How to speed up python instance initialization for millions of objects?
up vote
2
down vote
favorite
I have defined a python class
named Edge
as follows:
class Edge:
def __init__(self):
self.node1 = 0
self.node2 = 0
self.weight = 0
Now I have to create approximately 10^6 to 10^7 instances of Edge using:
edges=
for (i,j,w) in ijw:
edge = Edge()
edge.node1 = i
edge.node2 = j
edge.weight = w
edges.append(edge)
I took me approximately 2 seconds in Desktop. Is there any faster way to do?
python performance instance
add a comment |
up vote
2
down vote
favorite
I have defined a python class
named Edge
as follows:
class Edge:
def __init__(self):
self.node1 = 0
self.node2 = 0
self.weight = 0
Now I have to create approximately 10^6 to 10^7 instances of Edge using:
edges=
for (i,j,w) in ijw:
edge = Edge()
edge.node1 = i
edge.node2 = j
edge.weight = w
edges.append(edge)
I took me approximately 2 seconds in Desktop. Is there any faster way to do?
python performance instance
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have defined a python class
named Edge
as follows:
class Edge:
def __init__(self):
self.node1 = 0
self.node2 = 0
self.weight = 0
Now I have to create approximately 10^6 to 10^7 instances of Edge using:
edges=
for (i,j,w) in ijw:
edge = Edge()
edge.node1 = i
edge.node2 = j
edge.weight = w
edges.append(edge)
I took me approximately 2 seconds in Desktop. Is there any faster way to do?
python performance instance
I have defined a python class
named Edge
as follows:
class Edge:
def __init__(self):
self.node1 = 0
self.node2 = 0
self.weight = 0
Now I have to create approximately 10^6 to 10^7 instances of Edge using:
edges=
for (i,j,w) in ijw:
edge = Edge()
edge.node1 = i
edge.node2 = j
edge.weight = w
edges.append(edge)
I took me approximately 2 seconds in Desktop. Is there any faster way to do?
python performance instance
python performance instance
edited Nov 20 at 22:16
Martijn Pieters♦
696k12924052245
696k12924052245
asked Nov 20 at 7:52
ted930511
17312
17312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
8
down vote
accepted
You can't make it much faster, but I certainly would use __slots__
to save on memory allocations. Also make it possible to pass in the attribute values when creating the instance:
class Edge:
__slots__ = ('node1', 'node2', 'weight')
def __init__(self, node1=0, node2=0, weight=0):
self.node1 = node1
self.node2 = node2
self.weight = weight
With the updated __init__
you can use a list comprehension:
edges = [Edge(*args) for args in ijw]
Together these can shave off a decent amount of time creating the objects, roughly halve the time needed.
Comparison creating 1 million objects; the setup:
>>> from random import randrange
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 6)]
>>> class OrigEdge:
... def __init__(self):
... self.node1 = 0
... self.node2 = 0
... self.weight = 0
...
>>> origloop = '''
... edges=
... for (i,j,w) in ijw:
... edge = Edge()
... edge.node1 = i
... edge.node2 = j
... edge.weight = w
... edges.append(edge)
... '''
>>> class SlotsEdge:
... __slots__ = ('node1', 'node2', 'weight')
... def __init__(self, node1=0, node2=0, weight=0):
... self.node1 = node1
... self.node2 = node2
... self.weight = weight
...
>>> listcomploop = '''[Edge(*args) for args in ijw]'''
and the timings:
>>> from timeit import Timer
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
722.1121070033405
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
386.6706900007557
That's nearly 2 times as fast.
Increasing the random input list to 10^7 items, and the timing difference holds:
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 7)]
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count)
7.183759553998243
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count)
3.8709938440006226
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without__slots__
but with the list comp, you'd get the same timings.
– Martijn Pieters♦
Nov 20 at 10:08
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
|
show 16 more comments
up vote
1
down vote
Another option is to skip the Edge
class and implement the edges via a table, or adjacency matrix.
E.g.
A = create_adjacency_graph(ijw) # Implement to return a IxJ (sparse?) matrix of weights
edge_a_weight = A[3, 56]
edge_b_weight = A[670, 1023]
# etc...
This does remove some flexibility though, but should be quite fast both to create and use.
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
accepted
You can't make it much faster, but I certainly would use __slots__
to save on memory allocations. Also make it possible to pass in the attribute values when creating the instance:
class Edge:
__slots__ = ('node1', 'node2', 'weight')
def __init__(self, node1=0, node2=0, weight=0):
self.node1 = node1
self.node2 = node2
self.weight = weight
With the updated __init__
you can use a list comprehension:
edges = [Edge(*args) for args in ijw]
Together these can shave off a decent amount of time creating the objects, roughly halve the time needed.
Comparison creating 1 million objects; the setup:
>>> from random import randrange
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 6)]
>>> class OrigEdge:
... def __init__(self):
... self.node1 = 0
... self.node2 = 0
... self.weight = 0
...
>>> origloop = '''
... edges=
... for (i,j,w) in ijw:
... edge = Edge()
... edge.node1 = i
... edge.node2 = j
... edge.weight = w
... edges.append(edge)
... '''
>>> class SlotsEdge:
... __slots__ = ('node1', 'node2', 'weight')
... def __init__(self, node1=0, node2=0, weight=0):
... self.node1 = node1
... self.node2 = node2
... self.weight = weight
...
>>> listcomploop = '''[Edge(*args) for args in ijw]'''
and the timings:
>>> from timeit import Timer
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
722.1121070033405
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
386.6706900007557
That's nearly 2 times as fast.
Increasing the random input list to 10^7 items, and the timing difference holds:
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 7)]
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count)
7.183759553998243
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count)
3.8709938440006226
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without__slots__
but with the list comp, you'd get the same timings.
– Martijn Pieters♦
Nov 20 at 10:08
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
|
show 16 more comments
up vote
8
down vote
accepted
You can't make it much faster, but I certainly would use __slots__
to save on memory allocations. Also make it possible to pass in the attribute values when creating the instance:
class Edge:
__slots__ = ('node1', 'node2', 'weight')
def __init__(self, node1=0, node2=0, weight=0):
self.node1 = node1
self.node2 = node2
self.weight = weight
With the updated __init__
you can use a list comprehension:
edges = [Edge(*args) for args in ijw]
Together these can shave off a decent amount of time creating the objects, roughly halve the time needed.
Comparison creating 1 million objects; the setup:
>>> from random import randrange
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 6)]
>>> class OrigEdge:
... def __init__(self):
... self.node1 = 0
... self.node2 = 0
... self.weight = 0
...
>>> origloop = '''
... edges=
... for (i,j,w) in ijw:
... edge = Edge()
... edge.node1 = i
... edge.node2 = j
... edge.weight = w
... edges.append(edge)
... '''
>>> class SlotsEdge:
... __slots__ = ('node1', 'node2', 'weight')
... def __init__(self, node1=0, node2=0, weight=0):
... self.node1 = node1
... self.node2 = node2
... self.weight = weight
...
>>> listcomploop = '''[Edge(*args) for args in ijw]'''
and the timings:
>>> from timeit import Timer
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
722.1121070033405
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
386.6706900007557
That's nearly 2 times as fast.
Increasing the random input list to 10^7 items, and the timing difference holds:
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 7)]
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count)
7.183759553998243
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count)
3.8709938440006226
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without__slots__
but with the list comp, you'd get the same timings.
– Martijn Pieters♦
Nov 20 at 10:08
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
|
show 16 more comments
up vote
8
down vote
accepted
up vote
8
down vote
accepted
You can't make it much faster, but I certainly would use __slots__
to save on memory allocations. Also make it possible to pass in the attribute values when creating the instance:
class Edge:
__slots__ = ('node1', 'node2', 'weight')
def __init__(self, node1=0, node2=0, weight=0):
self.node1 = node1
self.node2 = node2
self.weight = weight
With the updated __init__
you can use a list comprehension:
edges = [Edge(*args) for args in ijw]
Together these can shave off a decent amount of time creating the objects, roughly halve the time needed.
Comparison creating 1 million objects; the setup:
>>> from random import randrange
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 6)]
>>> class OrigEdge:
... def __init__(self):
... self.node1 = 0
... self.node2 = 0
... self.weight = 0
...
>>> origloop = '''
... edges=
... for (i,j,w) in ijw:
... edge = Edge()
... edge.node1 = i
... edge.node2 = j
... edge.weight = w
... edges.append(edge)
... '''
>>> class SlotsEdge:
... __slots__ = ('node1', 'node2', 'weight')
... def __init__(self, node1=0, node2=0, weight=0):
... self.node1 = node1
... self.node2 = node2
... self.weight = weight
...
>>> listcomploop = '''[Edge(*args) for args in ijw]'''
and the timings:
>>> from timeit import Timer
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
722.1121070033405
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
386.6706900007557
That's nearly 2 times as fast.
Increasing the random input list to 10^7 items, and the timing difference holds:
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 7)]
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count)
7.183759553998243
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count)
3.8709938440006226
You can't make it much faster, but I certainly would use __slots__
to save on memory allocations. Also make it possible to pass in the attribute values when creating the instance:
class Edge:
__slots__ = ('node1', 'node2', 'weight')
def __init__(self, node1=0, node2=0, weight=0):
self.node1 = node1
self.node2 = node2
self.weight = weight
With the updated __init__
you can use a list comprehension:
edges = [Edge(*args) for args in ijw]
Together these can shave off a decent amount of time creating the objects, roughly halve the time needed.
Comparison creating 1 million objects; the setup:
>>> from random import randrange
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 6)]
>>> class OrigEdge:
... def __init__(self):
... self.node1 = 0
... self.node2 = 0
... self.weight = 0
...
>>> origloop = '''
... edges=
... for (i,j,w) in ijw:
... edge = Edge()
... edge.node1 = i
... edge.node2 = j
... edge.weight = w
... edges.append(edge)
... '''
>>> class SlotsEdge:
... __slots__ = ('node1', 'node2', 'weight')
... def __init__(self, node1=0, node2=0, weight=0):
... self.node1 = node1
... self.node2 = node2
... self.weight = weight
...
>>> listcomploop = '''[Edge(*args) for args in ijw]'''
and the timings:
>>> from timeit import Timer
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
722.1121070033405
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count) * 1000 # milliseconds
386.6706900007557
That's nearly 2 times as fast.
Increasing the random input list to 10^7 items, and the timing difference holds:
>>> ijw = [(randrange(100), randrange(100), randrange(1000)) for _ in range(10 ** 7)]
>>> count, total = Timer(origloop, 'from __main__ import OrigEdge as Edge, ijw').autorange()
>>> (total / count)
7.183759553998243
>>> count, total = Timer(listcomploop, 'from __main__ import SlotsEdge as Edge, ijw').autorange()
>>> (total / count)
3.8709938440006226
edited Nov 20 at 8:53
answered Nov 20 at 7:57
Martijn Pieters♦
696k12924052245
696k12924052245
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without__slots__
but with the list comp, you'd get the same timings.
– Martijn Pieters♦
Nov 20 at 10:08
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
|
show 16 more comments
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without__slots__
but with the list comp, you'd get the same timings.
– Martijn Pieters♦
Nov 20 at 10:08
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Thanks, I will try and test how much it improves!
– ted930511
Nov 20 at 8:05
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
Will dataclasses do anything for instantiation speed?
– Tomalak
Nov 20 at 8:08
1
1
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without
__slots__
but with the list comp, you'd get the same timings.– Martijn Pieters♦
Nov 20 at 10:08
@Tomalak: your dataclass code confirms my timings. It's the same speed as the slots example (the timings are the same within a margin). I may have misunderstood what your 75% was relative to here; the non-slots dataclass speedup is purely due to the list comprehension, not due to you using a dataclass. If you used my class without
__slots__
but with the list comp, you'd get the same timings.– Martijn Pieters♦
Nov 20 at 10:08
1
1
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
Thanks for clearing that up!
– Tomalak
Nov 20 at 10:17
1
1
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
@martineau: See gist.github.com/mjpieters/a4d01024f50d56210dceefc1acdbd487 for timings and memory footprint.
– Martijn Pieters♦
Nov 20 at 10:29
|
show 16 more comments
up vote
1
down vote
Another option is to skip the Edge
class and implement the edges via a table, or adjacency matrix.
E.g.
A = create_adjacency_graph(ijw) # Implement to return a IxJ (sparse?) matrix of weights
edge_a_weight = A[3, 56]
edge_b_weight = A[670, 1023]
# etc...
This does remove some flexibility though, but should be quite fast both to create and use.
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
add a comment |
up vote
1
down vote
Another option is to skip the Edge
class and implement the edges via a table, or adjacency matrix.
E.g.
A = create_adjacency_graph(ijw) # Implement to return a IxJ (sparse?) matrix of weights
edge_a_weight = A[3, 56]
edge_b_weight = A[670, 1023]
# etc...
This does remove some flexibility though, but should be quite fast both to create and use.
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
add a comment |
up vote
1
down vote
up vote
1
down vote
Another option is to skip the Edge
class and implement the edges via a table, or adjacency matrix.
E.g.
A = create_adjacency_graph(ijw) # Implement to return a IxJ (sparse?) matrix of weights
edge_a_weight = A[3, 56]
edge_b_weight = A[670, 1023]
# etc...
This does remove some flexibility though, but should be quite fast both to create and use.
Another option is to skip the Edge
class and implement the edges via a table, or adjacency matrix.
E.g.
A = create_adjacency_graph(ijw) # Implement to return a IxJ (sparse?) matrix of weights
edge_a_weight = A[3, 56]
edge_b_weight = A[670, 1023]
# etc...
This does remove some flexibility though, but should be quite fast both to create and use.
answered Nov 20 at 8:01
Hannes Ovrén
13k44663
13k44663
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
add a comment |
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
In my case, I will pass them into other functions, in order to improve code readability, I prefer using class.
– ted930511
Nov 20 at 8:03
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
@ted930511 : To run any algorithm on huge data, you must think at more efficient data structure/language, unless it is a prototype.
– B. M.
Nov 20 at 8:11
add a comment |
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