Compare two lists of different types using HashMap











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2
down vote

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I have two classes:



public class AClass{

String name;
int id;
int total;
}

public class BClass{
String batchName;
int id;
}


Now I have two lists:



List<AClass> aLst;
List<BClass> bLst;


Between these two list i need to check if AClass.id==BClass.id.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.



Other way is by using HashMap. Traverse the BClass list and use the BClass.id as the key and the respective object as the value:



Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}

foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}


Is this efficient way to compare?










share|improve this question
























  • You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
    – amn
    Nov 19 at 19:34












  • Are you looking just for missing ids or for entire objects?
    – Karol Dowbecki
    Nov 19 at 19:52










  • I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
    – James Patty
    Nov 19 at 20:36










  • We can safely assume that IDs are unquie...
    – James Patty
    Nov 19 at 20:37















up vote
2
down vote

favorite












I have two classes:



public class AClass{

String name;
int id;
int total;
}

public class BClass{
String batchName;
int id;
}


Now I have two lists:



List<AClass> aLst;
List<BClass> bLst;


Between these two list i need to check if AClass.id==BClass.id.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.



Other way is by using HashMap. Traverse the BClass list and use the BClass.id as the key and the respective object as the value:



Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}

foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}


Is this efficient way to compare?










share|improve this question
























  • You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
    – amn
    Nov 19 at 19:34












  • Are you looking just for missing ids or for entire objects?
    – Karol Dowbecki
    Nov 19 at 19:52










  • I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
    – James Patty
    Nov 19 at 20:36










  • We can safely assume that IDs are unquie...
    – James Patty
    Nov 19 at 20:37













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I have two classes:



public class AClass{

String name;
int id;
int total;
}

public class BClass{
String batchName;
int id;
}


Now I have two lists:



List<AClass> aLst;
List<BClass> bLst;


Between these two list i need to check if AClass.id==BClass.id.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.



Other way is by using HashMap. Traverse the BClass list and use the BClass.id as the key and the respective object as the value:



Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}

foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}


Is this efficient way to compare?










share|improve this question















I have two classes:



public class AClass{

String name;
int id;
int total;
}

public class BClass{
String batchName;
int id;
}


Now I have two lists:



List<AClass> aLst;
List<BClass> bLst;


Between these two list i need to check if AClass.id==BClass.id.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.



Other way is by using HashMap. Traverse the BClass list and use the BClass.id as the key and the respective object as the value:



Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}

foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}


Is this efficient way to compare?







java arraylist collections hashmap processing-efficiency






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 at 21:13









Karol Dowbecki

14k72745




14k72745










asked Nov 19 at 19:30









James Patty

111




111












  • You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
    – amn
    Nov 19 at 19:34












  • Are you looking just for missing ids or for entire objects?
    – Karol Dowbecki
    Nov 19 at 19:52










  • I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
    – James Patty
    Nov 19 at 20:36










  • We can safely assume that IDs are unquie...
    – James Patty
    Nov 19 at 20:37


















  • You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
    – amn
    Nov 19 at 19:34












  • Are you looking just for missing ids or for entire objects?
    – Karol Dowbecki
    Nov 19 at 19:52










  • I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
    – James Patty
    Nov 19 at 20:36










  • We can safely assume that IDs are unquie...
    – James Patty
    Nov 19 at 20:37
















You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34






You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34














Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52




Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52












I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36




I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36












We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37




We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37












1 Answer
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up vote
2
down vote













It would be easier with a Set<Integer> to store the identifiers from AClass. Since Set.contains() is O(1) the total complexity will be O(n).



List<AClass> aLst = ...;
List<BClass> bLst = ...;

Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());


However for small lists the cost of creating additional Set and boxing identifiers into Integer might outweigh the benefit of reduced number of iterations.






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    1 Answer
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    1 Answer
    1






    active

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    active

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    up vote
    2
    down vote













    It would be easier with a Set<Integer> to store the identifiers from AClass. Since Set.contains() is O(1) the total complexity will be O(n).



    List<AClass> aLst = ...;
    List<BClass> bLst = ...;

    Set<Integer> ids = aLst.stream()
    .map(AClass::getId)
    .collect(Collectors.toSet());
    List<BClass> required = bLst.stream()
    .filter(b -> ids.contains(b.getId()))
    .collect(Collectors.toList());


    However for small lists the cost of creating additional Set and boxing identifiers into Integer might outweigh the benefit of reduced number of iterations.






    share|improve this answer

























      up vote
      2
      down vote













      It would be easier with a Set<Integer> to store the identifiers from AClass. Since Set.contains() is O(1) the total complexity will be O(n).



      List<AClass> aLst = ...;
      List<BClass> bLst = ...;

      Set<Integer> ids = aLst.stream()
      .map(AClass::getId)
      .collect(Collectors.toSet());
      List<BClass> required = bLst.stream()
      .filter(b -> ids.contains(b.getId()))
      .collect(Collectors.toList());


      However for small lists the cost of creating additional Set and boxing identifiers into Integer might outweigh the benefit of reduced number of iterations.






      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        It would be easier with a Set<Integer> to store the identifiers from AClass. Since Set.contains() is O(1) the total complexity will be O(n).



        List<AClass> aLst = ...;
        List<BClass> bLst = ...;

        Set<Integer> ids = aLst.stream()
        .map(AClass::getId)
        .collect(Collectors.toSet());
        List<BClass> required = bLst.stream()
        .filter(b -> ids.contains(b.getId()))
        .collect(Collectors.toList());


        However for small lists the cost of creating additional Set and boxing identifiers into Integer might outweigh the benefit of reduced number of iterations.






        share|improve this answer












        It would be easier with a Set<Integer> to store the identifiers from AClass. Since Set.contains() is O(1) the total complexity will be O(n).



        List<AClass> aLst = ...;
        List<BClass> bLst = ...;

        Set<Integer> ids = aLst.stream()
        .map(AClass::getId)
        .collect(Collectors.toSet());
        List<BClass> required = bLst.stream()
        .filter(b -> ids.contains(b.getId()))
        .collect(Collectors.toList());


        However for small lists the cost of creating additional Set and boxing identifiers into Integer might outweigh the benefit of reduced number of iterations.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 at 20:06









        Karol Dowbecki

        14k72745




        14k72745






























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