Python Caesar Cipher Incrementing Problem











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My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.



An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'



I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"



def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)

def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1


I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.










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  • I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
    – Sam Mason
    Nov 19 at 20:30















up vote
0
down vote

favorite












My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.



An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'



I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"



def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)

def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1


I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.










share|improve this question






















  • I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
    – Sam Mason
    Nov 19 at 20:30













up vote
0
down vote

favorite









up vote
0
down vote

favorite











My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.



An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'



I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"



def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)

def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1


I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.










share|improve this question













My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.



An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'



I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"



def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)

def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1


I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.







python






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asked Nov 19 at 20:03









Johnathan

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  • I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
    – Sam Mason
    Nov 19 at 20:30


















  • I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
    – Sam Mason
    Nov 19 at 20:30
















I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
– Sam Mason
Nov 19 at 20:30




I'd go with Patrick's suggestion from your last question: change key to accept two parameters, the text you want to encrypt and the rotation/key you want to use
– Sam Mason
Nov 19 at 20:30

















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