Restriction of generator of a semigroup
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If an operator $A$ generates a semigroup on $L^2(Omega)$, can we say that its restriction on $L^infty(Omega)$ is m-dissipatif ?
Thank you.
pde semigroup-of-operators
edited Nov 25 at 4:05
Pedro
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asked Nov 23 at 17:10
Gustave
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If an operator $A$ generates a semigroup on $L^2(Omega)$, can we say that its restriction on $L^infty(Omega)$ is m-dissipatif ?
Thank you.
pde semigroup-of-operators
edited Nov 25 at 4:05
Pedro
10.2k23066
asked Nov 23 at 17:10
Gustave
686211
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If an operator $A$ generates a semigroup on $L^2(Omega)$, can we say that its restriction on $L^infty(Omega)$ is m-dissipatif ?
Thank you.
pde semigroup-of-operators
edited Nov 25 at 4:05
Pedro
10.2k23066
asked Nov 23 at 17:10
Gustave
686211
If an operator $A$ generates a semigroup on $L^2(Omega)$, can we say that its restriction on $L^infty(Omega)$ is m-dissipatif ?
Thank you.
pde semigroup-of-operators
pde semigroup-of-operators
edited Nov 25 at 4:05
Pedro
10.2k23066
asked Nov 23 at 17:10
Gustave
686211
edited Nov 25 at 4:05
Pedro
10.2k23066
asked Nov 23 at 17:10
Gustave
686211
edited Nov 25 at 4:05
Pedro
10.2k23066
edited Nov 25 at 4:05
Pedro
10.2k23066
edited Nov 25 at 4:05
Pedro
10.2k23066
10.2k23066
asked Nov 23 at 17:10
Gustave
686211
asked Nov 23 at 17:10
Gustave
686211
asked Nov 23 at 17:10
Gustave
686211
686211
add a comment |
add a comment |
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