r - for loop returns all zeroes when segmenting a beta distribution
I am trying to segment a beta distribution, but the for loop returns a vector of zeroes:
my_vector <- vector("numeric", 11L)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob ) {
my_vector[i] <- dbeta(i, shape1=7, shape2=2)
}
my_vector
[1] 0 0 0 0 0 0 0 0 0 0 0
r for-loop
add a comment |
I am trying to segment a beta distribution, but the for loop returns a vector of zeroes:
my_vector <- vector("numeric", 11L)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob ) {
my_vector[i] <- dbeta(i, shape1=7, shape2=2)
}
my_vector
[1] 0 0 0 0 0 0 0 0 0 0 0
r for-loop
1
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g.my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52
add a comment |
I am trying to segment a beta distribution, but the for loop returns a vector of zeroes:
my_vector <- vector("numeric", 11L)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob ) {
my_vector[i] <- dbeta(i, shape1=7, shape2=2)
}
my_vector
[1] 0 0 0 0 0 0 0 0 0 0 0
r for-loop
I am trying to segment a beta distribution, but the for loop returns a vector of zeroes:
my_vector <- vector("numeric", 11L)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob ) {
my_vector[i] <- dbeta(i, shape1=7, shape2=2)
}
my_vector
[1] 0 0 0 0 0 0 0 0 0 0 0
r for-loop
r for-loop
asked Nov 25 '18 at 17:22
NottolinaNottolina
7511
7511
1
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g.my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52
add a comment |
1
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g.my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52
1
1
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g. my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g. my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52
add a comment |
1 Answer
1
active
oldest
votes
If you want to do it using the for loop, you may do it like this:
my_vector <- vector("numeric", 0)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob) {
my_vector <- c(my_vector, dbeta(i, shape1=7, shape2=2))
}
my_vector
[1] 0.0000000 0.0000504 0.0028672 0.0285768 0.1376256 0.4375000 1.0450944 1.9765032 2.9360128 2.9760696 0.0000000
Or you better follow the suggestion of @ jogo by doing it like this:
prob <- seq(from = 0.0, to = 1, by = 0.1)
my_vector <- dbeta(prob, shape1=7, shape2=2)
add a comment |
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1 Answer
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1 Answer
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active
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If you want to do it using the for loop, you may do it like this:
my_vector <- vector("numeric", 0)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob) {
my_vector <- c(my_vector, dbeta(i, shape1=7, shape2=2))
}
my_vector
[1] 0.0000000 0.0000504 0.0028672 0.0285768 0.1376256 0.4375000 1.0450944 1.9765032 2.9360128 2.9760696 0.0000000
Or you better follow the suggestion of @ jogo by doing it like this:
prob <- seq(from = 0.0, to = 1, by = 0.1)
my_vector <- dbeta(prob, shape1=7, shape2=2)
add a comment |
If you want to do it using the for loop, you may do it like this:
my_vector <- vector("numeric", 0)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob) {
my_vector <- c(my_vector, dbeta(i, shape1=7, shape2=2))
}
my_vector
[1] 0.0000000 0.0000504 0.0028672 0.0285768 0.1376256 0.4375000 1.0450944 1.9765032 2.9360128 2.9760696 0.0000000
Or you better follow the suggestion of @ jogo by doing it like this:
prob <- seq(from = 0.0, to = 1, by = 0.1)
my_vector <- dbeta(prob, shape1=7, shape2=2)
add a comment |
If you want to do it using the for loop, you may do it like this:
my_vector <- vector("numeric", 0)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob) {
my_vector <- c(my_vector, dbeta(i, shape1=7, shape2=2))
}
my_vector
[1] 0.0000000 0.0000504 0.0028672 0.0285768 0.1376256 0.4375000 1.0450944 1.9765032 2.9360128 2.9760696 0.0000000
Or you better follow the suggestion of @ jogo by doing it like this:
prob <- seq(from = 0.0, to = 1, by = 0.1)
my_vector <- dbeta(prob, shape1=7, shape2=2)
If you want to do it using the for loop, you may do it like this:
my_vector <- vector("numeric", 0)
prob <- seq(from = 0.0, to = 1, by = 0.1)
for (i in prob) {
my_vector <- c(my_vector, dbeta(i, shape1=7, shape2=2))
}
my_vector
[1] 0.0000000 0.0000504 0.0028672 0.0285768 0.1376256 0.4375000 1.0450944 1.9765032 2.9360128 2.9760696 0.0000000
Or you better follow the suggestion of @ jogo by doing it like this:
prob <- seq(from = 0.0, to = 1, by = 0.1)
my_vector <- dbeta(prob, shape1=7, shape2=2)
edited Nov 26 '18 at 15:11
answered Nov 26 '18 at 1:15
TeeKeaTeeKea
3,22851932
3,22851932
add a comment |
add a comment |
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1
my_vector <- dbeta(prob, shape1=7, shape2=2)
You can not indexing with doubles (my_vector[i]
)! e.g.my_vector[0.1]
– jogo
Nov 25 '18 at 17:33
@jogo thank you!
– Nottolina
Nov 25 '18 at 17:52