Error Showing in Simple Google Apps Script, How to hide
I have a simple Google Apps Script that checks URLs, however, I would like to display something like "Not valid" for any non-200 status responses. Everything I try shows "#ERROR!" on the Google Sheet except for status 200 responses.
Here is my code:
function check_url(url) {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
} else {
return "Not Valid"
}
}
Any help is greatly appreciated as I am not very familiar with GA scripts or Javascript.
Thanks!
google-apps-script
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
add a comment |
I have a simple Google Apps Script that checks URLs, however, I would like to display something like "Not valid" for any non-200 status responses. Everything I try shows "#ERROR!" on the Google Sheet except for status 200 responses.
Here is my code:
function check_url(url) {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
} else {
return "Not Valid"
}
}
Any help is greatly appreciated as I am not very familiar with GA scripts or Javascript.
Thanks!
google-apps-script
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
add a comment |
I have a simple Google Apps Script that checks URLs, however, I would like to display something like "Not valid" for any non-200 status responses. Everything I try shows "#ERROR!" on the Google Sheet except for status 200 responses.
Here is my code:
function check_url(url) {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
} else {
return "Not Valid"
}
}
Any help is greatly appreciated as I am not very familiar with GA scripts or Javascript.
Thanks!
google-apps-script
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
I have a simple Google Apps Script that checks URLs, however, I would like to display something like "Not valid" for any non-200 status responses. Everything I try shows "#ERROR!" on the Google Sheet except for status 200 responses.
Here is my code:
function check_url(url) {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
} else {
return "Not Valid"
}
}
Any help is greatly appreciated as I am not very familiar with GA scripts or Javascript.
Thanks!
google-apps-script
google-apps-script
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
asked Nov 25 '18 at 17:43
thomaskesselthomaskessel
1392310
1392310
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
This is a case where you need a try catch block. The fetch is throwing an error so there is no response.
function check_url(url) {
try {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
}
}
catch(err) {
return "Not Valid"
}
}
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
add a comment |
You should muteHTTPExceptions:
var response = UrlFetchApp.fetch(url,{'muteHTTPExceptions':true})
Also use arrays with fetchAll method, if you have a large number of urls to fetch.
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is a case where you need a try catch block. The fetch is throwing an error so there is no response.
function check_url(url) {
try {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
}
}
catch(err) {
return "Not Valid"
}
}
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
add a comment |
This is a case where you need a try catch block. The fetch is throwing an error so there is no response.
function check_url(url) {
try {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
}
}
catch(err) {
return "Not Valid"
}
}
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
add a comment |
This is a case where you need a try catch block. The fetch is throwing an error so there is no response.
function check_url(url) {
try {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
}
}
catch(err) {
return "Not Valid"
}
}
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
This is a case where you need a try catch block. The fetch is throwing an error so there is no response.
function check_url(url) {
try {
var response = UrlFetchApp.fetch(url)
if( response.getResponseCode() == 200 ) {
return true
} else if( response.getResponseCode() == 401 ) {
return "401"
}
}
catch(err) {
return "Not Valid"
}
}
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
answered Nov 25 '18 at 18:14
TheWizEdTheWizEd
640158
640158
add a comment |
add a comment |
You should muteHTTPExceptions:
var response = UrlFetchApp.fetch(url,{'muteHTTPExceptions':true})
Also use arrays with fetchAll method, if you have a large number of urls to fetch.
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
add a comment |
You should muteHTTPExceptions:
var response = UrlFetchApp.fetch(url,{'muteHTTPExceptions':true})
Also use arrays with fetchAll method, if you have a large number of urls to fetch.
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
add a comment |
You should muteHTTPExceptions:
var response = UrlFetchApp.fetch(url,{'muteHTTPExceptions':true})
Also use arrays with fetchAll method, if you have a large number of urls to fetch.
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
You should muteHTTPExceptions:
var response = UrlFetchApp.fetch(url,{'muteHTTPExceptions':true})
Also use arrays with fetchAll method, if you have a large number of urls to fetch.
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
answered Nov 25 '18 at 18:23
TheMasterTheMaster
10.5k3936
10.5k3936
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
add a comment |
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
I would love to use fetchAll as I have many, many URLs to check, but I can't figure out how to get all the URL list as an array. Sorry, I am just learning this stuff.
– thomaskessel
Nov 25 '18 at 19:10
add a comment |
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