Python Caesar Cipher Incrementing Problem
up vote
0
down vote
favorite
My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.
An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'
I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"
def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)
def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1
I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.
python
add a comment |
up vote
0
down vote
favorite
My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.
An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'
I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"
def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)
def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1
I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.
python
I'd go with Patrick's suggestion from your last question: changekeyto accept two parameters, the text you want to encrypt and the rotation/key you want to use
– Sam Mason
Nov 19 at 20:30
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.
An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'
I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"
def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)
def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1
I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.
python
My task is to prompt a user for a string to decode, and a plain-text word that appears in the decoded string. The output should be the key needed to decode the string and the decoded string itself.
An example:
If the encoded string is: khoor zruog and the plain-text word is: hello
The program should work out the rotation was 3 and the decoded string is 'hello world'
I have defined a function key(shift), this allows me to call the function by doing key(3) for example. If I enter "khoor zruog" in the prompt I get "hello world"
def key(shift):
data =
string = input("Please enter the string you wish to decode.n")
for i in string:
if i.strip() and i in ALPHABET:
data.append(ALPHABET[(ALPHABET.index(i) - shift) % 26])
else:
data.append(i)
output = ''.join(data)
return (output)
def run():
shift = 1
for shift in range (26):
if key(shift) == "hello world":
print("hi")
else:
shift +=1
I am trying to figure out how to call my function key and increment it every time until it becomes hello world. So for example, it would first do key(1) then key(2) until it becomes "hello world" then stop.
python
python
asked Nov 19 at 20:03
Johnathan
43
43
I'd go with Patrick's suggestion from your last question: changekeyto accept two parameters, the text you want to encrypt and the rotation/key you want to use
– Sam Mason
Nov 19 at 20:30
add a comment |
I'd go with Patrick's suggestion from your last question: changekeyto accept two parameters, the text you want to encrypt and the rotation/key you want to use
– Sam Mason
Nov 19 at 20:30
I'd go with Patrick's suggestion from your last question: change
key to accept two parameters, the text you want to encrypt and the rotation/key you want to use– Sam Mason
Nov 19 at 20:30
I'd go with Patrick's suggestion from your last question: change
key to accept two parameters, the text you want to encrypt and the rotation/key you want to use– Sam Mason
Nov 19 at 20:30
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381841%2fpython-caesar-cipher-incrementing-problem%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
I'd go with Patrick's suggestion from your last question: change
keyto accept two parameters, the text you want to encrypt and the rotation/key you want to use– Sam Mason
Nov 19 at 20:30