Example of non-abelian groups with these properties
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I am looking for examples of non-abelian groups of arbitrarily large size with the following properties
- Have order $p^a$, where $a$ is a positive integer and $p$ is prime.
- Contain an abelian subgroup of order $p^{a-2}$.
I know one example which is the quaternion group. I am looking for more examples of groups of arbitrarily large size.
group-theory finite-groups p-groups
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I am looking for examples of non-abelian groups of arbitrarily large size with the following properties
- Have order $p^a$, where $a$ is a positive integer and $p$ is prime.
- Contain an abelian subgroup of order $p^{a-2}$.
I know one example which is the quaternion group. I am looking for more examples of groups of arbitrarily large size.
group-theory finite-groups p-groups
1
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05
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up vote
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down vote
favorite
I am looking for examples of non-abelian groups of arbitrarily large size with the following properties
- Have order $p^a$, where $a$ is a positive integer and $p$ is prime.
- Contain an abelian subgroup of order $p^{a-2}$.
I know one example which is the quaternion group. I am looking for more examples of groups of arbitrarily large size.
group-theory finite-groups p-groups
I am looking for examples of non-abelian groups of arbitrarily large size with the following properties
- Have order $p^a$, where $a$ is a positive integer and $p$ is prime.
- Contain an abelian subgroup of order $p^{a-2}$.
I know one example which is the quaternion group. I am looking for more examples of groups of arbitrarily large size.
group-theory finite-groups p-groups
group-theory finite-groups p-groups
edited Nov 26 at 12:58
the_fox
2,3191430
2,3191430
asked Nov 26 at 12:25
I_wil_break_wall
203
203
1
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05
add a comment |
1
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05
1
1
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05
add a comment |
2 Answers
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Take, for example, the direct product of a nonabelian group of order $p^3$ with an abelian group of order $p^{a-3}$.
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Dihedral groups of order $2^a$ have both properties (the subgroup being the cyclic one generated by the square of a highest-order element), but they also have a larger abelian subgroup of order $2^{a-1}$, so might not be what you're after.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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active
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votes
up vote
1
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accepted
Take, for example, the direct product of a nonabelian group of order $p^3$ with an abelian group of order $p^{a-3}$.
add a comment |
up vote
1
down vote
accepted
Take, for example, the direct product of a nonabelian group of order $p^3$ with an abelian group of order $p^{a-3}$.
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Take, for example, the direct product of a nonabelian group of order $p^3$ with an abelian group of order $p^{a-3}$.
Take, for example, the direct product of a nonabelian group of order $p^3$ with an abelian group of order $p^{a-3}$.
answered Nov 26 at 12:53
user10354138
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Dihedral groups of order $2^a$ have both properties (the subgroup being the cyclic one generated by the square of a highest-order element), but they also have a larger abelian subgroup of order $2^{a-1}$, so might not be what you're after.
add a comment |
up vote
0
down vote
Dihedral groups of order $2^a$ have both properties (the subgroup being the cyclic one generated by the square of a highest-order element), but they also have a larger abelian subgroup of order $2^{a-1}$, so might not be what you're after.
add a comment |
up vote
0
down vote
up vote
0
down vote
Dihedral groups of order $2^a$ have both properties (the subgroup being the cyclic one generated by the square of a highest-order element), but they also have a larger abelian subgroup of order $2^{a-1}$, so might not be what you're after.
Dihedral groups of order $2^a$ have both properties (the subgroup being the cyclic one generated by the square of a highest-order element), but they also have a larger abelian subgroup of order $2^{a-1}$, so might not be what you're after.
answered Nov 26 at 12:52
user3482749
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1
There are too many examples. You need to impose some more restrictions.
– Derek Holt
Nov 26 at 13:05