Explain about downstream and upstream in rxJava
I don't really understand the meaning of downstream and upstream in Rxjava.
What does that mean? Is it equivalent to subscribeOn and observableOn?
java
android edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
add a comment |
I don't really understand the meaning of downstream and upstream in Rxjava.
What does that mean? Is it equivalent to subscribeOn and observableOn?
java
android edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
add a comment |
I don't really understand the meaning of downstream and upstream in Rxjava.
What does that mean? Is it equivalent to subscribeOn and observableOn?
java
android edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
I don't really understand the meaning of downstream and upstream in Rxjava.
What does that mean? Is it equivalent to subscribeOn and observableOn?
java
android java
android edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
edited Nov 23 '18 at 7:21
Rene Knop
1,3433722
1,3433722
asked Nov 23 '18 at 6:49
miho39miho39
171520
asked Nov 23 '18 at 6:49
miho39miho39
171520
asked Nov 23 '18 at 6:49
miho39miho39
171520
171520
add a comment |
add a comment |
1 Answer
1
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oldest
votes
We can divide stream by seeing its position based on an operator.
upstream downstream
source <--------- operator -----------> consumer/further operators
So from top to the operator, we call it upstream.
From operator to the bottom, we call it downstream.
It's not equivalent to subscribeOn and observeOn. subscribeOn and observeOn are only operators. However, we can distinguish the behaviour of that two operators by using downstream and upstream concept.
subscribeOn is affecting its upstream and downstream. For example, subcsribeOn on this code
just("Some String")
.map(str -> str.length())
.subsribeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
will make all the stream (up and down) run on computation thread.
On the other hand, observeOn only affecting downstream. observeOn on this code
just("Some String")
.map(str -> str.length())
.observeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
only make the downstream run on computation thread.
I hope the explanation will help.
answered Dec 25 '18 at 10:57
KhardaKharda
560516
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
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oldest
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oldest
votes
We can divide stream by seeing its position based on an operator.
upstream downstream
source <--------- operator -----------> consumer/further operators
So from top to the operator, we call it upstream.
From operator to the bottom, we call it downstream.
It's not equivalent to subscribeOn and observeOn. subscribeOn and observeOn are only operators. However, we can distinguish the behaviour of that two operators by using downstream and upstream concept.
subscribeOn is affecting its upstream and downstream. For example, subcsribeOn on this code
just("Some String")
.map(str -> str.length())
.subsribeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
will make all the stream (up and down) run on computation thread.
On the other hand, observeOn only affecting downstream. observeOn on this code
just("Some String")
.map(str -> str.length())
.observeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
only make the downstream run on computation thread.
I hope the explanation will help.
answered Dec 25 '18 at 10:57
KhardaKharda
560516
add a comment |
We can divide stream by seeing its position based on an operator.
upstream downstream
source <--------- operator -----------> consumer/further operators
So from top to the operator, we call it upstream.
From operator to the bottom, we call it downstream.
It's not equivalent to subscribeOn and observeOn. subscribeOn and observeOn are only operators. However, we can distinguish the behaviour of that two operators by using downstream and upstream concept.
subscribeOn is affecting its upstream and downstream. For example, subcsribeOn on this code
just("Some String")
.map(str -> str.length())
.subsribeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
will make all the stream (up and down) run on computation thread.
On the other hand, observeOn only affecting downstream. observeOn on this code
just("Some String")
.map(str -> str.length())
.observeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
only make the downstream run on computation thread.
I hope the explanation will help.
answered Dec 25 '18 at 10:57
KhardaKharda
560516
add a comment |
We can divide stream by seeing its position based on an operator.
upstream downstream
source <--------- operator -----------> consumer/further operators
So from top to the operator, we call it upstream.
From operator to the bottom, we call it downstream.
It's not equivalent to subscribeOn and observeOn. subscribeOn and observeOn are only operators. However, we can distinguish the behaviour of that two operators by using downstream and upstream concept.
subscribeOn is affecting its upstream and downstream. For example, subcsribeOn on this code
just("Some String")
.map(str -> str.length())
.subsribeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
will make all the stream (up and down) run on computation thread.
On the other hand, observeOn only affecting downstream. observeOn on this code
just("Some String")
.map(str -> str.length())
.observeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
only make the downstream run on computation thread.
I hope the explanation will help.
answered Dec 25 '18 at 10:57
KhardaKharda
560516
We can divide stream by seeing its position based on an operator.
upstream downstream
source <--------- operator -----------> consumer/further operators
So from top to the operator, we call it upstream.
From operator to the bottom, we call it downstream.
It's not equivalent to subscribeOn and observeOn. subscribeOn and observeOn are only operators. However, we can distinguish the behaviour of that two operators by using downstream and upstream concept.
subscribeOn is affecting its upstream and downstream. For example, subcsribeOn on this code
just("Some String")
.map(str -> str.length())
.subsribeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
will make all the stream (up and down) run on computation thread.
On the other hand, observeOn only affecting downstream. observeOn on this code
just("Some String")
.map(str -> str.length())
.observeOn(Schedulers.computation()) // change thread
.map(length -> 2 * length)
.subscribe(number -> Log.d("", "Number " + number))
only make the downstream run on computation thread.
I hope the explanation will help.
answered Dec 25 '18 at 10:57
KhardaKharda
560516
answered Dec 25 '18 at 10:57
KhardaKharda
560516
answered Dec 25 '18 at 10:57
KhardaKharda
560516
answered Dec 25 '18 at 10:57
KhardaKharda
560516
560516
add a comment |
add a comment |
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