How to convert timestamp to numbers
Suppose I have a table like this:
Id Types Timestamp
1 A 2014-02-04 00:00:00
2 A 2014-02-05 00:00:00
1 A 2014-02-05 03:59:00
3 C 2014-05-06 03:59:00
1 B 2014-02-04 03:00:00
2 D 2014-02-05 00:40:00
I would like the output to be like this:
Id 1 2 3 4 5 etc
1 A B A C D ...
2 A D NULL NULL NULL
3 C NULL NULL NULL NULL
Is it possible to make time expresses the type's order.
Thanks for any hints.
postgresql
add a comment |
Suppose I have a table like this:
Id Types Timestamp
1 A 2014-02-04 00:00:00
2 A 2014-02-05 00:00:00
1 A 2014-02-05 03:59:00
3 C 2014-05-06 03:59:00
1 B 2014-02-04 03:00:00
2 D 2014-02-05 00:40:00
I would like the output to be like this:
Id 1 2 3 4 5 etc
1 A B A C D ...
2 A D NULL NULL NULL
3 C NULL NULL NULL NULL
Is it possible to make time expresses the type's order.
Thanks for any hints.
postgresql
add a comment |
Suppose I have a table like this:
Id Types Timestamp
1 A 2014-02-04 00:00:00
2 A 2014-02-05 00:00:00
1 A 2014-02-05 03:59:00
3 C 2014-05-06 03:59:00
1 B 2014-02-04 03:00:00
2 D 2014-02-05 00:40:00
I would like the output to be like this:
Id 1 2 3 4 5 etc
1 A B A C D ...
2 A D NULL NULL NULL
3 C NULL NULL NULL NULL
Is it possible to make time expresses the type's order.
Thanks for any hints.
postgresql
Suppose I have a table like this:
Id Types Timestamp
1 A 2014-02-04 00:00:00
2 A 2014-02-05 00:00:00
1 A 2014-02-05 03:59:00
3 C 2014-05-06 03:59:00
1 B 2014-02-04 03:00:00
2 D 2014-02-05 00:40:00
I would like the output to be like this:
Id 1 2 3 4 5 etc
1 A B A C D ...
2 A D NULL NULL NULL
3 C NULL NULL NULL NULL
Is it possible to make time expresses the type's order.
Thanks for any hints.
postgresql
postgresql
asked Nov 22 '18 at 15:16
H.EH.E
61
61
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Preliminary comments:
- SQL can only return a predefined number of columns returned. IMHO, the best you can get is values concatenated in an array.
- I have name your input table
MyTable
and renamed the columnTimestamp
toMyTimestamp
to avoid conflict with the corresponding type's keyword. - You have put C and D in the 1 row of your output. I will treat it as a typo (they are not on ID = 1)
-
WITH RECURSIVE ConcatAndOrder(ID, MyResult, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, ARRAY[Type], RowNumForOrder, RowCountForOrder
FROM IndexedTable
WHERE RowNumForOrder = 1
UNION ALL
SELECT I.ID, MyResult || I.Type, I.RowNumForOrder, I.RowCountForOrder
FROM IndexedTable I
JOIN ConcatAndOrder C on I.ID = C.ID and I.RowNumForOrder = C.RowNumForOrder + 1
), IndexedTable(ID, Type, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, Type,
row_number() OVER (PARTITION BY ID ORDER BY MyTimestamp),
count(*) OVER (PARTITION BY ID)
FROM MyTable
)
SELECT ID, MyResult
FROM ConcatAndOrder
WHERE RowNumForOrder = RowCountForOrder
ORDER BY ID
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433927%2fhow-to-convert-timestamp-to-numbers%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Preliminary comments:
- SQL can only return a predefined number of columns returned. IMHO, the best you can get is values concatenated in an array.
- I have name your input table
MyTable
and renamed the columnTimestamp
toMyTimestamp
to avoid conflict with the corresponding type's keyword. - You have put C and D in the 1 row of your output. I will treat it as a typo (they are not on ID = 1)
-
WITH RECURSIVE ConcatAndOrder(ID, MyResult, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, ARRAY[Type], RowNumForOrder, RowCountForOrder
FROM IndexedTable
WHERE RowNumForOrder = 1
UNION ALL
SELECT I.ID, MyResult || I.Type, I.RowNumForOrder, I.RowCountForOrder
FROM IndexedTable I
JOIN ConcatAndOrder C on I.ID = C.ID and I.RowNumForOrder = C.RowNumForOrder + 1
), IndexedTable(ID, Type, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, Type,
row_number() OVER (PARTITION BY ID ORDER BY MyTimestamp),
count(*) OVER (PARTITION BY ID)
FROM MyTable
)
SELECT ID, MyResult
FROM ConcatAndOrder
WHERE RowNumForOrder = RowCountForOrder
ORDER BY ID
add a comment |
Preliminary comments:
- SQL can only return a predefined number of columns returned. IMHO, the best you can get is values concatenated in an array.
- I have name your input table
MyTable
and renamed the columnTimestamp
toMyTimestamp
to avoid conflict with the corresponding type's keyword. - You have put C and D in the 1 row of your output. I will treat it as a typo (they are not on ID = 1)
-
WITH RECURSIVE ConcatAndOrder(ID, MyResult, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, ARRAY[Type], RowNumForOrder, RowCountForOrder
FROM IndexedTable
WHERE RowNumForOrder = 1
UNION ALL
SELECT I.ID, MyResult || I.Type, I.RowNumForOrder, I.RowCountForOrder
FROM IndexedTable I
JOIN ConcatAndOrder C on I.ID = C.ID and I.RowNumForOrder = C.RowNumForOrder + 1
), IndexedTable(ID, Type, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, Type,
row_number() OVER (PARTITION BY ID ORDER BY MyTimestamp),
count(*) OVER (PARTITION BY ID)
FROM MyTable
)
SELECT ID, MyResult
FROM ConcatAndOrder
WHERE RowNumForOrder = RowCountForOrder
ORDER BY ID
add a comment |
Preliminary comments:
- SQL can only return a predefined number of columns returned. IMHO, the best you can get is values concatenated in an array.
- I have name your input table
MyTable
and renamed the columnTimestamp
toMyTimestamp
to avoid conflict with the corresponding type's keyword. - You have put C and D in the 1 row of your output. I will treat it as a typo (they are not on ID = 1)
-
WITH RECURSIVE ConcatAndOrder(ID, MyResult, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, ARRAY[Type], RowNumForOrder, RowCountForOrder
FROM IndexedTable
WHERE RowNumForOrder = 1
UNION ALL
SELECT I.ID, MyResult || I.Type, I.RowNumForOrder, I.RowCountForOrder
FROM IndexedTable I
JOIN ConcatAndOrder C on I.ID = C.ID and I.RowNumForOrder = C.RowNumForOrder + 1
), IndexedTable(ID, Type, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, Type,
row_number() OVER (PARTITION BY ID ORDER BY MyTimestamp),
count(*) OVER (PARTITION BY ID)
FROM MyTable
)
SELECT ID, MyResult
FROM ConcatAndOrder
WHERE RowNumForOrder = RowCountForOrder
ORDER BY ID
Preliminary comments:
- SQL can only return a predefined number of columns returned. IMHO, the best you can get is values concatenated in an array.
- I have name your input table
MyTable
and renamed the columnTimestamp
toMyTimestamp
to avoid conflict with the corresponding type's keyword. - You have put C and D in the 1 row of your output. I will treat it as a typo (they are not on ID = 1)
-
WITH RECURSIVE ConcatAndOrder(ID, MyResult, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, ARRAY[Type], RowNumForOrder, RowCountForOrder
FROM IndexedTable
WHERE RowNumForOrder = 1
UNION ALL
SELECT I.ID, MyResult || I.Type, I.RowNumForOrder, I.RowCountForOrder
FROM IndexedTable I
JOIN ConcatAndOrder C on I.ID = C.ID and I.RowNumForOrder = C.RowNumForOrder + 1
), IndexedTable(ID, Type, RowNumForOrder, RowCountForOrder) AS (
SELECT ID, Type,
row_number() OVER (PARTITION BY ID ORDER BY MyTimestamp),
count(*) OVER (PARTITION BY ID)
FROM MyTable
)
SELECT ID, MyResult
FROM ConcatAndOrder
WHERE RowNumForOrder = RowCountForOrder
ORDER BY ID
answered Nov 22 '18 at 15:58
laulau
72314
72314
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433927%2fhow-to-convert-timestamp-to-numbers%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown