Polynomials satisfying condition $P(x^2)=P(-x)P(x)$. [closed]











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I need some help in finding out the number of polynomials P having degree 4 with real coefficients such that $P(x^2)=P(-x)P(x)$. Please don't use the brute force method of checking every condition established by the general equation.










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closed as off-topic by GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3 Nov 25 at 16:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 4




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Nov 25 at 16:22






  • 1




    @RudrakshJ: Please share with us what you have done.
    – Yadati Kiran
    Nov 25 at 16:23










  • @hamam_Abdallah $1-x$ is not of degree $4$
    – saulspatz
    Nov 25 at 16:30










  • $x^4$ is a solution.
    – hamam_Abdallah
    Nov 25 at 16:32












  • BTW, to edit your question, you can click the word "edit" below the question itself.
    – John Hughes
    Nov 25 at 16:37















up vote
1
down vote

favorite
1












I need some help in finding out the number of polynomials P having degree 4 with real coefficients such that $P(x^2)=P(-x)P(x)$. Please don't use the brute force method of checking every condition established by the general equation.










share|cite|improve this question















closed as off-topic by GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3 Nov 25 at 16:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 4




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Nov 25 at 16:22






  • 1




    @RudrakshJ: Please share with us what you have done.
    – Yadati Kiran
    Nov 25 at 16:23










  • @hamam_Abdallah $1-x$ is not of degree $4$
    – saulspatz
    Nov 25 at 16:30










  • $x^4$ is a solution.
    – hamam_Abdallah
    Nov 25 at 16:32












  • BTW, to edit your question, you can click the word "edit" below the question itself.
    – John Hughes
    Nov 25 at 16:37













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
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1





I need some help in finding out the number of polynomials P having degree 4 with real coefficients such that $P(x^2)=P(-x)P(x)$. Please don't use the brute force method of checking every condition established by the general equation.










share|cite|improve this question















I need some help in finding out the number of polynomials P having degree 4 with real coefficients such that $P(x^2)=P(-x)P(x)$. Please don't use the brute force method of checking every condition established by the general equation.







algebra-precalculus polynomials






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edited Nov 25 at 16:30









Yadati Kiran

1,289417




1,289417










asked Nov 25 at 16:21









RudrakshJ

122




122




closed as off-topic by GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3 Nov 25 at 16:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3 Nov 25 at 16:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – GNUSupporter 8964民主女神 地下教會, Ennar, greedoid, John Hughes, kingW3

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Nov 25 at 16:22






  • 1




    @RudrakshJ: Please share with us what you have done.
    – Yadati Kiran
    Nov 25 at 16:23










  • @hamam_Abdallah $1-x$ is not of degree $4$
    – saulspatz
    Nov 25 at 16:30










  • $x^4$ is a solution.
    – hamam_Abdallah
    Nov 25 at 16:32












  • BTW, to edit your question, you can click the word "edit" below the question itself.
    – John Hughes
    Nov 25 at 16:37














  • 4




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Nov 25 at 16:22






  • 1




    @RudrakshJ: Please share with us what you have done.
    – Yadati Kiran
    Nov 25 at 16:23










  • @hamam_Abdallah $1-x$ is not of degree $4$
    – saulspatz
    Nov 25 at 16:30










  • $x^4$ is a solution.
    – hamam_Abdallah
    Nov 25 at 16:32












  • BTW, to edit your question, you can click the word "edit" below the question itself.
    – John Hughes
    Nov 25 at 16:37








4




4




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Nov 25 at 16:22




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Nov 25 at 16:22




1




1




@RudrakshJ: Please share with us what you have done.
– Yadati Kiran
Nov 25 at 16:23




@RudrakshJ: Please share with us what you have done.
– Yadati Kiran
Nov 25 at 16:23












@hamam_Abdallah $1-x$ is not of degree $4$
– saulspatz
Nov 25 at 16:30




@hamam_Abdallah $1-x$ is not of degree $4$
– saulspatz
Nov 25 at 16:30












$x^4$ is a solution.
– hamam_Abdallah
Nov 25 at 16:32






$x^4$ is a solution.
– hamam_Abdallah
Nov 25 at 16:32














BTW, to edit your question, you can click the word "edit" below the question itself.
– John Hughes
Nov 25 at 16:37




BTW, to edit your question, you can click the word "edit" below the question itself.
– John Hughes
Nov 25 at 16:37










1 Answer
1






active

oldest

votes

















up vote
0
down vote













hint



Assume $P(0)=0$
then
$$P(x)=xQ(x)$$
with



$$Q(x^2)=-Q(x)Q(-x)$$






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    hint



    Assume $P(0)=0$
    then
    $$P(x)=xQ(x)$$
    with



    $$Q(x^2)=-Q(x)Q(-x)$$






    share|cite|improve this answer

























      up vote
      0
      down vote













      hint



      Assume $P(0)=0$
      then
      $$P(x)=xQ(x)$$
      with



      $$Q(x^2)=-Q(x)Q(-x)$$






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        hint



        Assume $P(0)=0$
        then
        $$P(x)=xQ(x)$$
        with



        $$Q(x^2)=-Q(x)Q(-x)$$






        share|cite|improve this answer












        hint



        Assume $P(0)=0$
        then
        $$P(x)=xQ(x)$$
        with



        $$Q(x^2)=-Q(x)Q(-x)$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 25 at 16:31









        hamam_Abdallah

        37.5k21634




        37.5k21634















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