How do I print the full result of a matrix multiplication in a Maple for loop?
How do I print the full result without the u1, u2, … variables using a for loop?
I tried declaring my two matrix this way:
Capture 1
Capture 2
It executes my for loop until u11 but doesn’t return the vector
Then I tried to change my multiplication for a multiply
Capture 3
It also does the for loop completely but doesn’t print the vector like u1 in the last example.
Then I tried declaring my two matrixes with an array:
Capture 4
Capture 5
It does the for completely but doesn’t print the vectors like u1
I change my multiplication for A.u[i] but it ain’t working either
Then I tried to declare the matrix with Matrix and the vector with Vector
Capture 6
Capture 7
It doesn’t work….
It’s always the first vector u1 that prints correctly and the others aren’t doing the multiplication
matrices maple
asked Dec 1 '18 at 19:53
Émile Bernard
33
add a comment |
How do I print the full result without the u1, u2, … variables using a for loop?
I tried declaring my two matrix this way:
Capture 1
Capture 2
It executes my for loop until u11 but doesn’t return the vector
Then I tried to change my multiplication for a multiply
Capture 3
It also does the for loop completely but doesn’t print the vector like u1 in the last example.
Then I tried declaring my two matrixes with an array:
Capture 4
Capture 5
It does the for completely but doesn’t print the vectors like u1
I change my multiplication for A.u[i] but it ain’t working either
Then I tried to declare the matrix with Matrix and the vector with Vector
Capture 6
Capture 7
It doesn’t work….
It’s always the first vector u1 that prints correctly and the others aren’t doing the multiplication
matrices maple
asked Dec 1 '18 at 19:53
Émile Bernard
33
add a comment |
How do I print the full result without the u1, u2, … variables using a for loop?
I tried declaring my two matrix this way:
Capture 1
Capture 2
It executes my for loop until u11 but doesn’t return the vector
Then I tried to change my multiplication for a multiply
Capture 3
It also does the for loop completely but doesn’t print the vector like u1 in the last example.
Then I tried declaring my two matrixes with an array:
Capture 4
Capture 5
It does the for completely but doesn’t print the vectors like u1
I change my multiplication for A.u[i] but it ain’t working either
Then I tried to declare the matrix with Matrix and the vector with Vector
Capture 6
Capture 7
It doesn’t work….
It’s always the first vector u1 that prints correctly and the others aren’t doing the multiplication
matrices maple
asked Dec 1 '18 at 19:53
Émile Bernard
33
How do I print the full result without the u1, u2, … variables using a for loop?
I tried declaring my two matrix this way:
Capture 1
Capture 2
It executes my for loop until u11 but doesn’t return the vector
Then I tried to change my multiplication for a multiply
Capture 3
It also does the for loop completely but doesn’t print the vector like u1 in the last example.
Then I tried declaring my two matrixes with an array:
Capture 4
Capture 5
It does the for completely but doesn’t print the vectors like u1
I change my multiplication for A.u[i] but it ain’t working either
Then I tried to declare the matrix with Matrix and the vector with Vector
Capture 6
Capture 7
It doesn’t work….
It’s always the first vector u1 that prints correctly and the others aren’t doing the multiplication
matrices maple
matrices maple
asked Dec 1 '18 at 19:53
Émile Bernard
33
asked Dec 1 '18 at 19:53
Émile Bernard
33
asked Dec 1 '18 at 19:53
Émile Bernard
33
asked Dec 1 '18 at 19:53
Émile Bernard
33
asked Dec 1 '18 at 19:53
Émile Bernard
33
33
add a comment |
add a comment |
1 Answer
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active
oldest
votes
I believe that your problem is that you are not using the correct syntax for assigning a result to a name.
Inside you loops, you have statements like this,
u[i+1] = A.u[i];
Such a statement constructs an equation, and does nothing else with it. Nothing is being assigned here.
What you seem to have expected was actual assignment that a statement like this would accomplish,
u[i+1] := A.u[i];
answered Dec 2 '18 at 5:30
acer
3,615199
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I believe that your problem is that you are not using the correct syntax for assigning a result to a name.
Inside you loops, you have statements like this,
u[i+1] = A.u[i];
Such a statement constructs an equation, and does nothing else with it. Nothing is being assigned here.
What you seem to have expected was actual assignment that a statement like this would accomplish,
u[i+1] := A.u[i];
answered Dec 2 '18 at 5:30
acer
3,615199
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
add a comment |
I believe that your problem is that you are not using the correct syntax for assigning a result to a name.
Inside you loops, you have statements like this,
u[i+1] = A.u[i];
Such a statement constructs an equation, and does nothing else with it. Nothing is being assigned here.
What you seem to have expected was actual assignment that a statement like this would accomplish,
u[i+1] := A.u[i];
answered Dec 2 '18 at 5:30
acer
3,615199
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
add a comment |
I believe that your problem is that you are not using the correct syntax for assigning a result to a name.
Inside you loops, you have statements like this,
u[i+1] = A.u[i];
Such a statement constructs an equation, and does nothing else with it. Nothing is being assigned here.
What you seem to have expected was actual assignment that a statement like this would accomplish,
u[i+1] := A.u[i];
answered Dec 2 '18 at 5:30
acer
3,615199
I believe that your problem is that you are not using the correct syntax for assigning a result to a name.
Inside you loops, you have statements like this,
u[i+1] = A.u[i];
Such a statement constructs an equation, and does nothing else with it. Nothing is being assigned here.
What you seem to have expected was actual assignment that a statement like this would accomplish,
u[i+1] := A.u[i];
answered Dec 2 '18 at 5:30
acer
3,615199
answered Dec 2 '18 at 5:30
acer
3,615199
answered Dec 2 '18 at 5:30
acer
3,615199
answered Dec 2 '18 at 5:30
acer
3,615199
3,615199
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
add a comment |
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
It solved it thanks a lot @acer
– Émile Bernard
Dec 2 '18 at 5:44
add a comment |
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