c printing the actual content of string
0
I want to print a string, which name was contained by another string.
My code is this:
int i=1; //forexample
char end[9];
char start[25]="kerdesek[index]."; //my question(kerdes) array
if(i==1){
melyikkerdes='A';
strcpy(vege,"a_valasz"); //the exact answer(=valasz) i want to
} //print
else if(i==2){
melyikkerdes='B';
strcpy(vege,"b_valasz");
}
else if(i==3){
melyikkerdes='C';
strcpy(vege,"c_valasz");
}
else{
melyikkerdes='D';
strcpy(vege,"d_valasz");
}
strcat(end,start);
printf("%s",start"); //i want to print the value of the
//concatenated string here
My program prints:
kerdesek[index].a_valasz
Do you have any solution? .
c string
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
|
show 3 more comments
0
I want to print a string, which name was contained by another string.
My code is this:
int i=1; //forexample
char end[9];
char start[25]="kerdesek[index]."; //my question(kerdes) array
if(i==1){
melyikkerdes='A';
strcpy(vege,"a_valasz"); //the exact answer(=valasz) i want to
} //print
else if(i==2){
melyikkerdes='B';
strcpy(vege,"b_valasz");
}
else if(i==3){
melyikkerdes='C';
strcpy(vege,"c_valasz");
}
else{
melyikkerdes='D';
strcpy(vege,"d_valasz");
}
strcat(end,start);
printf("%s",start"); //i want to print the value of the
//concatenated string here
My program prints:
kerdesek[index].a_valasz
Do you have any solution? .
c string
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
You are usingendwithout initializing it.
– H.S.
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36
|
show 3 more comments
0
0
0
I want to print a string, which name was contained by another string.
My code is this:
int i=1; //forexample
char end[9];
char start[25]="kerdesek[index]."; //my question(kerdes) array
if(i==1){
melyikkerdes='A';
strcpy(vege,"a_valasz"); //the exact answer(=valasz) i want to
} //print
else if(i==2){
melyikkerdes='B';
strcpy(vege,"b_valasz");
}
else if(i==3){
melyikkerdes='C';
strcpy(vege,"c_valasz");
}
else{
melyikkerdes='D';
strcpy(vege,"d_valasz");
}
strcat(end,start);
printf("%s",start"); //i want to print the value of the
//concatenated string here
My program prints:
kerdesek[index].a_valasz
Do you have any solution? .
c string
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
I want to print a string, which name was contained by another string.
My code is this:
int i=1; //forexample
char end[9];
char start[25]="kerdesek[index]."; //my question(kerdes) array
if(i==1){
melyikkerdes='A';
strcpy(vege,"a_valasz"); //the exact answer(=valasz) i want to
} //print
else if(i==2){
melyikkerdes='B';
strcpy(vege,"b_valasz");
}
else if(i==3){
melyikkerdes='C';
strcpy(vege,"c_valasz");
}
else{
melyikkerdes='D';
strcpy(vege,"d_valasz");
}
strcat(end,start);
printf("%s",start"); //i want to print the value of the
//concatenated string here
My program prints:
kerdesek[index].a_valasz
Do you have any solution? .
c string
c string
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
edited Nov 25 '18 at 8:16
Md. Mokammal Hossen Farnan
586320
586320
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
asked Nov 25 '18 at 5:22
Gergely HalászGergely Halász
1
1
Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
You are usingendwithout initializing it.
– H.S.
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36
|
show 3 more comments
Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
You are usingendwithout initializing it.
– H.S.
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36
Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
You are using
end without initializing it.– H.S.
Nov 25 '18 at 5:35
You are using
end without initializing it.– H.S.
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36
|
show 3 more comments
2 Answers
2
active
oldest
votes
0
C has no way to evalutate the contents of a string as an expression. You may be able to do what you want with pointers, however:
int i=1; //forexample
struct kerdesek_type *kelem = &kerdesek[index];
char *string = 0;
if(i==1){
melyikkerdes='A';
string = kelem->a_valasz;
}
else if(i==2){
melyikkerdes='B';
string = kelem->b_valasz;
}
else if(i==3){
melyikkerdes='C';
string = kelem->c_valasz;
}
else{
melyikkerdes='D';
string = kelem->d_valasz;
}
printf("%s",string);
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
add a comment |
0
If I understand you correctly, you don't want to print
kerdesek[index].a_valasz
but rather what is contained in the structure element?
You cannot construct C code as strings at runtime and have them an executable part of your program.
Is this what you are trying to do?
#include <stdio.h>
#define MAX_RECORDS 2
struct ker
{
char a_answer[50];
char b_answer[50];
};
int main()
{
struct ker questions[MAX_RECORDS] = {{"a_one", "b_one"},{"a_two", "b_two"}};
char *reply_string = "None";
int answer_number = 2; //Example
int question_number = 1; //Example
switch (answer_number){
case 1:
reply_string = questions[question_number].a_answer;
break;
case 2:
reply_string = questions[question_number].b_answer;
break;
default:
reply_string = "None";
break;
}
printf("%sn", reply_string);
return 0;
}
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
C has no way to evalutate the contents of a string as an expression. You may be able to do what you want with pointers, however:
int i=1; //forexample
struct kerdesek_type *kelem = &kerdesek[index];
char *string = 0;
if(i==1){
melyikkerdes='A';
string = kelem->a_valasz;
}
else if(i==2){
melyikkerdes='B';
string = kelem->b_valasz;
}
else if(i==3){
melyikkerdes='C';
string = kelem->c_valasz;
}
else{
melyikkerdes='D';
string = kelem->d_valasz;
}
printf("%s",string);
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
add a comment |
0
C has no way to evalutate the contents of a string as an expression. You may be able to do what you want with pointers, however:
int i=1; //forexample
struct kerdesek_type *kelem = &kerdesek[index];
char *string = 0;
if(i==1){
melyikkerdes='A';
string = kelem->a_valasz;
}
else if(i==2){
melyikkerdes='B';
string = kelem->b_valasz;
}
else if(i==3){
melyikkerdes='C';
string = kelem->c_valasz;
}
else{
melyikkerdes='D';
string = kelem->d_valasz;
}
printf("%s",string);
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
add a comment |
0
0
0
C has no way to evalutate the contents of a string as an expression. You may be able to do what you want with pointers, however:
int i=1; //forexample
struct kerdesek_type *kelem = &kerdesek[index];
char *string = 0;
if(i==1){
melyikkerdes='A';
string = kelem->a_valasz;
}
else if(i==2){
melyikkerdes='B';
string = kelem->b_valasz;
}
else if(i==3){
melyikkerdes='C';
string = kelem->c_valasz;
}
else{
melyikkerdes='D';
string = kelem->d_valasz;
}
printf("%s",string);
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
C has no way to evalutate the contents of a string as an expression. You may be able to do what you want with pointers, however:
int i=1; //forexample
struct kerdesek_type *kelem = &kerdesek[index];
char *string = 0;
if(i==1){
melyikkerdes='A';
string = kelem->a_valasz;
}
else if(i==2){
melyikkerdes='B';
string = kelem->b_valasz;
}
else if(i==3){
melyikkerdes='C';
string = kelem->c_valasz;
}
else{
melyikkerdes='D';
string = kelem->d_valasz;
}
printf("%s",string);
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
answered Nov 25 '18 at 7:28
Chris DoddChris Dodd
81.8k681160
81.8k681160
add a comment |
add a comment |
0
If I understand you correctly, you don't want to print
kerdesek[index].a_valasz
but rather what is contained in the structure element?
You cannot construct C code as strings at runtime and have them an executable part of your program.
Is this what you are trying to do?
#include <stdio.h>
#define MAX_RECORDS 2
struct ker
{
char a_answer[50];
char b_answer[50];
};
int main()
{
struct ker questions[MAX_RECORDS] = {{"a_one", "b_one"},{"a_two", "b_two"}};
char *reply_string = "None";
int answer_number = 2; //Example
int question_number = 1; //Example
switch (answer_number){
case 1:
reply_string = questions[question_number].a_answer;
break;
case 2:
reply_string = questions[question_number].b_answer;
break;
default:
reply_string = "None";
break;
}
printf("%sn", reply_string);
return 0;
}
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
add a comment |
0
If I understand you correctly, you don't want to print
kerdesek[index].a_valasz
but rather what is contained in the structure element?
You cannot construct C code as strings at runtime and have them an executable part of your program.
Is this what you are trying to do?
#include <stdio.h>
#define MAX_RECORDS 2
struct ker
{
char a_answer[50];
char b_answer[50];
};
int main()
{
struct ker questions[MAX_RECORDS] = {{"a_one", "b_one"},{"a_two", "b_two"}};
char *reply_string = "None";
int answer_number = 2; //Example
int question_number = 1; //Example
switch (answer_number){
case 1:
reply_string = questions[question_number].a_answer;
break;
case 2:
reply_string = questions[question_number].b_answer;
break;
default:
reply_string = "None";
break;
}
printf("%sn", reply_string);
return 0;
}
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
add a comment |
0
0
0
If I understand you correctly, you don't want to print
kerdesek[index].a_valasz
but rather what is contained in the structure element?
You cannot construct C code as strings at runtime and have them an executable part of your program.
Is this what you are trying to do?
#include <stdio.h>
#define MAX_RECORDS 2
struct ker
{
char a_answer[50];
char b_answer[50];
};
int main()
{
struct ker questions[MAX_RECORDS] = {{"a_one", "b_one"},{"a_two", "b_two"}};
char *reply_string = "None";
int answer_number = 2; //Example
int question_number = 1; //Example
switch (answer_number){
case 1:
reply_string = questions[question_number].a_answer;
break;
case 2:
reply_string = questions[question_number].b_answer;
break;
default:
reply_string = "None";
break;
}
printf("%sn", reply_string);
return 0;
}
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
If I understand you correctly, you don't want to print
kerdesek[index].a_valasz
but rather what is contained in the structure element?
You cannot construct C code as strings at runtime and have them an executable part of your program.
Is this what you are trying to do?
#include <stdio.h>
#define MAX_RECORDS 2
struct ker
{
char a_answer[50];
char b_answer[50];
};
int main()
{
struct ker questions[MAX_RECORDS] = {{"a_one", "b_one"},{"a_two", "b_two"}};
char *reply_string = "None";
int answer_number = 2; //Example
int question_number = 1; //Example
switch (answer_number){
case 1:
reply_string = questions[question_number].a_answer;
break;
case 2:
reply_string = questions[question_number].b_answer;
break;
default:
reply_string = "None";
break;
}
printf("%sn", reply_string);
return 0;
}
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
answered Nov 25 '18 at 8:19
GermanNerdGermanNerd
512111
512111
add a comment |
add a comment |
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Could you add example input and output?
– J...S
Nov 25 '18 at 5:25
from my sturct (kerdesek[index].a_valasz) i have to print "apple", but it only prints the name of the path, not the exact string, that the path contains
– Gergely Halász
Nov 25 '18 at 5:33
You are using
endwithout initializing it.– H.S.
Nov 25 '18 at 5:35
i is hard coded to 1, then you concatenate "a_valasz" to "kerdesek[index]." giving your answer, so... it is doing what you are telling it to.
– SteveFerg
Nov 25 '18 at 5:35
sry i translated it bad. vege=end
– Gergely Halász
Nov 25 '18 at 5:36