st.petersburg paradox in python
I have been trying to do the St.Petersburg paradox( the player wins 2 dollars if tail appears on the first toss, 4 dollars if heads appear on the first toss and tails on the second, 8 dollars if heads appear on the first two tosses and tails on the third, and so on.) in python.
But I cannot do it correctly. I want to know if we flip the coin 100 times, how much money we will get.
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(2)
if choices=="tail":
money=money+sum(l)+2
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
but it doesnt give any results or just 2
i tried in another way but its the same:
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(choices)
if choices=="tail":
money=money+2**(len(l)+1)
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
Can you help me?
probability random python
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
add a comment |
I have been trying to do the St.Petersburg paradox( the player wins 2 dollars if tail appears on the first toss, 4 dollars if heads appear on the first toss and tails on the second, 8 dollars if heads appear on the first two tosses and tails on the third, and so on.) in python.
But I cannot do it correctly. I want to know if we flip the coin 100 times, how much money we will get.
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(2)
if choices=="tail":
money=money+sum(l)+2
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
but it doesnt give any results or just 2
i tried in another way but its the same:
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(choices)
if choices=="tail":
money=money+2**(len(l)+1)
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
Can you help me?
probability random python
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41
add a comment |
I have been trying to do the St.Petersburg paradox( the player wins 2 dollars if tail appears on the first toss, 4 dollars if heads appear on the first toss and tails on the second, 8 dollars if heads appear on the first two tosses and tails on the third, and so on.) in python.
But I cannot do it correctly. I want to know if we flip the coin 100 times, how much money we will get.
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(2)
if choices=="tail":
money=money+sum(l)+2
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
but it doesnt give any results or just 2
i tried in another way but its the same:
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(choices)
if choices=="tail":
money=money+2**(len(l)+1)
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
Can you help me?
probability random python
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
I have been trying to do the St.Petersburg paradox( the player wins 2 dollars if tail appears on the first toss, 4 dollars if heads appear on the first toss and tails on the second, 8 dollars if heads appear on the first two tosses and tails on the third, and so on.) in python.
But I cannot do it correctly. I want to know if we flip the coin 100 times, how much money we will get.
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(2)
if choices=="tail":
money=money+sum(l)+2
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
but it doesnt give any results or just 2
i tried in another way but its the same:
import random
def St(number):
l=
money=0
signs=["head","tail"]
for i in range(number):
choices=random.choice(signs)
while choices=="head":
l.append(choices)
if choices=="tail":
money=money+2**(len(l)+1)
del l[:]
result=round(money/number,3)
return(money,result)
print(St(100))
Can you help me?
probability random python
probability random python
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
asked Dec 1 '18 at 21:39
Egshiglen Bat-Erdene
1
1
The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41
add a comment |
The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41
The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41
add a comment |
1 Answer
1
active
oldest
votes
In Python, there's usually an easy way. Here's what you could do, using the $U(0,,1)$-sampling numpy.random.random:
from numpy.random import random
def St(number):
result = 2
for i in range(number):
if random() < 0.5: return result
result *= 2
return result
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
In Python, there's usually an easy way. Here's what you could do, using the $U(0,,1)$-sampling numpy.random.random:
from numpy.random import random
def St(number):
result = 2
for i in range(number):
if random() < 0.5: return result
result *= 2
return result
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
add a comment |
In Python, there's usually an easy way. Here's what you could do, using the $U(0,,1)$-sampling numpy.random.random:
from numpy.random import random
def St(number):
result = 2
for i in range(number):
if random() < 0.5: return result
result *= 2
return result
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
add a comment |
In Python, there's usually an easy way. Here's what you could do, using the $U(0,,1)$-sampling numpy.random.random:
from numpy.random import random
def St(number):
result = 2
for i in range(number):
if random() < 0.5: return result
result *= 2
return result
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
In Python, there's usually an easy way. Here's what you could do, using the $U(0,,1)$-sampling numpy.random.random:
from numpy.random import random
def St(number):
result = 2
for i in range(number):
if random() < 0.5: return result
result *= 2
return result
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
answered Dec 1 '18 at 22:06
J.G.
22.8k22137
22.8k22137
add a comment |
add a comment |
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The while loop you've written is an infinite loop. (Have you tried stepping through your code line by line using a debugger? That can help a lot to understand what's going on in your code.)
– littleO
Dec 1 '18 at 22:25
Sorry I am not familiar with debugger. Can you explain?
– Egshiglen Bat-Erdene
Dec 2 '18 at 9:41
It's possible to use a debugger to step through your code line by line and look closely at every step. This can be very helpful, especially when you're learning to code, to understand what your code is doing. I recommend googling to learn how to use a debugger and trying it out. Python has a debugger called pdb that you can use. Alternatively, if you're using the Spyder IDE (which comes with the Anaconda Python distribution), Spyder makes it easy to put a breakpoint in your code and debug it.
– littleO
Dec 2 '18 at 9:54
Thank you for explaining
– Egshiglen Bat-Erdene
Dec 2 '18 at 15:41