If $zin S^1,zinmathbb{C}$ is then $zbar{z}^{-1}= z^2$
-1
$S^1$ denotes the unit circle.
I would appreciate a hint how I can start the proof and I'd like to know whether the statment is true.
Thank you very much.
complex-numbers
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
add a comment |
-1
$S^1$ denotes the unit circle.
I would appreciate a hint how I can start the proof and I'd like to know whether the statment is true.
Thank you very much.
complex-numbers
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
1
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25
add a comment |
-1
-1
-1
$S^1$ denotes the unit circle.
I would appreciate a hint how I can start the proof and I'd like to know whether the statment is true.
Thank you very much.
complex-numbers
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
$S^1$ denotes the unit circle.
I would appreciate a hint how I can start the proof and I'd like to know whether the statment is true.
Thank you very much.
complex-numbers
complex-numbers
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
edited Nov 29 at 15:21
Pedro Tamaroff♦
95.9k10150295
95.9k10150295
asked Nov 29 at 15:18
RM777
1928
asked Nov 29 at 15:18
RM777
1928
asked Nov 29 at 15:18
RM777
1928
1928
Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
1
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25
add a comment |
Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
1
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25
Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
1
1
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25
add a comment |
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Have you worked out the conjugate of $z$, knowing that it lies on the circle?
– Randall
Nov 29 at 15:21
Recall that for any complex number $z$ which is nonzero, $z^{-1} = bar z/|z|^2$.
– Pedro Tamaroff♦
Nov 29 at 15:21
1
This question is related to your previous one. Just set $a^2+b^2=1$.
– Shubham Johri
Nov 29 at 15:25