Making a new dictionary using the key and value with the longest length from the old one, how to increment a...

So, I have a dictionary with a bunch of keys and values, e.g.

dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

Each key has at least 2 values in my dictionary, hence maxlen = 2 below.

I want to make a new dictionary 'longest' that gets the key and its value that has the most amount of items in it's list, so 'arst' in this case.

I wrote this:

maxlen = 2



longest = {k: v for k, v in dictionary.items() if (len(v) > maxlen)}

The code above will do what I want it to if I manage to set maxlen = len(v) each time len(v) > maxlen (just like finding the maximum normally of a list or something) but how do I do that here?

So, at this part:

if (len(v) > maxlen)

I want this to happen:

len(v) = maxlen

How do I do that and can I fit that in that one line without writing a bunch of different lines or loops?

Thanks

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

2

Can you share the expected output?

– timgeb
Nov 25 '18 at 17:38

@timgeb It'd just be the key and its values that has the longest length, so longest = {'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']} in this case.

– Mandingo
Nov 25 '18 at 17:41

1

What if two keys have the same amount of elements? Do you want both in this case?

– Felix
Nov 25 '18 at 17:43

1

@Felix Yes, both.

– Mandingo
Nov 25 '18 at 17:45

1

Ok then @timgeb posted the answer already

– Felix
Nov 25 '18 at 17:47

add a comment |

So, I have a dictionary with a bunch of keys and values, e.g.

dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

Each key has at least 2 values in my dictionary, hence maxlen = 2 below.

I want to make a new dictionary 'longest' that gets the key and its value that has the most amount of items in it's list, so 'arst' in this case.

I wrote this:

maxlen = 2



longest = {k: v for k, v in dictionary.items() if (len(v) > maxlen)}

The code above will do what I want it to if I manage to set maxlen = len(v) each time len(v) > maxlen (just like finding the maximum normally of a list or something) but how do I do that here?

So, at this part:

if (len(v) > maxlen)

I want this to happen:

len(v) = maxlen

How do I do that and can I fit that in that one line without writing a bunch of different lines or loops?

Thanks

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

2

Can you share the expected output?

– timgeb
Nov 25 '18 at 17:38

@timgeb It'd just be the key and its values that has the longest length, so longest = {'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']} in this case.

– Mandingo
Nov 25 '18 at 17:41

1

What if two keys have the same amount of elements? Do you want both in this case?

– Felix
Nov 25 '18 at 17:43

1

@Felix Yes, both.

– Mandingo
Nov 25 '18 at 17:45

1

Ok then @timgeb posted the answer already

– Felix
Nov 25 '18 at 17:47

add a comment |

So, I have a dictionary with a bunch of keys and values, e.g.

dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

Each key has at least 2 values in my dictionary, hence maxlen = 2 below.

I want to make a new dictionary 'longest' that gets the key and its value that has the most amount of items in it's list, so 'arst' in this case.

I wrote this:

maxlen = 2



longest = {k: v for k, v in dictionary.items() if (len(v) > maxlen)}

The code above will do what I want it to if I manage to set maxlen = len(v) each time len(v) > maxlen (just like finding the maximum normally of a list or something) but how do I do that here?

So, at this part:

if (len(v) > maxlen)

I want this to happen:

len(v) = maxlen

How do I do that and can I fit that in that one line without writing a bunch of different lines or loops?

Thanks

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

So, I have a dictionary with a bunch of keys and values, e.g.

dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

Each key has at least 2 values in my dictionary, hence maxlen = 2 below.

I want to make a new dictionary 'longest' that gets the key and its value that has the most amount of items in it's list, so 'arst' in this case.

I wrote this:

maxlen = 2



longest = {k: v for k, v in dictionary.items() if (len(v) > maxlen)}

The code above will do what I want it to if I manage to set maxlen = len(v) each time len(v) > maxlen (just like finding the maximum normally of a list or something) but how do I do that here?

So, at this part:

if (len(v) > maxlen)

I want this to happen:

len(v) = maxlen

How do I do that and can I fit that in that one line without writing a bunch of different lines or loops?

Thanks

python dictionary

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

edited Nov 25 '18 at 17:41

asked Nov 25 '18 at 17:37

Mandingo

376212

asked Nov 25 '18 at 17:37

Mandingo

376212

asked Nov 25 '18 at 17:37

Mandingo

376212

2

Can you share the expected output?

– timgeb
Nov 25 '18 at 17:38

@timgeb It'd just be the key and its values that has the longest length, so longest = {'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']} in this case.

– Mandingo
Nov 25 '18 at 17:41

1

What if two keys have the same amount of elements? Do you want both in this case?

– Felix
Nov 25 '18 at 17:43

1

@Felix Yes, both.

– Mandingo
Nov 25 '18 at 17:45

1

Ok then @timgeb posted the answer already

– Felix
Nov 25 '18 at 17:47

add a comment |

2

Can you share the expected output?

– timgeb
Nov 25 '18 at 17:38

@timgeb It'd just be the key and its values that has the longest length, so longest = {'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']} in this case.

– Mandingo
Nov 25 '18 at 17:41

1

What if two keys have the same amount of elements? Do you want both in this case?

– Felix
Nov 25 '18 at 17:43

1

@Felix Yes, both.

– Mandingo
Nov 25 '18 at 17:45

1

Ok then @timgeb posted the answer already

– Felix
Nov 25 '18 at 17:47

Can you share the expected output?

– timgeb
Nov 25 '18 at 17:38

@timgeb It'd just be the key and its values that has the longest length, so longest = {'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']} in this case.

– Mandingo
Nov 25 '18 at 17:41

What if two keys have the same amount of elements? Do you want both in this case?

– Felix
Nov 25 '18 at 17:43

@Felix Yes, both.

– Mandingo
Nov 25 '18 at 17:45

Ok then @timgeb posted the answer already

– Felix
Nov 25 '18 at 17:47

add a comment |

1 Answer
1

active

oldest

votes

Find the length of the longest values first

>>> dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

>>> max_len = len(max(dictionary.values(), key=len)) # 7

>>> max_len

7

then filter your dictionary.

>>> {k:v for k,v in dictionary.items() if len(v) == max_len}

{'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

1

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

2

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

1

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

add a comment |

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1 Answer
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1 Answer
1

active

oldest

votes

Find the length of the longest values first

>>> dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

>>> max_len = len(max(dictionary.values(), key=len)) # 7

>>> max_len

7

then filter your dictionary.

>>> {k:v for k,v in dictionary.items() if len(v) == max_len}

{'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

1

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

2

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

1

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

add a comment |

Find the length of the longest values first

>>> dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

>>> max_len = len(max(dictionary.values(), key=len)) # 7

>>> max_len

7

then filter your dictionary.

>>> {k:v for k,v in dictionary.items() if len(v) == max_len}

{'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

1

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

2

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

1

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

add a comment |

Find the length of the longest values first

>>> dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

>>> max_len = len(max(dictionary.values(), key=len)) # 7

>>> max_len

7

then filter your dictionary.

>>> {k:v for k,v in dictionary.items() if len(v) == max_len}

{'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

Find the length of the longest values first

>>> dictionary = {'aety': ['yate', 'yeat', 'yeta'], 'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

>>> max_len = len(max(dictionary.values(), key=len)) # 7

>>> max_len

7

then filter your dictionary.

>>> {k:v for k,v in dictionary.items() if len(v) == max_len}

{'arst': ['sart', 'sart', 'star', 'star', 'stra', 'tars', 'tsar']}

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

answered Nov 25 '18 at 17:40

timgeb

51.2k116794

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

1

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

2

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

1

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

add a comment |

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

1

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

2

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

1

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

Thanks. Does this change my current dictionary? As in, can I still print out the old dictionary with all the old values before finding the maximum length and using that?

– Mandingo
Nov 25 '18 at 17:44

@Mandingo your old dictionary is not mutated, I'm building a new dictionary with the result here.

– timgeb
Nov 25 '18 at 17:46

I like max_len2 = max(map(len, dictionary.values())) even better ;-)

– Felix
Nov 25 '18 at 17:47

Thanks, it works! :)

– Mandingo
Nov 25 '18 at 17:50

@Felix I like that too. As far as performance goes, I timed it and there does not seem to be any noticeable difference.

– timgeb
Nov 25 '18 at 17:53

add a comment |

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