Use of '.' in relations [closed]











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I am trying to understand what the following relation means:
$${(i, i · j) | i, j in mathbb N}$$



Any help is appreciated!










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closed as off-topic by amWhy, GNUSupporter 8964民主女神 地下教會, Ethan Bolker, Paul Frost, Gibbs Nov 23 at 17:55


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, GNUSupporter 8964民主女神 地下教會, Paul Frost, Gibbs

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 5




    Multiplication would be the obvious guess.
    – user3482749
    Nov 23 at 11:35










  • Math needs context. Without it, it could mean just about anything...
    – JuliusL33t
    Nov 23 at 11:55










  • It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
    – drhab
    Nov 23 at 12:04










  • The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
    – Eff
    Nov 23 at 13:22










  • I'm voting to close this question because the OP's latest edit makes it meaningless.
    – Ethan Bolker
    Nov 23 at 13:23















up vote
-2
down vote

favorite












I am trying to understand what the following relation means:
$${(i, i · j) | i, j in mathbb N}$$



Any help is appreciated!










share|cite|improve this question















closed as off-topic by amWhy, GNUSupporter 8964民主女神 地下教會, Ethan Bolker, Paul Frost, Gibbs Nov 23 at 17:55


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, GNUSupporter 8964民主女神 地下教會, Paul Frost, Gibbs

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 5




    Multiplication would be the obvious guess.
    – user3482749
    Nov 23 at 11:35










  • Math needs context. Without it, it could mean just about anything...
    – JuliusL33t
    Nov 23 at 11:55










  • It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
    – drhab
    Nov 23 at 12:04










  • The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
    – Eff
    Nov 23 at 13:22










  • I'm voting to close this question because the OP's latest edit makes it meaningless.
    – Ethan Bolker
    Nov 23 at 13:23













up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











I am trying to understand what the following relation means:
$${(i, i · j) | i, j in mathbb N}$$



Any help is appreciated!










share|cite|improve this question















I am trying to understand what the following relation means:
$${(i, i · j) | i, j in mathbb N}$$



Any help is appreciated!







discrete-mathematics relations






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edited Nov 23 at 13:24









Trevor Gunn

13.9k32045




13.9k32045










asked Nov 23 at 11:34









NorthernStars

13




13




closed as off-topic by amWhy, GNUSupporter 8964民主女神 地下教會, Ethan Bolker, Paul Frost, Gibbs Nov 23 at 17:55


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, GNUSupporter 8964民主女神 地下教會, Paul Frost, Gibbs

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by amWhy, GNUSupporter 8964民主女神 地下教會, Ethan Bolker, Paul Frost, Gibbs Nov 23 at 17:55


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, GNUSupporter 8964民主女神 地下教會, Paul Frost, Gibbs

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 5




    Multiplication would be the obvious guess.
    – user3482749
    Nov 23 at 11:35










  • Math needs context. Without it, it could mean just about anything...
    – JuliusL33t
    Nov 23 at 11:55










  • It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
    – drhab
    Nov 23 at 12:04










  • The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
    – Eff
    Nov 23 at 13:22










  • I'm voting to close this question because the OP's latest edit makes it meaningless.
    – Ethan Bolker
    Nov 23 at 13:23














  • 5




    Multiplication would be the obvious guess.
    – user3482749
    Nov 23 at 11:35










  • Math needs context. Without it, it could mean just about anything...
    – JuliusL33t
    Nov 23 at 11:55










  • It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
    – drhab
    Nov 23 at 12:04










  • The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
    – Eff
    Nov 23 at 13:22










  • I'm voting to close this question because the OP's latest edit makes it meaningless.
    – Ethan Bolker
    Nov 23 at 13:23








5




5




Multiplication would be the obvious guess.
– user3482749
Nov 23 at 11:35




Multiplication would be the obvious guess.
– user3482749
Nov 23 at 11:35












Math needs context. Without it, it could mean just about anything...
– JuliusL33t
Nov 23 at 11:55




Math needs context. Without it, it could mean just about anything...
– JuliusL33t
Nov 23 at 11:55












It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
– drhab
Nov 23 at 12:04




It is the (graph of the) function $mathbb Ntomathbb N$ prescribed by $dmapsto dcdot r$.
– drhab
Nov 23 at 12:04












The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
– Eff
Nov 23 at 13:22




The current version of the OP has nothing to do with "dot." I'm guessing something got lost in translation in the editing process...
– Eff
Nov 23 at 13:22












I'm voting to close this question because the OP's latest edit makes it meaningless.
– Ethan Bolker
Nov 23 at 13:23




I'm voting to close this question because the OP's latest edit makes it meaningless.
– Ethan Bolker
Nov 23 at 13:23










2 Answers
2






active

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1
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If $i,j in mathbb N$, then $(i,i cdot j)$ is the pair with $i$ in the first coordinate and the product $i cdot j$ in the second coordinate, hence



$(i,i cdot j) in mathbb N times mathbb N$ .






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    up vote
    0
    down vote













    (Working from the original version rather than the current which makes no sense) this is a way of writing down the relation "divides". $i$ divides $icdot j$ (that is $itimes j$) for each natural number $j$, and it divides no other natural numbers. So this relation contains all the pairs of that form.






    share|cite|improve this answer




























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote













      If $i,j in mathbb N$, then $(i,i cdot j)$ is the pair with $i$ in the first coordinate and the product $i cdot j$ in the second coordinate, hence



      $(i,i cdot j) in mathbb N times mathbb N$ .






      share|cite|improve this answer

























        up vote
        1
        down vote













        If $i,j in mathbb N$, then $(i,i cdot j)$ is the pair with $i$ in the first coordinate and the product $i cdot j$ in the second coordinate, hence



        $(i,i cdot j) in mathbb N times mathbb N$ .






        share|cite|improve this answer























          up vote
          1
          down vote










          up vote
          1
          down vote









          If $i,j in mathbb N$, then $(i,i cdot j)$ is the pair with $i$ in the first coordinate and the product $i cdot j$ in the second coordinate, hence



          $(i,i cdot j) in mathbb N times mathbb N$ .






          share|cite|improve this answer












          If $i,j in mathbb N$, then $(i,i cdot j)$ is the pair with $i$ in the first coordinate and the product $i cdot j$ in the second coordinate, hence



          $(i,i cdot j) in mathbb N times mathbb N$ .







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 23 at 11:38









          Fred

          43k1643




          43k1643






















              up vote
              0
              down vote













              (Working from the original version rather than the current which makes no sense) this is a way of writing down the relation "divides". $i$ divides $icdot j$ (that is $itimes j$) for each natural number $j$, and it divides no other natural numbers. So this relation contains all the pairs of that form.






              share|cite|improve this answer

























                up vote
                0
                down vote













                (Working from the original version rather than the current which makes no sense) this is a way of writing down the relation "divides". $i$ divides $icdot j$ (that is $itimes j$) for each natural number $j$, and it divides no other natural numbers. So this relation contains all the pairs of that form.






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  (Working from the original version rather than the current which makes no sense) this is a way of writing down the relation "divides". $i$ divides $icdot j$ (that is $itimes j$) for each natural number $j$, and it divides no other natural numbers. So this relation contains all the pairs of that form.






                  share|cite|improve this answer












                  (Working from the original version rather than the current which makes no sense) this is a way of writing down the relation "divides". $i$ divides $icdot j$ (that is $itimes j$) for each natural number $j$, and it divides no other natural numbers. So this relation contains all the pairs of that form.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 23 at 13:25









                  Especially Lime

                  21.2k22655




                  21.2k22655















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