array of structure pointers












2















So I have 3 files: main.c,countries.h and countries.c



I declare pointer of the structure called "Country" in the countries.h



I have included the countries.h in countries.c and in main.c



and declared the structure its self in countries.c



countries.h



typedef struct Country* pCountry;


countries.c



struct Country {
char *name;
pCity cities;
int numCities;
pTerritory countryTerr;
};


now, I want to create array of pointers of the Country structure, using malloc



so I did that:



pCountry countries_array;
countries_array = (pCountry);
malloc(num_of_countries*sizeof(countries_array));


and to assign pointers to each pointer,even though the malloc, does seems to work I cant



assign pointers to the elements in the array using :



countries_array[0]= new_pointer;


I get "invalid use of undefine struct country" and "derefrecing pointer to incomplete",



what is the problem with the code?



thanks










share|improve this question




















  • 2





    malloc() returns a value.

    – wildplasser
    Nov 21 '18 at 22:46






  • 2





    malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

    – Tom Kuschel
    Nov 21 '18 at 22:48








  • 2





    You will want to review: Is it a good idea to typedef pointers?.

    – David C. Rankin
    Nov 21 '18 at 23:00











  • What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

    – Barmar
    Nov 21 '18 at 23:42











  • which file does the error point to, to which line? how declaration of the country_array looks like?

    – Serge
    Nov 22 '18 at 2:33


















2















So I have 3 files: main.c,countries.h and countries.c



I declare pointer of the structure called "Country" in the countries.h



I have included the countries.h in countries.c and in main.c



and declared the structure its self in countries.c



countries.h



typedef struct Country* pCountry;


countries.c



struct Country {
char *name;
pCity cities;
int numCities;
pTerritory countryTerr;
};


now, I want to create array of pointers of the Country structure, using malloc



so I did that:



pCountry countries_array;
countries_array = (pCountry);
malloc(num_of_countries*sizeof(countries_array));


and to assign pointers to each pointer,even though the malloc, does seems to work I cant



assign pointers to the elements in the array using :



countries_array[0]= new_pointer;


I get "invalid use of undefine struct country" and "derefrecing pointer to incomplete",



what is the problem with the code?



thanks










share|improve this question




















  • 2





    malloc() returns a value.

    – wildplasser
    Nov 21 '18 at 22:46






  • 2





    malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

    – Tom Kuschel
    Nov 21 '18 at 22:48








  • 2





    You will want to review: Is it a good idea to typedef pointers?.

    – David C. Rankin
    Nov 21 '18 at 23:00











  • What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

    – Barmar
    Nov 21 '18 at 23:42











  • which file does the error point to, to which line? how declaration of the country_array looks like?

    – Serge
    Nov 22 '18 at 2:33
















2












2








2








So I have 3 files: main.c,countries.h and countries.c



I declare pointer of the structure called "Country" in the countries.h



I have included the countries.h in countries.c and in main.c



and declared the structure its self in countries.c



countries.h



typedef struct Country* pCountry;


countries.c



struct Country {
char *name;
pCity cities;
int numCities;
pTerritory countryTerr;
};


now, I want to create array of pointers of the Country structure, using malloc



so I did that:



pCountry countries_array;
countries_array = (pCountry);
malloc(num_of_countries*sizeof(countries_array));


and to assign pointers to each pointer,even though the malloc, does seems to work I cant



assign pointers to the elements in the array using :



countries_array[0]= new_pointer;


I get "invalid use of undefine struct country" and "derefrecing pointer to incomplete",



what is the problem with the code?



thanks










share|improve this question
















So I have 3 files: main.c,countries.h and countries.c



I declare pointer of the structure called "Country" in the countries.h



I have included the countries.h in countries.c and in main.c



and declared the structure its self in countries.c



countries.h



typedef struct Country* pCountry;


countries.c



struct Country {
char *name;
pCity cities;
int numCities;
pTerritory countryTerr;
};


now, I want to create array of pointers of the Country structure, using malloc



so I did that:



pCountry countries_array;
countries_array = (pCountry);
malloc(num_of_countries*sizeof(countries_array));


and to assign pointers to each pointer,even though the malloc, does seems to work I cant



assign pointers to the elements in the array using :



countries_array[0]= new_pointer;


I get "invalid use of undefine struct country" and "derefrecing pointer to incomplete",



what is the problem with the code?



thanks







c pointers






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 0:28









Tico

2,07712332




2,07712332










asked Nov 21 '18 at 22:44









kal polakal pola

111




111








  • 2





    malloc() returns a value.

    – wildplasser
    Nov 21 '18 at 22:46






  • 2





    malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

    – Tom Kuschel
    Nov 21 '18 at 22:48








  • 2





    You will want to review: Is it a good idea to typedef pointers?.

    – David C. Rankin
    Nov 21 '18 at 23:00











  • What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

    – Barmar
    Nov 21 '18 at 23:42











  • which file does the error point to, to which line? how declaration of the country_array looks like?

    – Serge
    Nov 22 '18 at 2:33
















  • 2





    malloc() returns a value.

    – wildplasser
    Nov 21 '18 at 22:46






  • 2





    malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

    – Tom Kuschel
    Nov 21 '18 at 22:48








  • 2





    You will want to review: Is it a good idea to typedef pointers?.

    – David C. Rankin
    Nov 21 '18 at 23:00











  • What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

    – Barmar
    Nov 21 '18 at 23:42











  • which file does the error point to, to which line? how declaration of the country_array looks like?

    – Serge
    Nov 22 '18 at 2:33










2




2





malloc() returns a value.

– wildplasser
Nov 21 '18 at 22:46





malloc() returns a value.

– wildplasser
Nov 21 '18 at 22:46




2




2





malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

– Tom Kuschel
Nov 21 '18 at 22:48







malloc itselfs returns the pointer, NULL if there is no memory available like: countries_array = malloc(num_of_countries*sizeof countries_array);

– Tom Kuschel
Nov 21 '18 at 22:48






2




2





You will want to review: Is it a good idea to typedef pointers?.

– David C. Rankin
Nov 21 '18 at 23:00





You will want to review: Is it a good idea to typedef pointers?.

– David C. Rankin
Nov 21 '18 at 23:00













What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

– Barmar
Nov 21 '18 at 23:42





What is countries_array = (pCountry); supposed to mean? Was that intended to be a type cast of the result of the next line?

– Barmar
Nov 21 '18 at 23:42













which file does the error point to, to which line? how declaration of the country_array looks like?

– Serge
Nov 22 '18 at 2:33







which file does the error point to, to which line? how declaration of the country_array looks like?

– Serge
Nov 22 '18 at 2:33














1 Answer
1






active

oldest

votes


















1














Looks good. Just assign it to something of the same type, struct Country. Also, as pointed out in the comments, it should be malloc num_of_countries * sizeof struct Country (not the pointer type), which is now correctly dereferenced below as sizeof (*countries_array) which also works.



pCountry countries_array;
countries_array = malloc(num_of_countries * sizeof (*countries_array));
struct Country Jefferson = {"Jefferson", 1,2,3 };
countries_array[0] = Jefferson;

// don't forget to free the memory when no longer needed.
free (countries_array);


If we must put a pointer into this array of structs, we can either dereference the pointer like countries_array[0] = *pointer, or... we could declare countries_array as an array of pointers, instead of an array of structs. Perhaps this is what you may want. Either way, the actual structures have to occupy memory somewhere...



pCountry *countries_array = malloc(num_of_countries*sizeof countries_array);
pCountry j = &Jefferson; // `&`, "address of" operator
countries_array[0] = j; // put a `pointer` into the array...





share|improve this answer


























  • Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

    – hellork
    Nov 21 '18 at 23:46











  • On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

    – hellork
    Nov 22 '18 at 0:10











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Looks good. Just assign it to something of the same type, struct Country. Also, as pointed out in the comments, it should be malloc num_of_countries * sizeof struct Country (not the pointer type), which is now correctly dereferenced below as sizeof (*countries_array) which also works.



pCountry countries_array;
countries_array = malloc(num_of_countries * sizeof (*countries_array));
struct Country Jefferson = {"Jefferson", 1,2,3 };
countries_array[0] = Jefferson;

// don't forget to free the memory when no longer needed.
free (countries_array);


If we must put a pointer into this array of structs, we can either dereference the pointer like countries_array[0] = *pointer, or... we could declare countries_array as an array of pointers, instead of an array of structs. Perhaps this is what you may want. Either way, the actual structures have to occupy memory somewhere...



pCountry *countries_array = malloc(num_of_countries*sizeof countries_array);
pCountry j = &Jefferson; // `&`, "address of" operator
countries_array[0] = j; // put a `pointer` into the array...





share|improve this answer


























  • Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

    – hellork
    Nov 21 '18 at 23:46











  • On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

    – hellork
    Nov 22 '18 at 0:10
















1














Looks good. Just assign it to something of the same type, struct Country. Also, as pointed out in the comments, it should be malloc num_of_countries * sizeof struct Country (not the pointer type), which is now correctly dereferenced below as sizeof (*countries_array) which also works.



pCountry countries_array;
countries_array = malloc(num_of_countries * sizeof (*countries_array));
struct Country Jefferson = {"Jefferson", 1,2,3 };
countries_array[0] = Jefferson;

// don't forget to free the memory when no longer needed.
free (countries_array);


If we must put a pointer into this array of structs, we can either dereference the pointer like countries_array[0] = *pointer, or... we could declare countries_array as an array of pointers, instead of an array of structs. Perhaps this is what you may want. Either way, the actual structures have to occupy memory somewhere...



pCountry *countries_array = malloc(num_of_countries*sizeof countries_array);
pCountry j = &Jefferson; // `&`, "address of" operator
countries_array[0] = j; // put a `pointer` into the array...





share|improve this answer


























  • Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

    – hellork
    Nov 21 '18 at 23:46











  • On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

    – hellork
    Nov 22 '18 at 0:10














1












1








1







Looks good. Just assign it to something of the same type, struct Country. Also, as pointed out in the comments, it should be malloc num_of_countries * sizeof struct Country (not the pointer type), which is now correctly dereferenced below as sizeof (*countries_array) which also works.



pCountry countries_array;
countries_array = malloc(num_of_countries * sizeof (*countries_array));
struct Country Jefferson = {"Jefferson", 1,2,3 };
countries_array[0] = Jefferson;

// don't forget to free the memory when no longer needed.
free (countries_array);


If we must put a pointer into this array of structs, we can either dereference the pointer like countries_array[0] = *pointer, or... we could declare countries_array as an array of pointers, instead of an array of structs. Perhaps this is what you may want. Either way, the actual structures have to occupy memory somewhere...



pCountry *countries_array = malloc(num_of_countries*sizeof countries_array);
pCountry j = &Jefferson; // `&`, "address of" operator
countries_array[0] = j; // put a `pointer` into the array...





share|improve this answer















Looks good. Just assign it to something of the same type, struct Country. Also, as pointed out in the comments, it should be malloc num_of_countries * sizeof struct Country (not the pointer type), which is now correctly dereferenced below as sizeof (*countries_array) which also works.



pCountry countries_array;
countries_array = malloc(num_of_countries * sizeof (*countries_array));
struct Country Jefferson = {"Jefferson", 1,2,3 };
countries_array[0] = Jefferson;

// don't forget to free the memory when no longer needed.
free (countries_array);


If we must put a pointer into this array of structs, we can either dereference the pointer like countries_array[0] = *pointer, or... we could declare countries_array as an array of pointers, instead of an array of structs. Perhaps this is what you may want. Either way, the actual structures have to occupy memory somewhere...



pCountry *countries_array = malloc(num_of_countries*sizeof countries_array);
pCountry j = &Jefferson; // `&`, "address of" operator
countries_array[0] = j; // put a `pointer` into the array...






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 23 '18 at 7:18

























answered Nov 21 '18 at 23:39









hellorkhellork

935




935













  • Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

    – hellork
    Nov 21 '18 at 23:46











  • On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

    – hellork
    Nov 22 '18 at 0:10



















  • Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

    – hellork
    Nov 21 '18 at 23:46











  • On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

    – hellork
    Nov 22 '18 at 0:10

















Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

– hellork
Nov 21 '18 at 23:46





Checking right after malloc for out of memory condition is advisable. if (!countries_array) { fprintf(stderr, "out of memory"); exit 1; }

– hellork
Nov 21 '18 at 23:46













On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

– hellork
Nov 22 '18 at 0:10





On casting malloc(). Since this is tagged "C" we don't (cast) the result of malloc, because it hides important compiler errors if we do. In C++, it is required, so it crops up quite a bit. c-faq.com/malloc/mallocnocast.html

– hellork
Nov 22 '18 at 0:10


















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