How can a strict subset of a probability space be collectively exhaustive?
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In the example given in this text, I am given 4 possible events in a space. Then I am told that two of the events are collectively exhaustive. How is this remotely possible?
Please help.
probability probability-theory
asked Nov 23 at 17:00
Kohler Fryer
1031
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In the example given in this text, I am given 4 possible events in a space. Then I am told that two of the events are collectively exhaustive. How is this remotely possible?
Please help.
probability probability-theory
asked Nov 23 at 17:00
Kohler Fryer
1031
2
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
In the example given in this text, I am given 4 possible events in a space. Then I am told that two of the events are collectively exhaustive. How is this remotely possible?
Please help.
probability probability-theory
asked Nov 23 at 17:00
Kohler Fryer
1031
In the example given in this text, I am given 4 possible events in a space. Then I am told that two of the events are collectively exhaustive. How is this remotely possible?
Please help.
probability probability-theory
probability probability-theory
asked Nov 23 at 17:00
Kohler Fryer
1031
asked Nov 23 at 17:00
Kohler Fryer
1031
asked Nov 23 at 17:00
Kohler Fryer
1031
asked Nov 23 at 17:00
Kohler Fryer
1031
asked Nov 23 at 17:00
Kohler Fryer
1031
1031
2
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12
add a comment |
2
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12
2
2
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12
add a comment |
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2
Everyone is either healthy or diseased. What's the problem?
– saulspatz
Nov 23 at 17:03
The probability space defined in the question consists of 4 events: disease present, healthy, positive test, and negative test. The union of the events healthy and disease does not result in the probability space defined thus cannot be collectively exhaustive.
– Kohler Fryer
Nov 23 at 17:12