Closed and finite subspace [duplicate]












1












$begingroup$



This question already has an answer here:




  • Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.

    3 answers




Given $X$ a normed space, $M$ a closed subspace of $X$ and $Z$ a finite dimension subspace of $X.$ Show that $M+Z$ is a closed subspace of $X.$



How can I do this? I thought to construct a sequence convergent in $M+Z$ with limit in $M+Z$ but I don’t know if it is the right way and anyway I don’t know how to construct this sequence...










share|cite|improve this question











$endgroup$



marked as duplicate by Martin Sleziak, GNUSupporter 8964民主女神 地下教會, Davide Giraudo functional-analysis
Users with the  functional-analysis badge can single-handedly close functional-analysis questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Dec 9 '18 at 14:44


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
    $endgroup$
    – Martin Sleziak
    Dec 9 '18 at 13:05
















1












$begingroup$



This question already has an answer here:




  • Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.

    3 answers




Given $X$ a normed space, $M$ a closed subspace of $X$ and $Z$ a finite dimension subspace of $X.$ Show that $M+Z$ is a closed subspace of $X.$



How can I do this? I thought to construct a sequence convergent in $M+Z$ with limit in $M+Z$ but I don’t know if it is the right way and anyway I don’t know how to construct this sequence...










share|cite|improve this question











$endgroup$



marked as duplicate by Martin Sleziak, GNUSupporter 8964民主女神 地下教會, Davide Giraudo functional-analysis
Users with the  functional-analysis badge can single-handedly close functional-analysis questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Dec 9 '18 at 14:44


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
    $endgroup$
    – Martin Sleziak
    Dec 9 '18 at 13:05














1












1








1





$begingroup$



This question already has an answer here:




  • Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.

    3 answers




Given $X$ a normed space, $M$ a closed subspace of $X$ and $Z$ a finite dimension subspace of $X.$ Show that $M+Z$ is a closed subspace of $X.$



How can I do this? I thought to construct a sequence convergent in $M+Z$ with limit in $M+Z$ but I don’t know if it is the right way and anyway I don’t know how to construct this sequence...










share|cite|improve this question











$endgroup$





This question already has an answer here:




  • Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.

    3 answers




Given $X$ a normed space, $M$ a closed subspace of $X$ and $Z$ a finite dimension subspace of $X.$ Show that $M+Z$ is a closed subspace of $X.$



How can I do this? I thought to construct a sequence convergent in $M+Z$ with limit in $M+Z$ but I don’t know if it is the right way and anyway I don’t know how to construct this sequence...





This question already has an answer here:




  • Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.

    3 answers








sequences-and-series functional-analysis banach-spaces normed-spaces closed-graph






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 6 '18 at 23:56









user376343

3,3582826




3,3582826










asked Dec 6 '18 at 13:56









Maggie94Maggie94

856




856




marked as duplicate by Martin Sleziak, GNUSupporter 8964民主女神 地下教會, Davide Giraudo functional-analysis
Users with the  functional-analysis badge can single-handedly close functional-analysis questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Dec 9 '18 at 14:44


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Martin Sleziak, GNUSupporter 8964民主女神 地下教會, Davide Giraudo functional-analysis
Users with the  functional-analysis badge can single-handedly close functional-analysis questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Dec 9 '18 at 14:44


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • $begingroup$
    See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
    $endgroup$
    – Martin Sleziak
    Dec 9 '18 at 13:05


















  • $begingroup$
    See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
    $endgroup$
    – Martin Sleziak
    Dec 9 '18 at 13:05
















$begingroup$
See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
$endgroup$
– Martin Sleziak
Dec 9 '18 at 13:05




$begingroup$
See also: Show that $F+G$ is closed when $G$ a closed subspace of normed space $E$ and $F$ a finite dimensional subspace of $E$.
$endgroup$
– Martin Sleziak
Dec 9 '18 at 13:05










1 Answer
1






active

oldest

votes


















2












$begingroup$

Note that $X / M$ is also a normed space with the quotient norm, because $M$ was assumed to be closed. Define the projection $pi colon X rightarrow X setminus M$, which is continuous. Now note that $W:= pi(Z)$ is a finite dimensional subspace of $X /M$. Thus $M+ Z = pi^{-1}(W)$ is a closed subspace.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
    $endgroup$
    – Maggie94
    Dec 7 '18 at 11:58




















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Note that $X / M$ is also a normed space with the quotient norm, because $M$ was assumed to be closed. Define the projection $pi colon X rightarrow X setminus M$, which is continuous. Now note that $W:= pi(Z)$ is a finite dimensional subspace of $X /M$. Thus $M+ Z = pi^{-1}(W)$ is a closed subspace.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
    $endgroup$
    – Maggie94
    Dec 7 '18 at 11:58


















2












$begingroup$

Note that $X / M$ is also a normed space with the quotient norm, because $M$ was assumed to be closed. Define the projection $pi colon X rightarrow X setminus M$, which is continuous. Now note that $W:= pi(Z)$ is a finite dimensional subspace of $X /M$. Thus $M+ Z = pi^{-1}(W)$ is a closed subspace.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
    $endgroup$
    – Maggie94
    Dec 7 '18 at 11:58
















2












2








2





$begingroup$

Note that $X / M$ is also a normed space with the quotient norm, because $M$ was assumed to be closed. Define the projection $pi colon X rightarrow X setminus M$, which is continuous. Now note that $W:= pi(Z)$ is a finite dimensional subspace of $X /M$. Thus $M+ Z = pi^{-1}(W)$ is a closed subspace.






share|cite|improve this answer









$endgroup$



Note that $X / M$ is also a normed space with the quotient norm, because $M$ was assumed to be closed. Define the projection $pi colon X rightarrow X setminus M$, which is continuous. Now note that $W:= pi(Z)$ is a finite dimensional subspace of $X /M$. Thus $M+ Z = pi^{-1}(W)$ is a closed subspace.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 6 '18 at 14:24









p4schp4sch

4,995217




4,995217












  • $begingroup$
    Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
    $endgroup$
    – Maggie94
    Dec 7 '18 at 11:58




















  • $begingroup$
    Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
    $endgroup$
    – Maggie94
    Dec 7 '18 at 11:58


















$begingroup$
Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
$endgroup$
– Maggie94
Dec 7 '18 at 11:58






$begingroup$
Wow, easier than I thought. Thank you very much!! Can you also help me with this? math.stackexchange.com/questions/3029768/…
$endgroup$
– Maggie94
Dec 7 '18 at 11:58





Popular posts from this blog

Tonle Sap (See)

I get strange results when I access the Sqlitedatabase with Unity C# via XAMPP

Guatemaltekische Davis-Cup-Mannschaft