Return Yahoo! weather API data in Celsius, using YQL
I'm trying to get Yahoo! weather API with temperatures in Celsius.
I've added &u=c
in the request, but it's still returning data in Fahrenheit.
This is the URL i'm using:
http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c
And the response:
{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"n<img src="http://l.yimg.com/a/i/us/we/52/30.gif"/><br />n<b>Current Conditions:</b><br />nPartly Cloudy, 64 F<BR />n<BR /><b>Forecast:</b><BR />nMon - Partly Cloudy. High: 64 Low: 55<br />nTue - Cloudy. High: 66 Low: 56<br />nWed - Mostly Sunny. High: 68 Low: 58<br />nThu - Sunny. High: 70 Low: 60<br />nFri - Scattered Showers. High: 65 Low: 57<br />n<br />n<a href="http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/>n(provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/>n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`
any ideas ?
json api yahoo
add a comment |
I'm trying to get Yahoo! weather API with temperatures in Celsius.
I've added &u=c
in the request, but it's still returning data in Fahrenheit.
This is the URL i'm using:
http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c
And the response:
{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"n<img src="http://l.yimg.com/a/i/us/we/52/30.gif"/><br />n<b>Current Conditions:</b><br />nPartly Cloudy, 64 F<BR />n<BR /><b>Forecast:</b><BR />nMon - Partly Cloudy. High: 64 Low: 55<br />nTue - Cloudy. High: 66 Low: 56<br />nWed - Mostly Sunny. High: 68 Low: 58<br />nThu - Sunny. High: 70 Low: 60<br />nFri - Scattered Showers. High: 65 Low: 57<br />n<br />n<a href="http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/>n(provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/>n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`
any ideas ?
json api yahoo
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00
add a comment |
I'm trying to get Yahoo! weather API with temperatures in Celsius.
I've added &u=c
in the request, but it's still returning data in Fahrenheit.
This is the URL i'm using:
http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c
And the response:
{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"n<img src="http://l.yimg.com/a/i/us/we/52/30.gif"/><br />n<b>Current Conditions:</b><br />nPartly Cloudy, 64 F<BR />n<BR /><b>Forecast:</b><BR />nMon - Partly Cloudy. High: 64 Low: 55<br />nTue - Cloudy. High: 66 Low: 56<br />nWed - Mostly Sunny. High: 68 Low: 58<br />nThu - Sunny. High: 70 Low: 60<br />nFri - Scattered Showers. High: 65 Low: 57<br />n<br />n<a href="http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/>n(provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/>n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`
any ideas ?
json api yahoo
I'm trying to get Yahoo! weather API with temperatures in Celsius.
I've added &u=c
in the request, but it's still returning data in Fahrenheit.
This is the URL i'm using:
http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c
And the response:
{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"n<img src="http://l.yimg.com/a/i/us/we/52/30.gif"/><br />n<b>Current Conditions:</b><br />nPartly Cloudy, 64 F<BR />n<BR /><b>Forecast:</b><BR />nMon - Partly Cloudy. High: 64 Low: 55<br />nTue - Cloudy. High: 66 Low: 56<br />nWed - Mostly Sunny. High: 68 Low: 58<br />nThu - Sunny. High: 70 Low: 60<br />nFri - Scattered Showers. High: 65 Low: 57<br />n<br />n<a href="http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/>n(provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/>n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`
any ideas ?
json api yahoo
json api yahoo
edited Oct 16 '16 at 13:09
Bacco
609818
609818
asked Jan 13 '14 at 13:10
Jack
9,92972055
9,92972055
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00
add a comment |
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00
add a comment |
5 Answers
5
active
oldest
votes
Better late than never...
var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";
It's easier to read if you break it up. You we're pretty close, just needed the u=c as part of the query, not at the end of the url.
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for meu="c"
woked, notu='c'
– eadmaster
Aug 28 at 11:39
add a comment |
I used the yql
select item from weather.forecast where woeid=22724447 and u='c'
and it worked fine with the results in Celsius. I changed the "LEXX0003" for the real WOEID of that zone and it seems to have worked.
add a comment |
Whenever I had to call a temperature that I wanted in Celsius I just used a simple conversion function:
function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}
Then again, I wanted to toggle between Fahrenheit and Celsius. Just calling the Celsius JSON element from Yahoo is probably better if all you want to use is Celsius.
add a comment |
You can try this:
YQL Query:
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"
EndPoint:
https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys
This work when I try just now
add a comment |
just do this,be sure it will work
add this -->{ and u="c" } at the end of the YQL Query
for example:
YQL Query
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Better late than never...
var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";
It's easier to read if you break it up. You we're pretty close, just needed the u=c as part of the query, not at the end of the url.
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for meu="c"
woked, notu='c'
– eadmaster
Aug 28 at 11:39
add a comment |
Better late than never...
var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";
It's easier to read if you break it up. You we're pretty close, just needed the u=c as part of the query, not at the end of the url.
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for meu="c"
woked, notu='c'
– eadmaster
Aug 28 at 11:39
add a comment |
Better late than never...
var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";
It's easier to read if you break it up. You we're pretty close, just needed the u=c as part of the query, not at the end of the url.
Better late than never...
var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";
It's easier to read if you break it up. You we're pretty close, just needed the u=c as part of the query, not at the end of the url.
answered Jan 21 '14 at 22:09
DanV
1,39811429
1,39811429
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for meu="c"
woked, notu='c'
– eadmaster
Aug 28 at 11:39
add a comment |
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for meu="c"
woked, notu='c'
– eadmaster
Aug 28 at 11:39
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
what if I already have an and appended? <and gflags = "R">
– nr5
May 29 '15 at 9:27
2
2
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
u='c' not working for me...it steel give me result in F
– H Raval
Mar 25 '16 at 11:56
it works! thanks
– nicmare
Apr 5 '17 at 8:05
it works! thanks
– nicmare
Apr 5 '17 at 8:05
for me
u="c"
woked, not u='c'
– eadmaster
Aug 28 at 11:39
for me
u="c"
woked, not u='c'
– eadmaster
Aug 28 at 11:39
add a comment |
I used the yql
select item from weather.forecast where woeid=22724447 and u='c'
and it worked fine with the results in Celsius. I changed the "LEXX0003" for the real WOEID of that zone and it seems to have worked.
add a comment |
I used the yql
select item from weather.forecast where woeid=22724447 and u='c'
and it worked fine with the results in Celsius. I changed the "LEXX0003" for the real WOEID of that zone and it seems to have worked.
add a comment |
I used the yql
select item from weather.forecast where woeid=22724447 and u='c'
and it worked fine with the results in Celsius. I changed the "LEXX0003" for the real WOEID of that zone and it seems to have worked.
I used the yql
select item from weather.forecast where woeid=22724447 and u='c'
and it worked fine with the results in Celsius. I changed the "LEXX0003" for the real WOEID of that zone and it seems to have worked.
answered Mar 29 '16 at 1:16
Aris
13818
13818
add a comment |
add a comment |
Whenever I had to call a temperature that I wanted in Celsius I just used a simple conversion function:
function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}
Then again, I wanted to toggle between Fahrenheit and Celsius. Just calling the Celsius JSON element from Yahoo is probably better if all you want to use is Celsius.
add a comment |
Whenever I had to call a temperature that I wanted in Celsius I just used a simple conversion function:
function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}
Then again, I wanted to toggle between Fahrenheit and Celsius. Just calling the Celsius JSON element from Yahoo is probably better if all you want to use is Celsius.
add a comment |
Whenever I had to call a temperature that I wanted in Celsius I just used a simple conversion function:
function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}
Then again, I wanted to toggle between Fahrenheit and Celsius. Just calling the Celsius JSON element from Yahoo is probably better if all you want to use is Celsius.
Whenever I had to call a temperature that I wanted in Celsius I just used a simple conversion function:
function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}
Then again, I wanted to toggle between Fahrenheit and Celsius. Just calling the Celsius JSON element from Yahoo is probably better if all you want to use is Celsius.
answered Dec 18 '15 at 15:21
Michael Howard
112
112
add a comment |
add a comment |
You can try this:
YQL Query:
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"
EndPoint:
https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys
This work when I try just now
add a comment |
You can try this:
YQL Query:
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"
EndPoint:
https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys
This work when I try just now
add a comment |
You can try this:
YQL Query:
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"
EndPoint:
https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys
This work when I try just now
You can try this:
YQL Query:
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"
EndPoint:
https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys
This work when I try just now
answered Aug 30 '17 at 8:01
Zhao Weihao
1111
1111
add a comment |
add a comment |
just do this,be sure it will work
add this -->{ and u="c" } at the end of the YQL Query
for example:
YQL Query
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"
add a comment |
just do this,be sure it will work
add this -->{ and u="c" } at the end of the YQL Query
for example:
YQL Query
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"
add a comment |
just do this,be sure it will work
add this -->{ and u="c" } at the end of the YQL Query
for example:
YQL Query
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"
just do this,be sure it will work
add this -->{ and u="c" } at the end of the YQL Query
for example:
YQL Query
select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"
edited Nov 20 at 17:40
pushkin
3,914112651
3,914112651
answered Nov 20 at 16:45
user10002267
1
1
add a comment |
add a comment |
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Did you ever solve this?
– DanV
Jan 21 '14 at 22:00