Extending Dictionary of key : String value:Array in swift
up vote
1
down vote
favorite
How can I extend a Swift Dictionary of type [String:[Double]]?
What is the protocol/Class_Type to be conformed by the Value while extending the dictionary?
[ P.S : In this Extension I want to return all the keys whose value arrays contains a particular element(Double) that is send to the function.]
swift dictionary protocols extension-methods
edited Nov 20 at 15:04
timgeb
48k116390
asked Nov 20 at 10:42
Siva Athi
83
add a comment |
up vote
1
down vote
favorite
How can I extend a Swift Dictionary of type [String:[Double]]?
What is the protocol/Class_Type to be conformed by the Value while extending the dictionary?
[ P.S : In this Extension I want to return all the keys whose value arrays contains a particular element(Double) that is send to the function.]
swift dictionary protocols extension-methods
edited Nov 20 at 15:04
timgeb
48k116390
asked Nov 20 at 10:42
Siva Athi
83
So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
How can I extend a Swift Dictionary of type [String:[Double]]?
What is the protocol/Class_Type to be conformed by the Value while extending the dictionary?
[ P.S : In this Extension I want to return all the keys whose value arrays contains a particular element(Double) that is send to the function.]
swift dictionary protocols extension-methods
edited Nov 20 at 15:04
timgeb
48k116390
asked Nov 20 at 10:42
Siva Athi
83
How can I extend a Swift Dictionary of type [String:[Double]]?
What is the protocol/Class_Type to be conformed by the Value while extending the dictionary?
[ P.S : In this Extension I want to return all the keys whose value arrays contains a particular element(Double) that is send to the function.]
swift dictionary protocols extension-methods
swift dictionary protocols extension-methods
edited Nov 20 at 15:04
timgeb
48k116390
asked Nov 20 at 10:42
Siva Athi
83
edited Nov 20 at 15:04
timgeb
48k116390
asked Nov 20 at 10:42
Siva Athi
83
edited Nov 20 at 15:04
timgeb
48k116390
edited Nov 20 at 15:04
timgeb
48k116390
edited Nov 20 at 15:04
timgeb
48k116390
48k116390
asked Nov 20 at 10:42
Siva Athi
83
asked Nov 20 at 10:42
Siva Athi
83
asked Nov 20 at 10:42
Siva Athi
83
83
So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13
add a comment |
So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13
So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Dictionaries have two generic elements Key and Value that need constraining when you create your extension.
You can do that like so:
public extension Dictionary where Key == String, Value == [Double] { }
answered Nov 20 at 11:25
royalmurder
13010
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
add a comment |
up vote
0
down vote
You can use filter to do that like below:
let dictData = ["a":[1.0,2.0,3.0],
"b":[1.0,112.0,3.0],
"c":[7.0,12.0,3.0]]
let filterData = dictData.filter({$0.value.contains(1)})
print(filterData.keys) //output: ["a", "b"]
You can itrate this array like this:
for keys in filterData.keys.makeIterator() {
print(keys)
}
Or you can directly access like this:
filterData.keys.first
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Dictionaries have two generic elements Key and Value that need constraining when you create your extension.
You can do that like so:
public extension Dictionary where Key == String, Value == [Double] { }
answered Nov 20 at 11:25
royalmurder
13010
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
add a comment |
up vote
1
down vote
accepted
Dictionaries have two generic elements Key and Value that need constraining when you create your extension.
You can do that like so:
public extension Dictionary where Key == String, Value == [Double] { }
answered Nov 20 at 11:25
royalmurder
13010
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Dictionaries have two generic elements Key and Value that need constraining when you create your extension.
You can do that like so:
public extension Dictionary where Key == String, Value == [Double] { }
answered Nov 20 at 11:25
royalmurder
13010
Dictionaries have two generic elements Key and Value that need constraining when you create your extension.
You can do that like so:
public extension Dictionary where Key == String, Value == [Double] { }
answered Nov 20 at 11:25
royalmurder
13010
edited Nov 20 at 12:46
answered Nov 20 at 11:25
royalmurder
13010
answered Nov 20 at 11:25
royalmurder
13010
answered Nov 20 at 11:25
royalmurder
13010
13010
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
add a comment |
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
Thank You, This Works fine!
– Siva Athi
Nov 20 at 13:54
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
@SivaAthi if you've found an answer that resolves your question, try to remember to mark it as the accepted answer! You'll get a small reputation boost, as well as helping other readers with the same problem get to the solution faster!
– royalmurder
Nov 21 at 13:59
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
Sorry that I forget it.
– Siva Athi
Nov 26 at 6:52
add a comment |
up vote
0
down vote
You can use filter to do that like below:
let dictData = ["a":[1.0,2.0,3.0],
"b":[1.0,112.0,3.0],
"c":[7.0,12.0,3.0]]
let filterData = dictData.filter({$0.value.contains(1)})
print(filterData.keys) //output: ["a", "b"]
You can itrate this array like this:
for keys in filterData.keys.makeIterator() {
print(keys)
}
Or you can directly access like this:
filterData.keys.first
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
add a comment |
up vote
0
down vote
You can use filter to do that like below:
let dictData = ["a":[1.0,2.0,3.0],
"b":[1.0,112.0,3.0],
"c":[7.0,12.0,3.0]]
let filterData = dictData.filter({$0.value.contains(1)})
print(filterData.keys) //output: ["a", "b"]
You can itrate this array like this:
for keys in filterData.keys.makeIterator() {
print(keys)
}
Or you can directly access like this:
filterData.keys.first
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use filter to do that like below:
let dictData = ["a":[1.0,2.0,3.0],
"b":[1.0,112.0,3.0],
"c":[7.0,12.0,3.0]]
let filterData = dictData.filter({$0.value.contains(1)})
print(filterData.keys) //output: ["a", "b"]
You can itrate this array like this:
for keys in filterData.keys.makeIterator() {
print(keys)
}
Or you can directly access like this:
filterData.keys.first
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
You can use filter to do that like below:
let dictData = ["a":[1.0,2.0,3.0],
"b":[1.0,112.0,3.0],
"c":[7.0,12.0,3.0]]
let filterData = dictData.filter({$0.value.contains(1)})
print(filterData.keys) //output: ["a", "b"]
You can itrate this array like this:
for keys in filterData.keys.makeIterator() {
print(keys)
}
Or you can directly access like this:
filterData.keys.first
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
edited Nov 20 at 11:19
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
answered Nov 20 at 10:59
Jogendar Choudhary
2,3241518
2,3241518
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
add a comment |
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
yes, That Works!! But also I would like to know how to extend this type of Dictionary, Primarily.
– Siva Athi
Nov 20 at 11:12
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
@SivaAthi: I have updated answer Please have a look
– Jogendar Choudhary
Nov 20 at 11:20
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
Yeah, Taken care of. Thank you for the Update :)
– Siva Athi
Nov 21 at 7:09
add a comment |
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So you want to filter a dictionary to find keys that contain a particular double value?
– Scriptable
Nov 20 at 10:44
Welcome to stackoverflow.com. Please take some time to read the help pages, especially the sections named "What topics can I ask about here?" and "What types of questions should I avoid asking?". Also please take the tour and read about how to ask good questions. Lastly please read this question checklist.
– Spangen
Nov 20 at 10:46
Yes, I know how to Find the keys, But Primarily I need to know How Extend this type of Dictionary.
– Siva Athi
Nov 20 at 11:13