Count repeated words using javascript
0
I am trying to solve this exercise but i a little bit stuck, this is what i have right now, i am trying to iterate over the string incrementing the index plus one per word
"Write a function to perform basic string compression using the counts
of repeated characters e.g "aabcccccaaa" would become "a2b1c5a3", if
the compressed string would not become smaller than the original, just
print the original"
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())javascript
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
add a comment |
0
I am trying to solve this exercise but i a little bit stuck, this is what i have right now, i am trying to iterate over the string incrementing the index plus one per word
"Write a function to perform basic string compression using the counts
of repeated characters e.g "aabcccccaaa" would become "a2b1c5a3", if
the compressed string would not become smaller than the original, just
print the original"
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())javascript
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
4
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29
add a comment |
0
0
0
I am trying to solve this exercise but i a little bit stuck, this is what i have right now, i am trying to iterate over the string incrementing the index plus one per word
"Write a function to perform basic string compression using the counts
of repeated characters e.g "aabcccccaaa" would become "a2b1c5a3", if
the compressed string would not become smaller than the original, just
print the original"
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())javascript
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
I am trying to solve this exercise but i a little bit stuck, this is what i have right now, i am trying to iterate over the string incrementing the index plus one per word
"Write a function to perform basic string compression using the counts
of repeated characters e.g "aabcccccaaa" would become "a2b1c5a3", if
the compressed string would not become smaller than the original, just
print the original"
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 0;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 0;
i++;
} else {
counter++;
i++;
}
}
console.log(result);
if (result.length < word.length)
console.log(result)
else
console.log(word);
}
console.log(countWords())javascript
javascript
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
edited Mar 3 '17 at 18:48
Jonathan Portorreal
1,3762725
1,3762725
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
asked Mar 3 '17 at 17:25
Gilberto Langarica
175
175
Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
4
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29
add a comment |
Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
4
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29
Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
4
4
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29
add a comment |
6 Answers
6
active
oldest
votes
2
You can use the power of Regex, reduce in array and conditional ternary.
function compress(input) {
var re = /(.)1+|./gi;
var match = input.match(re);
var output = match.reduce(function (previousValue, currentValue) {
return previousValue + (currentValue.charAt(0) + currentValue.length);
}, "");
output = (output.length < input.length) ? output : input;
return output;
}
console.log(compress("aabcccccaaa"));
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
add a comment |
0
You have a couple of things going on.
First, you are incrementing your loop index twice. Remove the i++ from your if statement.
Secondly, you need to initialize your counter to 1 not 0.
This code seems to work.
<script>
function countWords()
{
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for(var i = 0; i <= word.length; i++) {
if(word.substr(i, 1) === word.substr(i+1, 1)) {
counter++;
}
else {
result = result + word.substr(i, 1) + counter;
counter = 1;
}
}
console.log(result);
if(result.length < word.length)
console.log(result)
else
console.log(word);
}
countWords();
</script>
answered Mar 3 '17 at 17:44
clarmond
33217
I changed the logic from!=to===just to make it more clear to me but I think the other way would work as well.
– clarmond
Mar 3 '17 at 17:53
add a comment |
0
function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa"));answered Mar 3 '17 at 17:55
beta-developper
1,321814
add a comment |
0
It could be done with reduce function:
let word = 'aabcccccaaa';
let chars = word.split('');
let counter = 1;
let occur = 0;
let result = chars.reduce(function(prevValue, currValue, index, array) {
let isLastChar = array.length - 1 === index;
if (prevValue.substr(prevValue.length - 1) !== currValue) {
occur = counter;
counter = 1;
prevValue = prevValue + occur + currValue;
return isLastChar ? prevValue + 1 : prevValue
} else {
counter++;
return isLastChar ? prevValue + counter : prevValue;
}
});
answered Mar 3 '17 at 18:52
Zacol
785
add a comment |
0
Here's your code with these bugs fixed.
counterstarting at0so the count would be off by one.- similarly to
1), settingcounterback to0each time instead of1. - incrementing
iinside the for loop so values were being skipped.
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
add a comment |
0
var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
}edited Nov 21 '18 at 10:54
barbsan
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
add a comment |
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can use the power of Regex, reduce in array and conditional ternary.
function compress(input) {
var re = /(.)1+|./gi;
var match = input.match(re);
var output = match.reduce(function (previousValue, currentValue) {
return previousValue + (currentValue.charAt(0) + currentValue.length);
}, "");
output = (output.length < input.length) ? output : input;
return output;
}
console.log(compress("aabcccccaaa"));
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
add a comment |
2
You can use the power of Regex, reduce in array and conditional ternary.
function compress(input) {
var re = /(.)1+|./gi;
var match = input.match(re);
var output = match.reduce(function (previousValue, currentValue) {
return previousValue + (currentValue.charAt(0) + currentValue.length);
}, "");
output = (output.length < input.length) ? output : input;
return output;
}
console.log(compress("aabcccccaaa"));
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
add a comment |
2
2
2
You can use the power of Regex, reduce in array and conditional ternary.
function compress(input) {
var re = /(.)1+|./gi;
var match = input.match(re);
var output = match.reduce(function (previousValue, currentValue) {
return previousValue + (currentValue.charAt(0) + currentValue.length);
}, "");
output = (output.length < input.length) ? output : input;
return output;
}
console.log(compress("aabcccccaaa"));
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
You can use the power of Regex, reduce in array and conditional ternary.
function compress(input) {
var re = /(.)1+|./gi;
var match = input.match(re);
var output = match.reduce(function (previousValue, currentValue) {
return previousValue + (currentValue.charAt(0) + currentValue.length);
}, "");
output = (output.length < input.length) ? output : input;
return output;
}
console.log(compress("aabcccccaaa"));
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
edited Mar 3 '17 at 19:40
Donald Duck
3,960123958
3,960123958
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
answered Mar 3 '17 at 18:59
Cleudson Cunha
212
212
add a comment |
add a comment |
0
You have a couple of things going on.
First, you are incrementing your loop index twice. Remove the i++ from your if statement.
Secondly, you need to initialize your counter to 1 not 0.
This code seems to work.
<script>
function countWords()
{
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for(var i = 0; i <= word.length; i++) {
if(word.substr(i, 1) === word.substr(i+1, 1)) {
counter++;
}
else {
result = result + word.substr(i, 1) + counter;
counter = 1;
}
}
console.log(result);
if(result.length < word.length)
console.log(result)
else
console.log(word);
}
countWords();
</script>
answered Mar 3 '17 at 17:44
clarmond
33217
I changed the logic from!=to===just to make it more clear to me but I think the other way would work as well.
– clarmond
Mar 3 '17 at 17:53
add a comment |
0
You have a couple of things going on.
First, you are incrementing your loop index twice. Remove the i++ from your if statement.
Secondly, you need to initialize your counter to 1 not 0.
This code seems to work.
<script>
function countWords()
{
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for(var i = 0; i <= word.length; i++) {
if(word.substr(i, 1) === word.substr(i+1, 1)) {
counter++;
}
else {
result = result + word.substr(i, 1) + counter;
counter = 1;
}
}
console.log(result);
if(result.length < word.length)
console.log(result)
else
console.log(word);
}
countWords();
</script>
answered Mar 3 '17 at 17:44
clarmond
33217
I changed the logic from!=to===just to make it more clear to me but I think the other way would work as well.
– clarmond
Mar 3 '17 at 17:53
add a comment |
0
0
0
You have a couple of things going on.
First, you are incrementing your loop index twice. Remove the i++ from your if statement.
Secondly, you need to initialize your counter to 1 not 0.
This code seems to work.
<script>
function countWords()
{
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for(var i = 0; i <= word.length; i++) {
if(word.substr(i, 1) === word.substr(i+1, 1)) {
counter++;
}
else {
result = result + word.substr(i, 1) + counter;
counter = 1;
}
}
console.log(result);
if(result.length < word.length)
console.log(result)
else
console.log(word);
}
countWords();
</script>
answered Mar 3 '17 at 17:44
clarmond
33217
You have a couple of things going on.
First, you are incrementing your loop index twice. Remove the i++ from your if statement.
Secondly, you need to initialize your counter to 1 not 0.
This code seems to work.
<script>
function countWords()
{
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for(var i = 0; i <= word.length; i++) {
if(word.substr(i, 1) === word.substr(i+1, 1)) {
counter++;
}
else {
result = result + word.substr(i, 1) + counter;
counter = 1;
}
}
console.log(result);
if(result.length < word.length)
console.log(result)
else
console.log(word);
}
countWords();
</script>
answered Mar 3 '17 at 17:44
clarmond
33217
edited Mar 3 '17 at 17:52
answered Mar 3 '17 at 17:44
clarmond
33217
answered Mar 3 '17 at 17:44
clarmond
33217
answered Mar 3 '17 at 17:44
clarmond
33217
33217
I changed the logic from!=to===just to make it more clear to me but I think the other way would work as well.
– clarmond
Mar 3 '17 at 17:53
add a comment |
I changed the logic from!=to===just to make it more clear to me but I think the other way would work as well.
– clarmond
Mar 3 '17 at 17:53
I changed the logic from
!= to === just to make it more clear to me but I think the other way would work as well.– clarmond
Mar 3 '17 at 17:53
I changed the logic from
!= to === just to make it more clear to me but I think the other way would work as well.– clarmond
Mar 3 '17 at 17:53
add a comment |
0
function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa"));answered Mar 3 '17 at 17:55
beta-developper
1,321814
add a comment |
0
function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa"));answered Mar 3 '17 at 17:55
beta-developper
1,321814
add a comment |
0
0
0
function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa"));answered Mar 3 '17 at 17:55
beta-developper
1,321814
function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa")); function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa")); function countChars(word) {
if (!word) {
return word;
}
var arr = word.split('');
var currentChar = arr[0];
var count = 1;
var compression = "";
for (var i = 1; i < arr.length; i++) {
if (arr[i] === currentChar) {
count++;
} else {
compression += currentChar + count;
currentChar = arr[i];
count = 1;
}
}
compression += currentChar + count;
if (compression.length > word.length) {
return word;
}
return compression;
}
console.log(countChars("aabcccccaaa"));answered Mar 3 '17 at 17:55
beta-developper
1,321814
answered Mar 3 '17 at 17:55
beta-developper
1,321814
answered Mar 3 '17 at 17:55
beta-developper
1,321814
answered Mar 3 '17 at 17:55
beta-developper
1,321814
1,321814
add a comment |
add a comment |
0
It could be done with reduce function:
let word = 'aabcccccaaa';
let chars = word.split('');
let counter = 1;
let occur = 0;
let result = chars.reduce(function(prevValue, currValue, index, array) {
let isLastChar = array.length - 1 === index;
if (prevValue.substr(prevValue.length - 1) !== currValue) {
occur = counter;
counter = 1;
prevValue = prevValue + occur + currValue;
return isLastChar ? prevValue + 1 : prevValue
} else {
counter++;
return isLastChar ? prevValue + counter : prevValue;
}
});
answered Mar 3 '17 at 18:52
Zacol
785
add a comment |
0
It could be done with reduce function:
let word = 'aabcccccaaa';
let chars = word.split('');
let counter = 1;
let occur = 0;
let result = chars.reduce(function(prevValue, currValue, index, array) {
let isLastChar = array.length - 1 === index;
if (prevValue.substr(prevValue.length - 1) !== currValue) {
occur = counter;
counter = 1;
prevValue = prevValue + occur + currValue;
return isLastChar ? prevValue + 1 : prevValue
} else {
counter++;
return isLastChar ? prevValue + counter : prevValue;
}
});
answered Mar 3 '17 at 18:52
Zacol
785
add a comment |
0
0
0
It could be done with reduce function:
let word = 'aabcccccaaa';
let chars = word.split('');
let counter = 1;
let occur = 0;
let result = chars.reduce(function(prevValue, currValue, index, array) {
let isLastChar = array.length - 1 === index;
if (prevValue.substr(prevValue.length - 1) !== currValue) {
occur = counter;
counter = 1;
prevValue = prevValue + occur + currValue;
return isLastChar ? prevValue + 1 : prevValue
} else {
counter++;
return isLastChar ? prevValue + counter : prevValue;
}
});
answered Mar 3 '17 at 18:52
Zacol
785
It could be done with reduce function:
let word = 'aabcccccaaa';
let chars = word.split('');
let counter = 1;
let occur = 0;
let result = chars.reduce(function(prevValue, currValue, index, array) {
let isLastChar = array.length - 1 === index;
if (prevValue.substr(prevValue.length - 1) !== currValue) {
occur = counter;
counter = 1;
prevValue = prevValue + occur + currValue;
return isLastChar ? prevValue + 1 : prevValue
} else {
counter++;
return isLastChar ? prevValue + counter : prevValue;
}
});
answered Mar 3 '17 at 18:52
Zacol
785
edited Mar 3 '17 at 19:24
answered Mar 3 '17 at 18:52
Zacol
785
answered Mar 3 '17 at 18:52
Zacol
785
answered Mar 3 '17 at 18:52
Zacol
785
785
add a comment |
add a comment |
0
Here's your code with these bugs fixed.
counterstarting at0so the count would be off by one.- similarly to
1), settingcounterback to0each time instead of1. - incrementing
iinside the for loop so values were being skipped.
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
add a comment |
0
Here's your code with these bugs fixed.
counterstarting at0so the count would be off by one.- similarly to
1), settingcounterback to0each time instead of1. - incrementing
iinside the for loop so values were being skipped.
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
add a comment |
0
0
0
Here's your code with these bugs fixed.
counterstarting at0so the count would be off by one.- similarly to
1), settingcounterback to0each time instead of1. - incrementing
iinside the for loop so values were being skipped.
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
Here's your code with these bugs fixed.
counterstarting at0so the count would be off by one.- similarly to
1), settingcounterback to0each time instead of1. - incrementing
iinside the for loop so values were being skipped.
function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());function countWords() {
var word = "aabcccccaaa";
var result = "";
var counter = 1;
for (var i = 0; i <= word.length; i++) {
if (word[i] != word[i + 1]) {
result = result + word[i] + counter;
counter = 1;
} else {
counter++;
}
}
return result.length < word.length ? result : word;
}
console.log(countWords());answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
edited Mar 3 '17 at 19:49
answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
answered Mar 3 '17 at 19:19
Jonathan Portorreal
1,3762725
1,3762725
add a comment |
add a comment |
0
var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
}edited Nov 21 '18 at 10:54
barbsan
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
add a comment |
0
var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
}edited Nov 21 '18 at 10:54
barbsan
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
add a comment |
0
0
0
var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
}edited Nov 21 '18 at 10:54
barbsan
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
} var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
} var inputString = "Javascript",
searchChar, count = 0;
accurancesRepeat(inputString);
function accurancesRepeat(inputString) {
for (var i = 0; i < inputString.length; i++) {
searchChar = inputString[i];
for (var j = 0; j < inputString.length; j++) {
if (searchChar == inputString[j]) {
count += 1;
}
}
console.log("Accorances of character " + searchChar + " is... " + count);
count = 0;
}
}edited Nov 21 '18 at 10:54
barbsan
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
edited Nov 21 '18 at 10:54
barbsan
2,20811122
edited Nov 21 '18 at 10:54
barbsan
2,20811122
edited Nov 21 '18 at 10:54
barbsan
2,20811122
2,20811122
answered Nov 21 '18 at 10:32
Regan Amburose
32
answered Nov 21 '18 at 10:32
Regan Amburose
32
answered Nov 21 '18 at 10:32
Regan Amburose
32
32
add a comment |
add a comment |
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Not a question. Define your problem.
– Fabian Klötzl
Mar 3 '17 at 17:28
How isn't your code working? What part do you need help with?
– qxz
Mar 3 '17 at 17:28
4
You might find this helpful: stackoverflow.com/help/how-to-ask
– let_the_coding_begin
Mar 3 '17 at 17:29