Quantifier difference
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What s the difference between $ n in Z implies n(n+1) =2k/ k in Z$ and $ forall n in Z implies n(n+1) =2k/ k in Z$
Is this true:
$ (n in Z implies n(n+1) =2k/ k in Z) implies forall n in Z; n(n+1) =2k/ k in Z$
quantifiers
asked 3 hours ago
J.Moh
395
add a comment |
up vote
0
down vote
favorite
What s the difference between $ n in Z implies n(n+1) =2k/ k in Z$ and $ forall n in Z implies n(n+1) =2k/ k in Z$
Is this true:
$ (n in Z implies n(n+1) =2k/ k in Z) implies forall n in Z; n(n+1) =2k/ k in Z$
quantifiers
asked 3 hours ago
J.Moh
395
None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
/ means such that in my case
– J.Moh
1 hour ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
What s the difference between $ n in Z implies n(n+1) =2k/ k in Z$ and $ forall n in Z implies n(n+1) =2k/ k in Z$
Is this true:
$ (n in Z implies n(n+1) =2k/ k in Z) implies forall n in Z; n(n+1) =2k/ k in Z$
quantifiers
asked 3 hours ago
J.Moh
395
What s the difference between $ n in Z implies n(n+1) =2k/ k in Z$ and $ forall n in Z implies n(n+1) =2k/ k in Z$
Is this true:
$ (n in Z implies n(n+1) =2k/ k in Z) implies forall n in Z; n(n+1) =2k/ k in Z$
quantifiers
quantifiers
asked 3 hours ago
J.Moh
395
asked 3 hours ago
J.Moh
395
edited 1 hour ago
asked 3 hours ago
J.Moh
395
asked 3 hours ago
J.Moh
395
asked 3 hours ago
J.Moh
395
395
None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
/ means such that in my case
– J.Moh
1 hour ago
add a comment |
None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
/ means such that in my case
– J.Moh
1 hour ago
None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
/ means such that in my case
– J.Moh
1 hour ago
/ means such that in my case
– J.Moh
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
The first expression is about a pair of numbers $n$ and $k$ :
$dfrac {n}{(n+1)} = 2k$.
A formula about unspecified numbers $n$ and $k$ can be either true or false, according to the values we assign to them.
Specifically, the formula is true only for $n=k=0$.
The second one is expression about a number $k$; again, its truth value depends on $k$ (and it is always false).
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
The first expression is about a pair of numbers $n$ and $k$ :
$dfrac {n}{(n+1)} = 2k$.
A formula about unspecified numbers $n$ and $k$ can be either true or false, according to the values we assign to them.
Specifically, the formula is true only for $n=k=0$.
The second one is expression about a number $k$; again, its truth value depends on $k$ (and it is always false).
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
add a comment |
up vote
0
down vote
The first expression is about a pair of numbers $n$ and $k$ :
$dfrac {n}{(n+1)} = 2k$.
A formula about unspecified numbers $n$ and $k$ can be either true or false, according to the values we assign to them.
Specifically, the formula is true only for $n=k=0$.
The second one is expression about a number $k$; again, its truth value depends on $k$ (and it is always false).
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
add a comment |
up vote
0
down vote
up vote
0
down vote
The first expression is about a pair of numbers $n$ and $k$ :
$dfrac {n}{(n+1)} = 2k$.
A formula about unspecified numbers $n$ and $k$ can be either true or false, according to the values we assign to them.
Specifically, the formula is true only for $n=k=0$.
The second one is expression about a number $k$; again, its truth value depends on $k$ (and it is always false).
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
The first expression is about a pair of numbers $n$ and $k$ :
$dfrac {n}{(n+1)} = 2k$.
A formula about unspecified numbers $n$ and $k$ can be either true or false, according to the values we assign to them.
Specifically, the formula is true only for $n=k=0$.
The second one is expression about a number $k$; again, its truth value depends on $k$ (and it is always false).
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
edited 1 hour ago
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
answered 2 hours ago
Mauro ALLEGRANZA
63.3k448110
63.3k448110
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
add a comment |
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
/ doesn t mean division in my case, it means such that
– J.Moh
1 hour ago
add a comment |
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None, in that I cannot understand either: why have you introduced a $k$, only to use it in the expression $2k/k$ which merely simplifies to $2$?
– Lord Shark the Unknown
2 hours ago
/ means such that in my case
– J.Moh
1 hour ago