Distint factor of integers
up vote
0
down vote
favorite
I need to find the number of distinct factors of $500$.
$500= 5*100 = 5* (10*10) = 5* (5*2) * (5*2) = 2^2 * 5^3$. So, the total number of positive factors are $(2+1)*(3+1) = 12$.
But, as the question asked to find distinct factors, should I count negative factors also? Or should I only count the positive factors?
prime-factorization
edited Nov 23 at 11:59
Klangen
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
add a comment |
up vote
0
down vote
favorite
I need to find the number of distinct factors of $500$.
$500= 5*100 = 5* (10*10) = 5* (5*2) * (5*2) = 2^2 * 5^3$. So, the total number of positive factors are $(2+1)*(3+1) = 12$.
But, as the question asked to find distinct factors, should I count negative factors also? Or should I only count the positive factors?
prime-factorization
edited Nov 23 at 11:59
Klangen
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
4
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I need to find the number of distinct factors of $500$.
$500= 5*100 = 5* (10*10) = 5* (5*2) * (5*2) = 2^2 * 5^3$. So, the total number of positive factors are $(2+1)*(3+1) = 12$.
But, as the question asked to find distinct factors, should I count negative factors also? Or should I only count the positive factors?
prime-factorization
edited Nov 23 at 11:59
Klangen
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
I need to find the number of distinct factors of $500$.
$500= 5*100 = 5* (10*10) = 5* (5*2) * (5*2) = 2^2 * 5^3$. So, the total number of positive factors are $(2+1)*(3+1) = 12$.
But, as the question asked to find distinct factors, should I count negative factors also? Or should I only count the positive factors?
prime-factorization
prime-factorization
edited Nov 23 at 11:59
Klangen
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
edited Nov 23 at 11:59
Klangen
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
edited Nov 23 at 11:59
Klangen
1,25811129
edited Nov 23 at 11:59
Klangen
1,25811129
edited Nov 23 at 11:59
Klangen
1,25811129
1,25811129
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
asked Aug 20 '16 at 4:51
Mahmudul Hasan
416311
416311
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
4
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11
add a comment |
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
4
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
4
4
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1897780%2fdistint-factor-of-integers%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
cut-the-knot.org/blue/NumberOfFactors.shtml
– lab bhattacharjee
Aug 20 '16 at 4:52
4
The question of whether you want to count only positive factors or if you allow negative factors is up to you and the question writer. Both are viable interpretations. If you do allow for negative factors then the same method applies. Simply multiply by two as each positive factor is in direct correspondence with a negative and vice versa via an easy bijection.
– JMoravitz
Aug 20 '16 at 5:11