Compare two lists of different types using HashMap
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2
down vote
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I have two classes:
public class AClass{
String name;
int id;
int total;
}
public class BClass{
String batchName;
int id;
}
Now I have two lists:
List<AClass> aLst;
List<BClass> bLst;
Between these two list i need to check if AClass.id==BClass.id
.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.
Other way is by using HashMap
. Traverse the BClass
list and use the BClass.id
as the key and the respective object as the value:
Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}
foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}
Is this efficient way to compare?
java arraylist collections hashmap processing-efficiency
add a comment |
up vote
2
down vote
favorite
I have two classes:
public class AClass{
String name;
int id;
int total;
}
public class BClass{
String batchName;
int id;
}
Now I have two lists:
List<AClass> aLst;
List<BClass> bLst;
Between these two list i need to check if AClass.id==BClass.id
.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.
Other way is by using HashMap
. Traverse the BClass
list and use the BClass.id
as the key and the respective object as the value:
Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}
foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}
Is this efficient way to compare?
java arraylist collections hashmap processing-efficiency
You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have two classes:
public class AClass{
String name;
int id;
int total;
}
public class BClass{
String batchName;
int id;
}
Now I have two lists:
List<AClass> aLst;
List<BClass> bLst;
Between these two list i need to check if AClass.id==BClass.id
.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.
Other way is by using HashMap
. Traverse the BClass
list and use the BClass.id
as the key and the respective object as the value:
Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}
foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}
Is this efficient way to compare?
java arraylist collections hashmap processing-efficiency
I have two classes:
public class AClass{
String name;
int id;
int total;
}
public class BClass{
String batchName;
int id;
}
Now I have two lists:
List<AClass> aLst;
List<BClass> bLst;
Between these two list i need to check if AClass.id==BClass.id
.
One way to achieve this is to have two for loops and compare. But this is not the efficient way.
Other way is by using HashMap
. Traverse the BClass
list and use the BClass.id
as the key and the respective object as the value:
Map<int,BClass> map = new HashMap<int,BClass>();
List requiredLst <BClass> = new ArrayList<BClass>();
foreach(BClass b : bLst){
map.put(BClass.id, b);
}
foreach(AClass a : aLst){
BClass b = map.get(a.id);
requiredLst.add(b);
}
Is this efficient way to compare?
java arraylist collections hashmap processing-efficiency
java arraylist collections hashmap processing-efficiency
edited Nov 19 at 21:13
Karol Dowbecki
14k72745
14k72745
asked Nov 19 at 19:30
James Patty
111
111
You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37
add a comment |
You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37
You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
It would be easier with a Set<Integer>
to store the identifiers from AClass
. Since Set.contains()
is O(1) the total complexity will be O(n).
List<AClass> aLst = ...;
List<BClass> bLst = ...;
Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());
However for small lists the cost of creating additional Set
and boxing identifiers into Integer
might outweigh the benefit of reduced number of iterations.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
It would be easier with a Set<Integer>
to store the identifiers from AClass
. Since Set.contains()
is O(1) the total complexity will be O(n).
List<AClass> aLst = ...;
List<BClass> bLst = ...;
Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());
However for small lists the cost of creating additional Set
and boxing identifiers into Integer
might outweigh the benefit of reduced number of iterations.
add a comment |
up vote
2
down vote
It would be easier with a Set<Integer>
to store the identifiers from AClass
. Since Set.contains()
is O(1) the total complexity will be O(n).
List<AClass> aLst = ...;
List<BClass> bLst = ...;
Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());
However for small lists the cost of creating additional Set
and boxing identifiers into Integer
might outweigh the benefit of reduced number of iterations.
add a comment |
up vote
2
down vote
up vote
2
down vote
It would be easier with a Set<Integer>
to store the identifiers from AClass
. Since Set.contains()
is O(1) the total complexity will be O(n).
List<AClass> aLst = ...;
List<BClass> bLst = ...;
Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());
However for small lists the cost of creating additional Set
and boxing identifiers into Integer
might outweigh the benefit of reduced number of iterations.
It would be easier with a Set<Integer>
to store the identifiers from AClass
. Since Set.contains()
is O(1) the total complexity will be O(n).
List<AClass> aLst = ...;
List<BClass> bLst = ...;
Set<Integer> ids = aLst.stream()
.map(AClass::getId)
.collect(Collectors.toSet());
List<BClass> required = bLst.stream()
.filter(b -> ids.contains(b.getId()))
.collect(Collectors.toList());
However for small lists the cost of creating additional Set
and boxing identifiers into Integer
might outweigh the benefit of reduced number of iterations.
answered Nov 19 at 20:06
Karol Dowbecki
14k72745
14k72745
add a comment |
add a comment |
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You haven't sufficiently described the actual comparison procedure. What does the procedure return, a boolean? What if the 5th element in the first list has the same id as the 13th element in the second list?
– amn
Nov 19 at 19:34
Are you looking just for missing ids or for entire objects?
– Karol Dowbecki
Nov 19 at 19:52
I am looking for all the objects of BClass in bLst having the same id's as that of the ids in the AClass objects ..
– James Patty
Nov 19 at 20:36
We can safely assume that IDs are unquie...
– James Patty
Nov 19 at 20:37