Python websocket connect and listen to incoming messages
up vote
0
down vote
favorite
I can't find a very simple example how to do websocket connect in python, and provide some on_message callback that listens to incoming messages.
So the websocket has create_connection method to create a connection, but I don't see where I can pass a callback function that will be called each time the other side send messages to me.
I am creating a simple python websocket proxy/relay, so every time a client is connected to my server, I want to create a connection to another server, and then listen to incoming messages so I can pass them back to the client.
python websocket server proxy relay
asked Nov 20 at 10:31
Nadav B
508611
add a comment |
up vote
0
down vote
favorite
I can't find a very simple example how to do websocket connect in python, and provide some on_message callback that listens to incoming messages.
So the websocket has create_connection method to create a connection, but I don't see where I can pass a callback function that will be called each time the other side send messages to me.
I am creating a simple python websocket proxy/relay, so every time a client is connected to my server, I want to create a connection to another server, and then listen to incoming messages so I can pass them back to the client.
python websocket server proxy relay
asked Nov 20 at 10:31
Nadav B
508611
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I can't find a very simple example how to do websocket connect in python, and provide some on_message callback that listens to incoming messages.
So the websocket has create_connection method to create a connection, but I don't see where I can pass a callback function that will be called each time the other side send messages to me.
I am creating a simple python websocket proxy/relay, so every time a client is connected to my server, I want to create a connection to another server, and then listen to incoming messages so I can pass them back to the client.
python websocket server proxy relay
asked Nov 20 at 10:31
Nadav B
508611
I can't find a very simple example how to do websocket connect in python, and provide some on_message callback that listens to incoming messages.
So the websocket has create_connection method to create a connection, but I don't see where I can pass a callback function that will be called each time the other side send messages to me.
I am creating a simple python websocket proxy/relay, so every time a client is connected to my server, I want to create a connection to another server, and then listen to incoming messages so I can pass them back to the client.
python websocket server proxy relay
python websocket server proxy relay
asked Nov 20 at 10:31
Nadav B
508611
asked Nov 20 at 10:31
Nadav B
508611
asked Nov 20 at 10:31
Nadav B
508611
asked Nov 20 at 10:31
Nadav B
508611
asked Nov 20 at 10:31
Nadav B
508611
508611
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06
add a comment |
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
So I managed to do it this way. I hope that's the optimal way to do so.
ws = create_connection(url)
def run(*args):
while True:
try:
message = ws.recv() # This is blocking
# do what I need to do here
except WebSocketClosedError:
break
thread.start_new_thread(run, ())
answered Nov 20 at 11:13
Nadav B
508611
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53391017%2fpython-websocket-connect-and-listen-to-incoming-messages%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
So I managed to do it this way. I hope that's the optimal way to do so.
ws = create_connection(url)
def run(*args):
while True:
try:
message = ws.recv() # This is blocking
# do what I need to do here
except WebSocketClosedError:
break
thread.start_new_thread(run, ())
answered Nov 20 at 11:13
Nadav B
508611
add a comment |
up vote
0
down vote
So I managed to do it this way. I hope that's the optimal way to do so.
ws = create_connection(url)
def run(*args):
while True:
try:
message = ws.recv() # This is blocking
# do what I need to do here
except WebSocketClosedError:
break
thread.start_new_thread(run, ())
answered Nov 20 at 11:13
Nadav B
508611
add a comment |
up vote
0
down vote
up vote
0
down vote
So I managed to do it this way. I hope that's the optimal way to do so.
ws = create_connection(url)
def run(*args):
while True:
try:
message = ws.recv() # This is blocking
# do what I need to do here
except WebSocketClosedError:
break
thread.start_new_thread(run, ())
answered Nov 20 at 11:13
Nadav B
508611
So I managed to do it this way. I hope that's the optimal way to do so.
ws = create_connection(url)
def run(*args):
while True:
try:
message = ws.recv() # This is blocking
# do what I need to do here
except WebSocketClosedError:
break
thread.start_new_thread(run, ())
answered Nov 20 at 11:13
Nadav B
508611
answered Nov 20 at 11:13
Nadav B
508611
answered Nov 20 at 11:13
Nadav B
508611
answered Nov 20 at 11:13
Nadav B
508611
508611
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53391017%2fpython-websocket-connect-and-listen-to-incoming-messages%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1. add some code. 2. which lib are you using? 3. the problem is with the client or with the server?
– Dekel
Nov 20 at 11:06