Is it possible to construct a trigonometric series convergent in $(0,1)$ while divergent in $(2,3)$?
Here by a trigonometric series, I mean
$$ f(x)=sum_{n=1}^infty a_n e^{ i b_n x }, $$
where $a_n$, $b_n$ can be arbitrary complex numbers.
Two Questions:
Q1. Is it possible to make such a function $f$ convergent in $(0,1)$ but divergent in $(2,3)$?
Q2. As a related question, is it possible to make $f$ differentiable in $(0,1)$ but not differentiable in $(2,3)$?
fourier-analysis fourier-series
add a comment |
Here by a trigonometric series, I mean
$$ f(x)=sum_{n=1}^infty a_n e^{ i b_n x }, $$
where $a_n$, $b_n$ can be arbitrary complex numbers.
Two Questions:
Q1. Is it possible to make such a function $f$ convergent in $(0,1)$ but divergent in $(2,3)$?
Q2. As a related question, is it possible to make $f$ differentiable in $(0,1)$ but not differentiable in $(2,3)$?
fourier-analysis fourier-series
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Yes, pointwise.
– pie
Nov 29 at 11:02
add a comment |
Here by a trigonometric series, I mean
$$ f(x)=sum_{n=1}^infty a_n e^{ i b_n x }, $$
where $a_n$, $b_n$ can be arbitrary complex numbers.
Two Questions:
Q1. Is it possible to make such a function $f$ convergent in $(0,1)$ but divergent in $(2,3)$?
Q2. As a related question, is it possible to make $f$ differentiable in $(0,1)$ but not differentiable in $(2,3)$?
fourier-analysis fourier-series
Here by a trigonometric series, I mean
$$ f(x)=sum_{n=1}^infty a_n e^{ i b_n x }, $$
where $a_n$, $b_n$ can be arbitrary complex numbers.
Two Questions:
Q1. Is it possible to make such a function $f$ convergent in $(0,1)$ but divergent in $(2,3)$?
Q2. As a related question, is it possible to make $f$ differentiable in $(0,1)$ but not differentiable in $(2,3)$?
fourier-analysis fourier-series
fourier-analysis fourier-series
edited Nov 28 at 23:21
Mason
1,8581529
1,8581529
asked Nov 28 at 23:10
pie
735
735
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Yes, pointwise.
– pie
Nov 29 at 11:02
add a comment |
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Yes, pointwise.
– pie
Nov 29 at 11:02
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Yes, pointwise.
– pie
Nov 29 at 11:02
Yes, pointwise.
– pie
Nov 29 at 11:02
add a comment |
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3017893%2fis-it-possible-to-construct-a-trigonometric-series-convergent-in-0-1-while-d%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3017893%2fis-it-possible-to-construct-a-trigonometric-series-convergent-in-0-1-while-d%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Converges in what sense? Pointwise?
– Dunham
Nov 29 at 1:19
Yes, pointwise.
– pie
Nov 29 at 11:02