Convert mongo aggregate(with group and size) to query in spring data












0














sin my MongoDB I have documents like this:



{
"_id" : ObjectId("5bf3cd1c6b86db2c84d"),
"_class" : "Log",
"data" : {
"devices" : [
{
"id": "12364",
"name":"name"
},
{
"id": "12346",
"name":"name"
},
{
"id": "12345",
"name":"name"
}
]
}
}


I wanted to return number of devices, so I created query:



db.getCollection('coll').aggregate(
{$group: { _id: null, totalSize: { $sum: { $size: "$data.devices"}} }})


which returns me:



{ "_id" : null, "totalSize" : 6 }


But how to create method to return "totalSize" in Spring Data?



I get stuck and I dont know how to solve it:



public Long countDevices() {
GroupOperation groupOperation= Aggregation.group("_id").sum("_id");

Aggregation aggregation = Aggregation.newAggregation(groupOperation);

mongoOperations.aggregate(matchOperation,)

return ...
}


below solution seems to work, but its not looks so pretty and performance:



public Long count(Criteria searchCriteria) {

Aggregation aggregation = Aggregation.newAggregation(
Aggregation.match(searchCriteria),
Aggregation.unwind("data.device")
);
AggregationResults aggregationResults = mongoOperations.aggregate(aggregation,"coll", DBObject.class);
return (long) aggregationResults.getMappedResults().size();

}









share|improve this question



























    0














    sin my MongoDB I have documents like this:



    {
    "_id" : ObjectId("5bf3cd1c6b86db2c84d"),
    "_class" : "Log",
    "data" : {
    "devices" : [
    {
    "id": "12364",
    "name":"name"
    },
    {
    "id": "12346",
    "name":"name"
    },
    {
    "id": "12345",
    "name":"name"
    }
    ]
    }
    }


    I wanted to return number of devices, so I created query:



    db.getCollection('coll').aggregate(
    {$group: { _id: null, totalSize: { $sum: { $size: "$data.devices"}} }})


    which returns me:



    { "_id" : null, "totalSize" : 6 }


    But how to create method to return "totalSize" in Spring Data?



    I get stuck and I dont know how to solve it:



    public Long countDevices() {
    GroupOperation groupOperation= Aggregation.group("_id").sum("_id");

    Aggregation aggregation = Aggregation.newAggregation(groupOperation);

    mongoOperations.aggregate(matchOperation,)

    return ...
    }


    below solution seems to work, but its not looks so pretty and performance:



    public Long count(Criteria searchCriteria) {

    Aggregation aggregation = Aggregation.newAggregation(
    Aggregation.match(searchCriteria),
    Aggregation.unwind("data.device")
    );
    AggregationResults aggregationResults = mongoOperations.aggregate(aggregation,"coll", DBObject.class);
    return (long) aggregationResults.getMappedResults().size();

    }









    share|improve this question

























      0












      0








      0







      sin my MongoDB I have documents like this:



      {
      "_id" : ObjectId("5bf3cd1c6b86db2c84d"),
      "_class" : "Log",
      "data" : {
      "devices" : [
      {
      "id": "12364",
      "name":"name"
      },
      {
      "id": "12346",
      "name":"name"
      },
      {
      "id": "12345",
      "name":"name"
      }
      ]
      }
      }


      I wanted to return number of devices, so I created query:



      db.getCollection('coll').aggregate(
      {$group: { _id: null, totalSize: { $sum: { $size: "$data.devices"}} }})


      which returns me:



      { "_id" : null, "totalSize" : 6 }


      But how to create method to return "totalSize" in Spring Data?



      I get stuck and I dont know how to solve it:



      public Long countDevices() {
      GroupOperation groupOperation= Aggregation.group("_id").sum("_id");

      Aggregation aggregation = Aggregation.newAggregation(groupOperation);

      mongoOperations.aggregate(matchOperation,)

      return ...
      }


      below solution seems to work, but its not looks so pretty and performance:



      public Long count(Criteria searchCriteria) {

      Aggregation aggregation = Aggregation.newAggregation(
      Aggregation.match(searchCriteria),
      Aggregation.unwind("data.device")
      );
      AggregationResults aggregationResults = mongoOperations.aggregate(aggregation,"coll", DBObject.class);
      return (long) aggregationResults.getMappedResults().size();

      }









      share|improve this question













      sin my MongoDB I have documents like this:



      {
      "_id" : ObjectId("5bf3cd1c6b86db2c84d"),
      "_class" : "Log",
      "data" : {
      "devices" : [
      {
      "id": "12364",
      "name":"name"
      },
      {
      "id": "12346",
      "name":"name"
      },
      {
      "id": "12345",
      "name":"name"
      }
      ]
      }
      }


      I wanted to return number of devices, so I created query:



      db.getCollection('coll').aggregate(
      {$group: { _id: null, totalSize: { $sum: { $size: "$data.devices"}} }})


      which returns me:



      { "_id" : null, "totalSize" : 6 }


      But how to create method to return "totalSize" in Spring Data?



      I get stuck and I dont know how to solve it:



      public Long countDevices() {
      GroupOperation groupOperation= Aggregation.group("_id").sum("_id");

      Aggregation aggregation = Aggregation.newAggregation(groupOperation);

      mongoOperations.aggregate(matchOperation,)

      return ...
      }


      below solution seems to work, but its not looks so pretty and performance:



      public Long count(Criteria searchCriteria) {

      Aggregation aggregation = Aggregation.newAggregation(
      Aggregation.match(searchCriteria),
      Aggregation.unwind("data.device")
      );
      AggregationResults aggregationResults = mongoOperations.aggregate(aggregation,"coll", DBObject.class);
      return (long) aggregationResults.getMappedResults().size();

      }






      spring mongodb spring-data spring-data-mongodb






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      asked Nov 21 '18 at 8:25









      Adrian Wąt

      748




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