Why is my shapely polygon generated from a mask invalid?
I am trying to make a shapely Polygon from a binary mask, but I always end up with an invalid Polygon. How can I make a valid polygon from an arbitrary binary mask? Below is an example using a circular mask. I suspect that it is because the points I get from the mask contour are out of order, which is apparent when I plot the points (see images below).
import matplotlib.pyplot as plt
import numpy as np
from shapely.geometry import Point, Polygon
from scipy.ndimage.morphology import binary_erosion
from skimage import draw
def get_circular_se(radius=2):
N = (radius * 2) + 1
se = np.zeros(shape=[N,N])
for i in range(N):
for j in range(N):
se[i,j] = (i - N / 2)**2 + (j - N / 2)**2 <= radius**2
se = np.array(se, dtype="uint8")
return se
return new_regions, np.asarray(new_vertices)
#generates a circular mask
side_len = 512
rad = 100
mask = np.zeros(shape=(side_len, side_len))
rr, cc = draw.circle(side_len/2, side_len/2, radius=rad, shape=mask.shape)
mask[rr, cc] = 1
#makes a polygon from the mask perimeter
se = get_circular_se(radius=1)
contour = mask - binary_erosion(mask, structure=se)
pixels_mask = np.array(np.where(contour==1)[::-1]).T
polygon = Polygon(pixels_mask)
print polygon.is_valid
>>False
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask[:,0],pixels_mask[:,1],'b-',lw=0.5)
plt.tight_layout()
plt.show()
python numpy matplotlib shapely
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I am trying to make a shapely Polygon from a binary mask, but I always end up with an invalid Polygon. How can I make a valid polygon from an arbitrary binary mask? Below is an example using a circular mask. I suspect that it is because the points I get from the mask contour are out of order, which is apparent when I plot the points (see images below).
import matplotlib.pyplot as plt
import numpy as np
from shapely.geometry import Point, Polygon
from scipy.ndimage.morphology import binary_erosion
from skimage import draw
def get_circular_se(radius=2):
N = (radius * 2) + 1
se = np.zeros(shape=[N,N])
for i in range(N):
for j in range(N):
se[i,j] = (i - N / 2)**2 + (j - N / 2)**2 <= radius**2
se = np.array(se, dtype="uint8")
return se
return new_regions, np.asarray(new_vertices)
#generates a circular mask
side_len = 512
rad = 100
mask = np.zeros(shape=(side_len, side_len))
rr, cc = draw.circle(side_len/2, side_len/2, radius=rad, shape=mask.shape)
mask[rr, cc] = 1
#makes a polygon from the mask perimeter
se = get_circular_se(radius=1)
contour = mask - binary_erosion(mask, structure=se)
pixels_mask = np.array(np.where(contour==1)[::-1]).T
polygon = Polygon(pixels_mask)
print polygon.is_valid
>>False
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask[:,0],pixels_mask[:,1],'b-',lw=0.5)
plt.tight_layout()
plt.show()
python numpy matplotlib shapely
add a comment |
I am trying to make a shapely Polygon from a binary mask, but I always end up with an invalid Polygon. How can I make a valid polygon from an arbitrary binary mask? Below is an example using a circular mask. I suspect that it is because the points I get from the mask contour are out of order, which is apparent when I plot the points (see images below).
import matplotlib.pyplot as plt
import numpy as np
from shapely.geometry import Point, Polygon
from scipy.ndimage.morphology import binary_erosion
from skimage import draw
def get_circular_se(radius=2):
N = (radius * 2) + 1
se = np.zeros(shape=[N,N])
for i in range(N):
for j in range(N):
se[i,j] = (i - N / 2)**2 + (j - N / 2)**2 <= radius**2
se = np.array(se, dtype="uint8")
return se
return new_regions, np.asarray(new_vertices)
#generates a circular mask
side_len = 512
rad = 100
mask = np.zeros(shape=(side_len, side_len))
rr, cc = draw.circle(side_len/2, side_len/2, radius=rad, shape=mask.shape)
mask[rr, cc] = 1
#makes a polygon from the mask perimeter
se = get_circular_se(radius=1)
contour = mask - binary_erosion(mask, structure=se)
pixels_mask = np.array(np.where(contour==1)[::-1]).T
polygon = Polygon(pixels_mask)
print polygon.is_valid
>>False
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask[:,0],pixels_mask[:,1],'b-',lw=0.5)
plt.tight_layout()
plt.show()
python numpy matplotlib shapely
I am trying to make a shapely Polygon from a binary mask, but I always end up with an invalid Polygon. How can I make a valid polygon from an arbitrary binary mask? Below is an example using a circular mask. I suspect that it is because the points I get from the mask contour are out of order, which is apparent when I plot the points (see images below).
import matplotlib.pyplot as plt
import numpy as np
from shapely.geometry import Point, Polygon
from scipy.ndimage.morphology import binary_erosion
from skimage import draw
def get_circular_se(radius=2):
N = (radius * 2) + 1
se = np.zeros(shape=[N,N])
for i in range(N):
for j in range(N):
se[i,j] = (i - N / 2)**2 + (j - N / 2)**2 <= radius**2
se = np.array(se, dtype="uint8")
return se
return new_regions, np.asarray(new_vertices)
#generates a circular mask
side_len = 512
rad = 100
mask = np.zeros(shape=(side_len, side_len))
rr, cc = draw.circle(side_len/2, side_len/2, radius=rad, shape=mask.shape)
mask[rr, cc] = 1
#makes a polygon from the mask perimeter
se = get_circular_se(radius=1)
contour = mask - binary_erosion(mask, structure=se)
pixels_mask = np.array(np.where(contour==1)[::-1]).T
polygon = Polygon(pixels_mask)
print polygon.is_valid
>>False
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask[:,0],pixels_mask[:,1],'b-',lw=0.5)
plt.tight_layout()
plt.show()
python numpy matplotlib shapely
python numpy matplotlib shapely
asked Nov 21 '18 at 10:25
Andrew
1,2272109
1,2272109
add a comment |
add a comment |
1 Answer
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In fact I already found a solution that worked for me, but maybe someone has a better one. The problem was indeed that my points were out of order. Input coordinate order is crucial for making valid polygons. So, one just has to put the points in the right order first. Below is an example solution using a nearest neighbor approach with a KDTree, which I've already posted elsewhere for related problems.
from sklearn.neighbors import KDTree
def polygonize_by_nearest_neighbor(pp):
"""Takes a set of xy coordinates pp Numpy array(n,2) and reorders the array to make
a polygon using a nearest neighbor approach.
"""
# start with first index
pp_new = np.zeros_like(pp)
pp_new[0] = pp[0]
p_current_idx = 0
tree = KDTree(pp)
for i in range(len(pp) - 1):
nearest_dist, nearest_idx = tree.query([pp[p_current_idx]], k=4) # k1 = identity
nearest_idx = nearest_idx[0]
# finds next nearest point along the contour and adds it
for min_idx in nearest_idx[1:]: # skip the first point (will be zero for same pixel)
if not pp[min_idx].tolist() in pp_new.tolist(): # make sure it's not already in the list
pp_new[i + 1] = pp[min_idx]
p_current_idx = min_idx
break
pp_new[-1] = pp[0]
return pp_new
pixels_mask_ordered = polygonize_by_nearest_neighbor(pixels_mask)
polygon = Polygon(pixels_mask_ordered)
print polygon.is_valid
>>True
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask_ordered[:,0],pixels_mask_ordered[:,1],'b-',lw=2)
plt.tight_layout()
plt.show()
add a comment |
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1 Answer
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oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
In fact I already found a solution that worked for me, but maybe someone has a better one. The problem was indeed that my points were out of order. Input coordinate order is crucial for making valid polygons. So, one just has to put the points in the right order first. Below is an example solution using a nearest neighbor approach with a KDTree, which I've already posted elsewhere for related problems.
from sklearn.neighbors import KDTree
def polygonize_by_nearest_neighbor(pp):
"""Takes a set of xy coordinates pp Numpy array(n,2) and reorders the array to make
a polygon using a nearest neighbor approach.
"""
# start with first index
pp_new = np.zeros_like(pp)
pp_new[0] = pp[0]
p_current_idx = 0
tree = KDTree(pp)
for i in range(len(pp) - 1):
nearest_dist, nearest_idx = tree.query([pp[p_current_idx]], k=4) # k1 = identity
nearest_idx = nearest_idx[0]
# finds next nearest point along the contour and adds it
for min_idx in nearest_idx[1:]: # skip the first point (will be zero for same pixel)
if not pp[min_idx].tolist() in pp_new.tolist(): # make sure it's not already in the list
pp_new[i + 1] = pp[min_idx]
p_current_idx = min_idx
break
pp_new[-1] = pp[0]
return pp_new
pixels_mask_ordered = polygonize_by_nearest_neighbor(pixels_mask)
polygon = Polygon(pixels_mask_ordered)
print polygon.is_valid
>>True
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask_ordered[:,0],pixels_mask_ordered[:,1],'b-',lw=2)
plt.tight_layout()
plt.show()
add a comment |
In fact I already found a solution that worked for me, but maybe someone has a better one. The problem was indeed that my points were out of order. Input coordinate order is crucial for making valid polygons. So, one just has to put the points in the right order first. Below is an example solution using a nearest neighbor approach with a KDTree, which I've already posted elsewhere for related problems.
from sklearn.neighbors import KDTree
def polygonize_by_nearest_neighbor(pp):
"""Takes a set of xy coordinates pp Numpy array(n,2) and reorders the array to make
a polygon using a nearest neighbor approach.
"""
# start with first index
pp_new = np.zeros_like(pp)
pp_new[0] = pp[0]
p_current_idx = 0
tree = KDTree(pp)
for i in range(len(pp) - 1):
nearest_dist, nearest_idx = tree.query([pp[p_current_idx]], k=4) # k1 = identity
nearest_idx = nearest_idx[0]
# finds next nearest point along the contour and adds it
for min_idx in nearest_idx[1:]: # skip the first point (will be zero for same pixel)
if not pp[min_idx].tolist() in pp_new.tolist(): # make sure it's not already in the list
pp_new[i + 1] = pp[min_idx]
p_current_idx = min_idx
break
pp_new[-1] = pp[0]
return pp_new
pixels_mask_ordered = polygonize_by_nearest_neighbor(pixels_mask)
polygon = Polygon(pixels_mask_ordered)
print polygon.is_valid
>>True
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask_ordered[:,0],pixels_mask_ordered[:,1],'b-',lw=2)
plt.tight_layout()
plt.show()
add a comment |
In fact I already found a solution that worked for me, but maybe someone has a better one. The problem was indeed that my points were out of order. Input coordinate order is crucial for making valid polygons. So, one just has to put the points in the right order first. Below is an example solution using a nearest neighbor approach with a KDTree, which I've already posted elsewhere for related problems.
from sklearn.neighbors import KDTree
def polygonize_by_nearest_neighbor(pp):
"""Takes a set of xy coordinates pp Numpy array(n,2) and reorders the array to make
a polygon using a nearest neighbor approach.
"""
# start with first index
pp_new = np.zeros_like(pp)
pp_new[0] = pp[0]
p_current_idx = 0
tree = KDTree(pp)
for i in range(len(pp) - 1):
nearest_dist, nearest_idx = tree.query([pp[p_current_idx]], k=4) # k1 = identity
nearest_idx = nearest_idx[0]
# finds next nearest point along the contour and adds it
for min_idx in nearest_idx[1:]: # skip the first point (will be zero for same pixel)
if not pp[min_idx].tolist() in pp_new.tolist(): # make sure it's not already in the list
pp_new[i + 1] = pp[min_idx]
p_current_idx = min_idx
break
pp_new[-1] = pp[0]
return pp_new
pixels_mask_ordered = polygonize_by_nearest_neighbor(pixels_mask)
polygon = Polygon(pixels_mask_ordered)
print polygon.is_valid
>>True
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask_ordered[:,0],pixels_mask_ordered[:,1],'b-',lw=2)
plt.tight_layout()
plt.show()
In fact I already found a solution that worked for me, but maybe someone has a better one. The problem was indeed that my points were out of order. Input coordinate order is crucial for making valid polygons. So, one just has to put the points in the right order first. Below is an example solution using a nearest neighbor approach with a KDTree, which I've already posted elsewhere for related problems.
from sklearn.neighbors import KDTree
def polygonize_by_nearest_neighbor(pp):
"""Takes a set of xy coordinates pp Numpy array(n,2) and reorders the array to make
a polygon using a nearest neighbor approach.
"""
# start with first index
pp_new = np.zeros_like(pp)
pp_new[0] = pp[0]
p_current_idx = 0
tree = KDTree(pp)
for i in range(len(pp) - 1):
nearest_dist, nearest_idx = tree.query([pp[p_current_idx]], k=4) # k1 = identity
nearest_idx = nearest_idx[0]
# finds next nearest point along the contour and adds it
for min_idx in nearest_idx[1:]: # skip the first point (will be zero for same pixel)
if not pp[min_idx].tolist() in pp_new.tolist(): # make sure it's not already in the list
pp_new[i + 1] = pp[min_idx]
p_current_idx = min_idx
break
pp_new[-1] = pp[0]
return pp_new
pixels_mask_ordered = polygonize_by_nearest_neighbor(pixels_mask)
polygon = Polygon(pixels_mask_ordered)
print polygon.is_valid
>>True
#plots the results
fig, ax = plt.subplots()
ax.imshow(mask,cmap='Greys_r')
ax.plot(pixels_mask_ordered[:,0],pixels_mask_ordered[:,1],'b-',lw=2)
plt.tight_layout()
plt.show()
answered Nov 21 '18 at 10:30
Andrew
1,2272109
1,2272109
add a comment |
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