quotes - what will happen is those quotes will now be a part of the list member.
Say, the value of ${locationId}
is
location5
with those quotes surrounding it, it will end up as
'location5'
I don't think that's your goal; with these extra quotes, this will fail:
Should Be Equal As Strings location5 ${locationIds[3]} # because locationIds[3] will have the extra quotes
If the content of the var ${Location_Json}
is indeed the json sample you've put above, that would explain the exception "string indices must be integers".
The json you are working with is a dictionary (not a list); thus, in this loop:
:FOR ${item} IN @{Location_Json}
, the value of ${item}
is going to be the keys in the in the dictionary - e.g. locationId
, name
, etc of the top-level dictionary.
If you are interested in the "locationId" of the "children" subdict, that will do it - iteration over the "children" items:
:FOR ${item} IN @{Location_Json['children']}
On each iteration the ${item}
is going to be one of the sub-dicts in "children", and you can get its "locationId"
${locationId}= set variable ${item['locationId']}
Not related to your issue, put please do not do that:
append to list ${locationIds} '${locationId}'
Do not put the value of ${locationId}
inside the single quotes - what will happen is those quotes will now be a part of the list member.
Say, the value of ${locationId}
is
location5
with those quotes surrounding it, it will end up as
'location5'
I don't think that's your goal; with these extra quotes, this will fail:
Should Be Equal As Strings location5 ${locationIds[3]} # because locationIds[3] will have the extra quotes
answered Nov 20 at 18:51
Todor
5,2032033
5,2032033
Thanks for the answer, that helped me solve my problem, also nice spot with the'${locationId}'
thanks
– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get thelocation3
value
– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that hadlocation3
as value had something in thechildren
key - you would then want to get the valuelocation3.1
out from it too, I guess.That's a different problem from the one you've put in this question.
– Todor
Nov 21 at 9:57
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
add a comment |
Thanks for the answer, that helped me solve my problem, also nice spot with the'${locationId}'
thanks
– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get thelocation3
value
– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that hadlocation3
as value had something in thechildren
key - you would then want to get the valuelocation3.1
out from it too, I guess.That's a different problem from the one you've put in this question.
– Todor
Nov 21 at 9:57
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
Thanks for the answer, that helped me solve my problem, also nice spot with the
'${locationId}'
thanks– Wojtek T
Nov 21 at 9:40
Thanks for the answer, that helped me solve my problem, also nice spot with the
'${locationId}'
thanks– Wojtek T
Nov 21 at 9:40
I am able to get all the values one level down but i cannot get the
location3
value– Wojtek T
Nov 21 at 9:46
I am able to get all the values one level down but i cannot get the
location3
value– Wojtek T
Nov 21 at 9:46
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that had
location3
as value had something in the children
key - you would then want to get the value location3.1
out from it too, I guess.That's a different problem from the one you've put in this question.– Todor
Nov 21 at 9:57
Sounds like you need a general solution for "get all values of the key X in all sub-dictionaries that might be present in a list/dictionary", where X is "locationId" for you. Imagine the node that had
location3
as value had something in the children
key - you would then want to get the value location3.1
out from it too, I guess.That's a different problem from the one you've put in this question.– Todor
Nov 21 at 9:57
1
1
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
That's okay i think i will create a Custom Keyword for that, thanks
– Wojtek T
Nov 21 at 9:58
add a comment |
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Can you check with a
Log Many
if your in-memory structure is indeed what you expect it is. It sounds to me that there is a list that you're trying to access using a string.– A. Kootstra
Nov 20 at 13:31
@A.Kootstra I have changed the
${item['locationId']}
to${item["locationId"]}
and now i am able to find only the first location value– Wojtek T
Nov 20 at 13:39
The format is
Log Many ${Location_Json_List}
Note the$
– A. Kootstra
Nov 20 at 13:40
@A.Kootstra It is indeed the same structure as above json
– Wojtek T
Nov 20 at 13:44
Apply the
Log Many
to the children and just loop through them.– A. Kootstra
Nov 20 at 14:01