Python: How to add a new line with a variable inside of the print function
In Python, I'm aware that 'n' adds a new line when using a string inside of a print call. But how do I add a new line when using a variable inside of the print function?
For example:
print("nHello") # <----- string used, no issues here
produces
>>> print("nHello")
Hello
Now suppose I have a list named guest_list. How would I do something akin
to "print('n'guest_list)", printing an empty line and then the list?
Thanks for any help offered!
python string python-3.x
edited Nov 20 at 22:38
timgeb
48.8k116390
asked Nov 20 at 22:28
Maverick
244
add a comment |
In Python, I'm aware that 'n' adds a new line when using a string inside of a print call. But how do I add a new line when using a variable inside of the print function?
For example:
print("nHello") # <----- string used, no issues here
produces
>>> print("nHello")
Hello
Now suppose I have a list named guest_list. How would I do something akin
to "print('n'guest_list)", printing an empty line and then the list?
Thanks for any help offered!
python string python-3.x
edited Nov 20 at 22:38
timgeb
48.8k116390
asked Nov 20 at 22:28
Maverick
244
1
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05
add a comment |
In Python, I'm aware that 'n' adds a new line when using a string inside of a print call. But how do I add a new line when using a variable inside of the print function?
For example:
print("nHello") # <----- string used, no issues here
produces
>>> print("nHello")
Hello
Now suppose I have a list named guest_list. How would I do something akin
to "print('n'guest_list)", printing an empty line and then the list?
Thanks for any help offered!
python string python-3.x
edited Nov 20 at 22:38
timgeb
48.8k116390
asked Nov 20 at 22:28
Maverick
244
In Python, I'm aware that 'n' adds a new line when using a string inside of a print call. But how do I add a new line when using a variable inside of the print function?
For example:
print("nHello") # <----- string used, no issues here
produces
>>> print("nHello")
Hello
Now suppose I have a list named guest_list. How would I do something akin
to "print('n'guest_list)", printing an empty line and then the list?
Thanks for any help offered!
python string python-3.x
python string python-3.x
edited Nov 20 at 22:38
timgeb
48.8k116390
asked Nov 20 at 22:28
Maverick
244
edited Nov 20 at 22:38
timgeb
48.8k116390
asked Nov 20 at 22:28
Maverick
244
edited Nov 20 at 22:38
timgeb
48.8k116390
edited Nov 20 at 22:38
timgeb
48.8k116390
edited Nov 20 at 22:38
timgeb
48.8k116390
48.8k116390
asked Nov 20 at 22:28
Maverick
244
asked Nov 20 at 22:28
Maverick
244
asked Nov 20 at 22:28
Maverick
244
244
1
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05
add a comment |
1
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05
1
1
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05
add a comment |
2 Answers
2
active
oldest
votes
You can pass an empty string as the first argument and sep='n' if you want to avoid formatting/concatenation before printing.
>>> guest_list = [1, 2, 3]
>>> print('', guest_list, sep='n')
[1, 2, 3]
... or equivalently:
>>> print('n', guest_list, sep='')
[1, 2, 3]
answered Nov 20 at 22:30
timgeb
48.8k116390
add a comment |
Or convert to string, then add 'n' to it:
>>> l=[1,2,3]
>>> print('n'+str(l))
[1, 2, 3]
answered Nov 20 at 23:16
U9-Forward
12.3k21136
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can pass an empty string as the first argument and sep='n' if you want to avoid formatting/concatenation before printing.
>>> guest_list = [1, 2, 3]
>>> print('', guest_list, sep='n')
[1, 2, 3]
... or equivalently:
>>> print('n', guest_list, sep='')
[1, 2, 3]
answered Nov 20 at 22:30
timgeb
48.8k116390
add a comment |
You can pass an empty string as the first argument and sep='n' if you want to avoid formatting/concatenation before printing.
>>> guest_list = [1, 2, 3]
>>> print('', guest_list, sep='n')
[1, 2, 3]
... or equivalently:
>>> print('n', guest_list, sep='')
[1, 2, 3]
answered Nov 20 at 22:30
timgeb
48.8k116390
add a comment |
You can pass an empty string as the first argument and sep='n' if you want to avoid formatting/concatenation before printing.
>>> guest_list = [1, 2, 3]
>>> print('', guest_list, sep='n')
[1, 2, 3]
... or equivalently:
>>> print('n', guest_list, sep='')
[1, 2, 3]
answered Nov 20 at 22:30
timgeb
48.8k116390
You can pass an empty string as the first argument and sep='n' if you want to avoid formatting/concatenation before printing.
>>> guest_list = [1, 2, 3]
>>> print('', guest_list, sep='n')
[1, 2, 3]
... or equivalently:
>>> print('n', guest_list, sep='')
[1, 2, 3]
answered Nov 20 at 22:30
timgeb
48.8k116390
edited Nov 20 at 22:44
answered Nov 20 at 22:30
timgeb
48.8k116390
answered Nov 20 at 22:30
timgeb
48.8k116390
answered Nov 20 at 22:30
timgeb
48.8k116390
48.8k116390
add a comment |
add a comment |
Or convert to string, then add 'n' to it:
>>> l=[1,2,3]
>>> print('n'+str(l))
[1, 2, 3]
answered Nov 20 at 23:16
U9-Forward
12.3k21136
add a comment |
Or convert to string, then add 'n' to it:
>>> l=[1,2,3]
>>> print('n'+str(l))
[1, 2, 3]
answered Nov 20 at 23:16
U9-Forward
12.3k21136
add a comment |
Or convert to string, then add 'n' to it:
>>> l=[1,2,3]
>>> print('n'+str(l))
[1, 2, 3]
answered Nov 20 at 23:16
U9-Forward
12.3k21136
Or convert to string, then add 'n' to it:
>>> l=[1,2,3]
>>> print('n'+str(l))
[1, 2, 3]
answered Nov 20 at 23:16
U9-Forward
12.3k21136
answered Nov 20 at 23:16
U9-Forward
12.3k21136
answered Nov 20 at 23:16
U9-Forward
12.3k21136
answered Nov 20 at 23:16
U9-Forward
12.3k21136
12.3k21136
add a comment |
add a comment |
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1
did any of the answers solve the issue?
– timgeb
Nov 21 at 14:05