Prove that the given RV is normal












2












$begingroup$


This is an old qualifying exam problem of probability theory.




Let $X,Y$ be two iid random variables with mean zero and variance 1. Suppose that $X,Y,frac{X+Y}{sqrt{2}}$ are all identically distributed. Prove that $Xsim N(0,1)$.




My attempt: Let $varphi$ be the characteristic function of $X$. Then by the given condition, I got $varphi(t)=varphi(t/sqrt{2})^2$. Then I'm trying to conclude $varphi(t)=e^{-t^2/2}$ from such functional equation, but it seems not work.



Does anyone have ideas?



Thanks in advance!










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
    $endgroup$
    – Did
    Dec 6 '18 at 14:10










  • $begingroup$
    @Did Thanks for your hint! I'll post my answer shortly.
    $endgroup$
    – bellcircle
    Dec 6 '18 at 15:38
















2












$begingroup$


This is an old qualifying exam problem of probability theory.




Let $X,Y$ be two iid random variables with mean zero and variance 1. Suppose that $X,Y,frac{X+Y}{sqrt{2}}$ are all identically distributed. Prove that $Xsim N(0,1)$.




My attempt: Let $varphi$ be the characteristic function of $X$. Then by the given condition, I got $varphi(t)=varphi(t/sqrt{2})^2$. Then I'm trying to conclude $varphi(t)=e^{-t^2/2}$ from such functional equation, but it seems not work.



Does anyone have ideas?



Thanks in advance!










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
    $endgroup$
    – Did
    Dec 6 '18 at 14:10










  • $begingroup$
    @Did Thanks for your hint! I'll post my answer shortly.
    $endgroup$
    – bellcircle
    Dec 6 '18 at 15:38














2












2








2


0



$begingroup$


This is an old qualifying exam problem of probability theory.




Let $X,Y$ be two iid random variables with mean zero and variance 1. Suppose that $X,Y,frac{X+Y}{sqrt{2}}$ are all identically distributed. Prove that $Xsim N(0,1)$.




My attempt: Let $varphi$ be the characteristic function of $X$. Then by the given condition, I got $varphi(t)=varphi(t/sqrt{2})^2$. Then I'm trying to conclude $varphi(t)=e^{-t^2/2}$ from such functional equation, but it seems not work.



Does anyone have ideas?



Thanks in advance!










share|cite|improve this question











$endgroup$




This is an old qualifying exam problem of probability theory.




Let $X,Y$ be two iid random variables with mean zero and variance 1. Suppose that $X,Y,frac{X+Y}{sqrt{2}}$ are all identically distributed. Prove that $Xsim N(0,1)$.




My attempt: Let $varphi$ be the characteristic function of $X$. Then by the given condition, I got $varphi(t)=varphi(t/sqrt{2})^2$. Then I'm trying to conclude $varphi(t)=e^{-t^2/2}$ from such functional equation, but it seems not work.



Does anyone have ideas?



Thanks in advance!







probability-theory probability-distributions characteristic-functions






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share|cite|improve this question













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share|cite|improve this question








edited Dec 6 '18 at 14:06









gt6989b

33.6k22453




33.6k22453










asked Dec 6 '18 at 13:55









bellcirclebellcircle

1,331411




1,331411








  • 2




    $begingroup$
    Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
    $endgroup$
    – Did
    Dec 6 '18 at 14:10










  • $begingroup$
    @Did Thanks for your hint! I'll post my answer shortly.
    $endgroup$
    – bellcircle
    Dec 6 '18 at 15:38














  • 2




    $begingroup$
    Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
    $endgroup$
    – Did
    Dec 6 '18 at 14:10










  • $begingroup$
    @Did Thanks for your hint! I'll post my answer shortly.
    $endgroup$
    – bellcircle
    Dec 6 '18 at 15:38








2




2




$begingroup$
Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
$endgroup$
– Did
Dec 6 '18 at 14:10




$begingroup$
Hint: Iterate the relation you found and use the expansion $varphi(t)=1-t^2/2+o(t^2)$ when $tto0$.
$endgroup$
– Did
Dec 6 '18 at 14:10












$begingroup$
@Did Thanks for your hint! I'll post my answer shortly.
$endgroup$
– bellcircle
Dec 6 '18 at 15:38




$begingroup$
@Did Thanks for your hint! I'll post my answer shortly.
$endgroup$
– bellcircle
Dec 6 '18 at 15:38










1 Answer
1






active

oldest

votes


















2












$begingroup$

Iterating the property of $varphi$ found in the question, one gets $varphi(t)=left(varphi(t/2^{n/2})right)^{2^n}$ for all $ninmathbb{N}$.



Also, since $X$ has mean zero and variance 1, $varphi(t)=1-frac{t^2}{2}+o(t^2)$ as $tto 0$.



Therefore, $$varphi(t)=left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=lim_{ntoinfty}left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=e^{-t^2/2} $$ as desired.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Dec 6 '18 at 16:03











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Iterating the property of $varphi$ found in the question, one gets $varphi(t)=left(varphi(t/2^{n/2})right)^{2^n}$ for all $ninmathbb{N}$.



Also, since $X$ has mean zero and variance 1, $varphi(t)=1-frac{t^2}{2}+o(t^2)$ as $tto 0$.



Therefore, $$varphi(t)=left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=lim_{ntoinfty}left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=e^{-t^2/2} $$ as desired.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Dec 6 '18 at 16:03
















2












$begingroup$

Iterating the property of $varphi$ found in the question, one gets $varphi(t)=left(varphi(t/2^{n/2})right)^{2^n}$ for all $ninmathbb{N}$.



Also, since $X$ has mean zero and variance 1, $varphi(t)=1-frac{t^2}{2}+o(t^2)$ as $tto 0$.



Therefore, $$varphi(t)=left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=lim_{ntoinfty}left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=e^{-t^2/2} $$ as desired.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Dec 6 '18 at 16:03














2












2








2





$begingroup$

Iterating the property of $varphi$ found in the question, one gets $varphi(t)=left(varphi(t/2^{n/2})right)^{2^n}$ for all $ninmathbb{N}$.



Also, since $X$ has mean zero and variance 1, $varphi(t)=1-frac{t^2}{2}+o(t^2)$ as $tto 0$.



Therefore, $$varphi(t)=left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=lim_{ntoinfty}left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=e^{-t^2/2} $$ as desired.






share|cite|improve this answer









$endgroup$



Iterating the property of $varphi$ found in the question, one gets $varphi(t)=left(varphi(t/2^{n/2})right)^{2^n}$ for all $ninmathbb{N}$.



Also, since $X$ has mean zero and variance 1, $varphi(t)=1-frac{t^2}{2}+o(t^2)$ as $tto 0$.



Therefore, $$varphi(t)=left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=lim_{ntoinfty}left(1-frac{t^2}{2^{n+1}}+o(frac{t^2}{2^n})right)^{2^n}=e^{-t^2/2} $$ as desired.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 6 '18 at 15:41









bellcirclebellcircle

1,331411




1,331411












  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Dec 6 '18 at 16:03


















  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Dec 6 '18 at 16:03
















$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Dec 6 '18 at 16:03




$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Dec 6 '18 at 16:03


















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