How to locate row number based on month and year column values in R












0














I am trying to find the MSPE of a model. My dataset has 192 rows in it and my model is a time series model. I keep on getting the error: "number of items to replace is not a multiple of replacement length". This knitted once in R but has not since.



library(dplyr)
for (i in 1:100){
YX$id <- 1:nrow(YX)
train <- YX %>% dplyr::sample_frac(.8)
test <- dplyr::anti_join(YX, trainr, by = 'id')
fit <- lm(Y ~ Ypast+ seatbelt$month[t]+
seatbelt$year[t] + sin12 + cos12 + kmsperp, data=
train)
ytest <- predict(fit, test)
results[i] <- ((test$Y - ytest )^2)/nrow(test)
}
mean(results)









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  • 1




    Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
    – Tung
    Nov 21 at 1:42
















0














I am trying to find the MSPE of a model. My dataset has 192 rows in it and my model is a time series model. I keep on getting the error: "number of items to replace is not a multiple of replacement length". This knitted once in R but has not since.



library(dplyr)
for (i in 1:100){
YX$id <- 1:nrow(YX)
train <- YX %>% dplyr::sample_frac(.8)
test <- dplyr::anti_join(YX, trainr, by = 'id')
fit <- lm(Y ~ Ypast+ seatbelt$month[t]+
seatbelt$year[t] + sin12 + cos12 + kmsperp, data=
train)
ytest <- predict(fit, test)
results[i] <- ((test$Y - ytest )^2)/nrow(test)
}
mean(results)









share|improve this question


















  • 1




    Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
    – Tung
    Nov 21 at 1:42














0












0








0







I am trying to find the MSPE of a model. My dataset has 192 rows in it and my model is a time series model. I keep on getting the error: "number of items to replace is not a multiple of replacement length". This knitted once in R but has not since.



library(dplyr)
for (i in 1:100){
YX$id <- 1:nrow(YX)
train <- YX %>% dplyr::sample_frac(.8)
test <- dplyr::anti_join(YX, trainr, by = 'id')
fit <- lm(Y ~ Ypast+ seatbelt$month[t]+
seatbelt$year[t] + sin12 + cos12 + kmsperp, data=
train)
ytest <- predict(fit, test)
results[i] <- ((test$Y - ytest )^2)/nrow(test)
}
mean(results)









share|improve this question













I am trying to find the MSPE of a model. My dataset has 192 rows in it and my model is a time series model. I keep on getting the error: "number of items to replace is not a multiple of replacement length". This knitted once in R but has not since.



library(dplyr)
for (i in 1:100){
YX$id <- 1:nrow(YX)
train <- YX %>% dplyr::sample_frac(.8)
test <- dplyr::anti_join(YX, trainr, by = 'id')
fit <- lm(Y ~ Ypast+ seatbelt$month[t]+
seatbelt$year[t] + sin12 + cos12 + kmsperp, data=
train)
ytest <- predict(fit, test)
results[i] <- ((test$Y - ytest )^2)/nrow(test)
}
mean(results)






r time-series training-data mse






share|improve this question













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asked Nov 20 at 17:50









Liz

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1








  • 1




    Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
    – Tung
    Nov 21 at 1:42














  • 1




    Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
    – Tung
    Nov 21 at 1:42








1




1




Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
– Tung
Nov 21 at 1:42




Welcome to Stack Overflow! Could you make your problem reproducible by sharing a sample of your data so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?
– Tung
Nov 21 at 1:42

















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